Problem 90
Question
The sewage outlet of a house constructed on a slope is \(6.59 \mathrm{~m}\) below street level. If the sewer is \(2.16 \mathrm{~m}\) below street level, find the minimum pressure difference that must be created by the sewage pump to transfer waste of average density \(1000.00 \mathrm{~kg} / \mathrm{m}^{3}\) from outlet to sewer.
Step-by-Step Solution
Verified Answer
The minimum pressure difference needed is approximately 43500 Pa.
1Step 1: Identify the Given Information
We know that the outlet is located 6.59 meters below street level, and the sewer is 2.16 meters below street level. The density of the waste is given as 1000 kg/m³. We need to find the pressure difference needed to pump the waste.
2Step 2: Calculate the Height Difference
Determine the height difference between the outlet and the sewer. Since the outlet is at 6.59 m below street level and the sewer is at 2.16 m below street level, the height difference is:\[ \Delta h = 6.59 - 2.16 = 4.43 \text{ meters} \]
3Step 3: Use the Hydrostatic Pressure Formula
The pressure difference required to move the waste vertically is due to the height difference, which can be calculated using the hydrostatic pressure formula:\[ \Delta P = \rho \cdot g \cdot \Delta h \]where \( \rho = 1000 \ kg/m^3 \) (density of the waste) and \( g = 9.81 \ m/s^2 \) (acceleration due to gravity).
4Step 4: Calculate Pressure Difference
Substitute the values into the hydrostatic pressure formula:\[ \Delta P = 1000 \times 9.81 \times 4.43 \]Calculate to find:\[ \Delta P = 43542.3 \ Pa \]
5Step 5: Round Off the Result
Generally, results are rounded to reflect the precision of the original data. Since our input data has three significant figures, we should round to:\[ \Delta P \approx 43500 \ Pa \]
Key Concepts
Pressure DifferenceDensityHeight DifferenceFluid Mechanics
Pressure Difference
Understanding the pressure difference is crucial when dealing with fluids, such as sewage, in hydrostatics. Pressure difference refers to the variance in pressure between two points in a fluid. This difference is a driving force that can cause fluid flow from one location to another. In cases like the sewage outlet, the pressure difference helps in moving waste from a lower elevation to a higher one.
The pressure difference can be determined using the hydrostatic pressure formula:
The pressure difference can be determined using the hydrostatic pressure formula:
- \( \Delta P = \rho \cdot g \cdot \Delta h \)
- Here, \(\rho\) is the fluid's density, \(g\) is the gravitational acceleration, and \(\Delta h\) is the height difference.
Density
Density plays a significant role in hydrostatics, especially when calculating pressure differences. It is defined as the mass of a substance per unit volume. In mathematical terms, density \(\rho\) is expressed as:
Understanding density helps us predict how substances will behave under gravitational forces, particularly in closed systems like pipes.
- \( \rho = \frac{m}{V} \)
- Where \(m\) is the mass and \(V\) is the volume.
Understanding density helps us predict how substances will behave under gravitational forces, particularly in closed systems like pipes.
Height Difference
Height difference is another critical aspect in understanding fluid movement in hydrostatic scenarios. It refers to the vertical distance between two points in a fluid system. In the sewage pumping problem, the height difference \(\Delta h\) between the sewage outlet and the sewer was calculated as 4.43 meters.
This measurement is vital because it influences the pressure needed to move fluid. With a larger height difference, more pressure is required. Calculating this difference accurately ensures that the correct amount of force is applied for effective fluid transport. The principle behind this is due to gravitational pull, which necessitates higher pressure for ascending fluids over greater heights.
This measurement is vital because it influences the pressure needed to move fluid. With a larger height difference, more pressure is required. Calculating this difference accurately ensures that the correct amount of force is applied for effective fluid transport. The principle behind this is due to gravitational pull, which necessitates higher pressure for ascending fluids over greater heights.
Fluid Mechanics
Fluid mechanics is the broader scientific discipline that covers the behavior of fluids, both liquids and gases, and the forces acting on them. This field combines various principles, such as pressure differences, density, and height differences, to understand and solve real-world problems.
In the given exercise, fluid mechanics principles help determine the pressure difference needed for the upward movement of sewage against gravity. It explains how different factors, including waste density, gravitational forces, and vertical distances, interact to necessitate a specific pressure level. The practical application of fluid mechanics ensures efficient and safe design and operation of systems like sewage pumps.
For students and engineers, mastering fluid mechanics is essential to designing systems that efficiently manage fluid flow under various conditions.
In the given exercise, fluid mechanics principles help determine the pressure difference needed for the upward movement of sewage against gravity. It explains how different factors, including waste density, gravitational forces, and vertical distances, interact to necessitate a specific pressure level. The practical application of fluid mechanics ensures efficient and safe design and operation of systems like sewage pumps.
For students and engineers, mastering fluid mechanics is essential to designing systems that efficiently manage fluid flow under various conditions.
Other exercises in this chapter
Problem 88
A \(8.60 \mathrm{~kg}\) sphere of radius \(6.22 \mathrm{~cm}\) is at a depth of \(2.22 \mathrm{~km}\) in seawater that has an average density of \(1025 \mathrm{
View solution Problem 89
For seawater of density \(1.03 \mathrm{~g} / \mathrm{cm}^{3}\), find the weight of water on top of a submarine at a depth of \(255 \mathrm{~m}\) if the horizont
View solution Problem 87
What is the minimum area (in square meters) of the top surface of an ice slab \(0.441 \mathrm{~m}\) thick floating on fresh water that will hold up a \(938 \mat
View solution