Problem 90
Question
Which reaction product is formed from benzaldehyde and methyl amine? (a) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NH}_{2}\) (b) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}=\mathrm{NCH}_{3}\) (c) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}_{2} \mathrm{NH}_{2}\) (d) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CONH}_{2}\)
Step-by-Step Solution
Verified Answer
The product is 83C_6H_5CH=NCH_3 (option b).
1Step 1: Understanding the Reactants
Benzaldehyde (83C_6H_5CHO) is an aromatic aldehyde, while methyl amine (83CH_3NH_2) is a primary amine. When an aldehyde reacts with an amine, an imine or a similar compound is typically formed.
2Step 2: Recognize the Reaction Type
In a reaction between an aldehyde and a primary amine, a nucleophilic addition typically occurs, resulting in the formation of an imine. This process involves the replacement of the carbon-oxygen double bond with a carbon-nitrogen double bond.
3Step 3: Form the Imine Product
In this reaction, methyl amine reacts with benzaldehyde to form an imine by eliminating a water molecule from the newly formed compound. The expected imine structure would be 83C_6H_5CH=NCH_3.
4Step 4: Identify the Correct Option
From the provided options, 83C_6H_5CH=NCH_3 matches the predicted imine structure formed from the reaction of benzaldehyde and methyl amine.
Key Concepts
Aldehyde and amine reactionsImine formationNucleophilic addition reactions
Aldehyde and amine reactions
When aldehydes interact with amines, intriguing transformations occur. Both benzaldehyde and primary amines, like methyl amine, are essential players in creating versatile organic compounds. The key starting materials for aldehyde and amine reactions are:
- Aldehydes: Compounds with a carbonyl group, where the carbon atom is bonded to a hydrogen atom and is frequently reactive due to the electronegativity of oxygen.
- Amines: Organic derivatives of ammonia, categorized by their structure as primary (one alkyl or aryl group), secondary, or tertiary.
Imine formation
The formation of imines is an exciting aspect of aldehyde and amine chemistry. Imine formation involves a multi-step mechanism carried out under mild conditions. This transformation begins with:
- Nucleophilic Attack: The lone pair of electrons on the nitrogen atom in the amine attacks the electrophilic carbon atom in the aldehyde's carbonyl group, forming a nucleophilic addition product.
- Proton Transfer: A proton is transferred, facilitating the departure of a water molecule, crucial for finalizing the imine structure.
Nucleophilic addition reactions
Nucleophilic addition reactions are foundational in organic chemistry, where nucleophiles and electrophiles interact to form more complex structures. Benzaldehyde and amine reactions are classic examples showcasing this versatile chemistry.
The mechanism includes:
The mechanism includes:
- Electrophilic Site: The carbon atom in the carbonyl group of benzaldehyde serves as the electrophilic center.
- Nucleophile: Methyl amine acts as the nucleophile, utilizing its lone pair of electrons to attack the electrophilic carbon.
- Intermediate Formation: This attack forms a tetrahedral intermediate, which quickly rearranges as a result of a subsequent proton transfer.
Other exercises in this chapter
Problem 88
When propanamide reacts with \(\mathrm{Br}_{2}\) and \(\mathrm{NaOH}\) then which of the following compounds is formed? (a) propyl alcohol (b) ethyl alcohol (c)
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View solution Problem 94
Identify (a) in the following sequence of reactions. (a) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{COCl}\) (b) \(\mathrm{CH}_{3} \mathrm{CH}_{2}
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