Problem 90
Question
This set of exercises will draw on the ideas presented in this section and your general math background. Why must we have \(a \neq 0\) in the definition of a quadratic function?
Step-by-Step Solution
Verified Answer
We must have \(a \neq 0\) in the definition of a quadratic function to ensure that the function is not linear and that it represents a parabolic shape. If \(a = 0\), the function would become a linear function, not a quadratic function.
1Step 1: Understand the Structure of a Quadratic Function
A quadratic function is defined by the equation \(f(x) = ax^2 + bx + c\), where \(a\), \(b\), and \(c\) are constants, and \(a \neq 0\). If \(a = 0\), then the equation simplifies to \(f(x) = bx + c\), which is a linear equation, not a quadratic.
2Step 2: Understand the Importance of Term \(ax^2\)
The term \(ax^2\) determines the curvature of the graph of the function. Its coefficient \(a\) influences whether the graph opens upward \(a > 0\) or downward \(a < 0\). If \(a = 0\), the graph would be a straight line, which is not characteristic of a quadratic function.
3Step 3: Conclusion
We must have \(a \neq 0\) in the definition of a quadratic function in order for the equation to represent a parabola. If \(a = 0\), the equation would be for a linear function, not a quadratic function. Therefore, \(a \neq 0\) is a necessary condition for a quadratic function.
Key Concepts
Quadratic EquationParabolaLinear Function
Quadratic Equation
A quadratic equation is a type of polynomial equation that is defined by its degree, which is the highest power of the variable involved. In the case of quadratic equations, the degree is 2.
The general form of a quadratic equation is expressed as:
The general form of a quadratic equation is expressed as:
- \( ax^2 + bx + c = 0 \)
- If \(a = 0\), the equation reduces to a linear equation, \(bx + c = 0\).
Parabola
In the study of quadratic functions, the graph of any quadratic equation results in a curve known as a parabola. The parabolic shape is a key characteristic of quadratic equations.
Parabolas can open upward or downward based on the sign of the leading coefficient, \(a\), in the quadratic function:
Parabolas can open upward or downward based on the sign of the leading coefficient, \(a\), in the quadratic function:
- If \(a > 0\), the parabola opens upward, resembling a U-shape.
- If \(a < 0\), it opens downward, forming an upside-down U.
Linear Function
A linear function is the simplest form of a polynomial, characterized by its degree of 1. It takes the form:
The absence of the \(x^2\) term is crucial; when you have a quadratic equation \(ax^2 + bx + c\) but \(a = 0\), it simplifies to a linear equation. Consequently, the function no longer exhibits the properties of a parabola.
Linear functions have constant slopes that determine the steepness and direction of the line:
- \(f(x) = bx + c\)
The absence of the \(x^2\) term is crucial; when you have a quadratic equation \(ax^2 + bx + c\) but \(a = 0\), it simplifies to a linear equation. Consequently, the function no longer exhibits the properties of a parabola.
Linear functions have constant slopes that determine the steepness and direction of the line:
- The slope is \(b\), which tells you how much \(y\) increases or decreases as \(x\) increases.
Other exercises in this chapter
Problem 89
In Exercises \(87-96,\) find two functions \(f\) and \(g\) such that \(h(x)=(f \circ g)(x)=f(g(x)) .\) Answers may vary. $$h(x)=\sqrt[3]{4 x^{2}-1}$$
View solution Problem 89
Consider a parabola that opens upward and has vertex (0,4). (a) Why does the quadratic function associated with such a parabola have no real zeros? (b) Show tha
View solution Problem 90
In Exercises \(87-96,\) find two functions \(f\) and \(g\) such that \(h(x)=(f \circ g)(x)=f(g(x)) .\) Answers may vary. $$h(x)=\sqrt[5]{-x^{3}+8}$$
View solution Problem 91
The shape of the Gateway Arch in St. Louis, Missouri, can be approximated by a parabola. (The actual shape will be discussed in an exercise in the chapter on ex
View solution