Problem 90
Question
Use fundamental identities to find the values of the trigonometric functions for the given conditions. $$\csc \theta=5 \text { and } \cot \theta<0$$
Step-by-Step Solution
Verified Answer
Find \( \sin \theta = \frac{1}{5} \), \( \cos \theta = -\frac{\sqrt{24}}{5} \), and other trigonometrics.
1Step 1: Identify Given Information
We are given that \( \csc \theta = 5 \), which means \( \theta = \frac{1}{\sin \theta} \). Additionally, \( \cot \theta < 0 \) indicates that \( \theta \) is in the second or fourth quadrant since the cotangent is negative in those quadrants.
2Step 2: Find Sin θ Using Cosecant Definition
Since \( \csc \theta = 5 \), it follows from the definition \( \csc \theta = \frac{1}{\sin \theta} \) that \( \sin \theta = \frac{1}{5} \).
3Step 3: Determine the Appropriate Quadrant
Using \( \cot \theta < 0 \), we know that since \( \cot \theta = \frac{\cos \theta}{\sin \theta} \), the cosine must be negative, implying \( \theta \) is in the second quadrant where \( \sin \) is positive and \( \cos \) is negative.
4Step 4: Use Pythagorean Identity to Find Cos θ
Use the identity \( \sin^2 \theta + \cos^2 \theta = 1 \). Substituting \( \sin \theta = \frac{1}{5} \), we get \( \left(\frac{1}{5}\right)^2 + \cos^2 \theta = 1 \). Simplifying gives \( \cos^2 \theta = 1 - \frac{1}{25} = \frac{24}{25} \), so \( \cos \theta = -\sqrt{\frac{24}{25}} = -\frac{\sqrt{24}}{5} \) because \( \cos \theta \) is negative in quadrant II.
5Step 5: Calculate Remaining Trigonometric Functions Using Found Values
Now calculate the other trigonometric functions:- \( \tan \theta = \frac{\sin \theta}{\cos \theta} = \frac{\frac{1}{5}}{-\frac{\sqrt{24}}{5}} = -\frac{1}{\sqrt{24}} \)- \( \sec \theta = \frac{1}{\cos \theta} = -\frac{5}{\sqrt{24}} \) - Given \( \csc \theta = 5 \).- \( \cot \theta = \frac{1}{\tan \theta} = \sqrt{24} \)
Key Concepts
CosecantQuadrant AnalysisPythagorean Identity
Cosecant
Cosecant, abbreviated as \( \csc \), is a trigonometric function that is the reciprocal of the sine function. If \( \sin \theta \) represents the sine of angle \( \theta \), then \( \csc \theta = \frac{1}{\sin \theta} \). This means that to find the cosecant of an angle, you simply take the inverse of its sine value.
This concept is particularly useful in situations where you already have the value of \( \csc \theta \) and need to find \( \sin \theta \). For instance, if you know \( \csc \theta = 5 \), you can easily find that \( \sin \theta = \frac{1}{5} \).
This concept is particularly useful in situations where you already have the value of \( \csc \theta \) and need to find \( \sin \theta \). For instance, if you know \( \csc \theta = 5 \), you can easily find that \( \sin \theta = \frac{1}{5} \).
- Allows conversion between sine and cosecant functions using a reciprocal relationship.
- Helps in solving trigonometric equations where \( \sin \theta \) is needed but only \( \csc \theta \) is known.
Quadrant Analysis
Quadrant analysis is essential in trigonometry to determine the sign and behavior of trigonometric functions depending on the angle's position. The coordinate plane is divided into four quadrants, and each quadrant has implications for the sign of sine, cosine, tangent, and their reciprocals.
To determine which quadrant an angle falls into, it's crucial to use any given conditions about the trigonometric values. In our scenario, \( \cot \theta < 0 \), which means that the angle \( \theta \) is in a quadrant where the cosine and sine have opposite signs.
Quadrant analysis not only allows us to find out where an angle lies but also facilitates the prediction of the positivity or negativity of other trigonometric functions.
To determine which quadrant an angle falls into, it's crucial to use any given conditions about the trigonometric values. In our scenario, \( \cot \theta < 0 \), which means that the angle \( \theta \) is in a quadrant where the cosine and sine have opposite signs.
- In the second quadrant, \( \sin \theta \) is positive and \( \cos \theta \) is negative.
- In the fourth quadrant, \( \sin \theta \) is negative and \( \cos \theta \) is positive.
Quadrant analysis not only allows us to find out where an angle lies but also facilitates the prediction of the positivity or negativity of other trigonometric functions.
Pythagorean Identity
The Pythagorean identity is one of the fundamental relationships in trigonometry and is used to connect the sine and cosine functions. The most well-known form is \( \sin^2 \theta + \cos^2 \theta = 1 \).
This identity is particularly useful when one trigonometric function is known, and you need to determine another. For example, when you know \( \sin \theta \) (from the cosecant \( \csc \theta = 5 \), we have \( \sin \theta = \frac{1}{5} \)), you can find \( \cos \theta \) by substituting into the identity:
This identity allows us to solve for unknowns across numerous trigonometric problems, providing a strong backbone for understanding angles and their corresponding function values.
This identity is particularly useful when one trigonometric function is known, and you need to determine another. For example, when you know \( \sin \theta \) (from the cosecant \( \csc \theta = 5 \), we have \( \sin \theta = \frac{1}{5} \)), you can find \( \cos \theta \) by substituting into the identity:
- \( \sin^2 \theta + \cos^2 \theta = 1 \)
- \( \left(\frac{1}{5}\right)^2 + \cos^2 \theta = 1 \)
- \( \cos^2 \theta = 1 - \frac{1}{25} = \frac{24}{25} \)
This identity allows us to solve for unknowns across numerous trigonometric problems, providing a strong backbone for understanding angles and their corresponding function values.
Other exercises in this chapter
Problem 88
Use fundamental identities to find the values of the trigonometric functions for the given conditions. $$\cos \theta=\frac{1}{2} \text { and } \sin \theta
View solution Problem 89
Use fundamental identities to find the values of the trigonometric functions for the given conditions. $$\cos \theta=-\frac{1}{3} \text { and } \sin \theta
View solution Problem 91
Use fundamental identities to find the values of the trigonometric functions for the given conditions. $$\sec \theta=-4 \text { and } \csc \theta>0$$
View solution Problem 92
Use fundamental identities to find the values of the trigonometric functions for the given conditions. $$\sin \theta=\frac{2}{5} \text { and } \cos \theta
View solution