Problem 91
Question
A gas bubble with a volume of \(1.0 \mathrm{~mm}^{3}\) originates at the bottom of a lake where the pressure is \(3.0\) atm. Calculate its volume when the bubble reaches the surface of the lake where the pressure is 695 torr, assuming that the temperature doesn't change.
Step-by-Step Solution
Verified Answer
The volume of the gas bubble when it reaches the surface of the lake is \(3.28 \mathrm{~mm}^{3}\).
1Step 1: List the given values
Initial Volume (Vi) = 1.0 mm³
Initial Pressure (Pi) = 3.0 atm
Final Pressure (Pf) = 695 torr
2Step 2: Convert units
We need to convert the pressures to the same unit. Let's convert atm to torr:
1 atm = 760 torr
3.0 atm × (760 torr/1 atm) = 2280 torr
Initial Pressure (Pi) = 2280 torr
Additionally, convert the volume to a larger unit like liters:
1.0 mm³ × (1 cm³ / 1000 mm³) × (1 L / 1000 cm³) = 1.0 × 10⁻⁶ L
Initial Volume (Vi) = \(1.0 \times 10^{-6}\) L
3Step 3: Apply Boyle's Law
Boyle's Law states that for an ideal gas at constant temperature, the product of the initial pressure and volume is equal to the product of the final pressure and volume:
Pi × Vi = Pf × Vf
Now, solve for the final volume (Vf):
Vf = (Pi × Vi) / Pf
4Step 4: Calculate the final volume
Plug in the given values and solve for Vf:
Vf = (\(2280 \mathrm{~torr}\) × \(1.0 \times 10^{-6} \mathrm{~L}\)) / \(695 \mathrm{~torr}\)
Vf = \(2.28 \times 10^{-3} \mathrm{~L}\) / \(695 \mathrm{~torr}\)
Vf = \(3.28 \times 10^{-6}\) L
5Step 5: Convert the final volume to mm³
To convert the final volume back to mm³, use the following conversion:
Vf = \(3.28 \times 10^{-6}\) L × (1000 cm³ / 1 L) × (1000 mm³ / 1 cm³) = 3.28 mm³
The volume of the gas bubble when it reaches the surface of the lake is 3.28 mm³.
Key Concepts
Pressure ConversionGas LawsVolume Calculation
Pressure Conversion
One of the critical steps in gas calculations is converting pressure units. Pressure can be measured in various units such as atmospheres (atm) and torr. However, to perform accurate calculations, these units need to be consistent.
To convert pressure from atmospheres to torr or vice versa, remember that:
To convert pressure from atmospheres to torr or vice versa, remember that:
- 1 atm is equivalent to 760 torr.
- To convert from atm to torr, multiply by 760.
- To convert from torr to atm, divide by 760.
Gas Laws
Gas laws provide vital relationships between pressure, volume, and temperature of gases. One of the famous gas laws is Boyle's Law. This principle describes how the pressure of a gas tends to increase as the volume of the container decreases, provided the temperature remains constant.
Boyle's Law is mathematically expressed as:
Boyle's Law is mathematically expressed as:
- \[ P_i \times V_i = P_f \times V_f \]
- \(P_i\) = Initial pressure
- \(V_i\) = Initial volume
- \(P_f\) = Final pressure
- \(V_f\) = Final volume
Volume Calculation
Volume calculation is another critical aspect of gas problems. Sometimes, you need to convert between various volume units, such as milliliters, liters, or cubic millimeters.
In the original problem, the initial volume of the gas bubble is given as 1.0 mm³. Converting small units like mm³ into more standard or bigger units like liters makes handling numbers in calculations easier:
In the original problem, the initial volume of the gas bubble is given as 1.0 mm³. Converting small units like mm³ into more standard or bigger units like liters makes handling numbers in calculations easier:
- A cube with 10 mm on each side has a volume of 1 cm³.
- 1000 cm³ equals 1 liter.
- Thus, 1 mm³ is equivalent to \(1 \times 10^{-6}\) liters.
Other exercises in this chapter
Problem 88
Calculate the pressure that \(\mathrm{CCl}_{4}\) will exert at \(40^{\circ} \mathrm{C}\) if \(1.00 \mathrm{~mol}\) occupies \(28.0 \mathrm{~L}\), assuming that
View solution Problem 89
Suppose the mercury used to make a barometer has a few small droplets of water trapped in it that rise to the top of the mercury in the tube. Will the barometer
View solution Problem 92
A 15.0-L tank is filled with helium gas at a pressure of \(1.00 \times 10^{2}\). How many balloons (each \(2.00 \mathrm{~L}\) ) can be inflated to a pressure of
View solution Problem 93
To minimize the rate of evaporation of the tungsten filament, \(1.4 \times 10^{-5}\) mol of argon is placed in a \(600-\mathrm{cm}^{3}\) lightbulb. What is the
View solution