Problem 90
Question
Solve \(P=P_{0} e^{r\left(t-t_{0}\right)}+5\) for \(t\)
Step-by-Step Solution
Verified Answer
\( t = \frac{\ln \left( \frac{P-5}{P_0} \right)}{r} + t_0 \)
1Step 1: Isolate the Exponential Term
Start by subtracting 5 from both sides to isolate the exponential term. This gives:\[ P - 5 = P_0 e^{r(t-t_0)} \]
2Step 2: Divide by Initial Condition
Divide both sides by \( P_0 \) to further isolate the exponential term:\[ \frac{P-5}{P_0} = e^{r(t-t_0)} \]
3Step 3: Take the Natural Logarithm
Apply the natural logarithm (\(\ln\)) to both sides to remove the exponential:\[ \ln \left( \frac{P-5}{P_0} \right) = r(t-t_0) \]
4Step 4: Solve for Time Variable
Finally, solve for \( t \) by dividing both sides by \( r \) and adding \( t_0 \):\[ t = \frac{\ln \left( \frac{P-5}{P_0} \right)}{r} + t_0 \]
Key Concepts
Natural LogarithmsIsolating VariablesGrowth Models
Natural Logarithms
Natural logarithms are a special type of logarithm, where the base is the constant \( e \), approximately equal to 2.71828. They are denoted as \( \ln \). When dealing with exponential equations, natural logarithms play a critical role. Why? Because they can effectively "undo" an exponentiation of the base \( e \).
This property is extremely useful in solving equations where the unknown variable is in an exponent. For instance, if you have an equation \( e^x = y \), taking the natural logarithm of both sides gives \( x = \ln(y) \). This is because \( \ln(e^x) = x \). The ability of natural logarithms to simplify such equations makes them indispensable in mathematics.
This property is extremely useful in solving equations where the unknown variable is in an exponent. For instance, if you have an equation \( e^x = y \), taking the natural logarithm of both sides gives \( x = \ln(y) \). This is because \( \ln(e^x) = x \). The ability of natural logarithms to simplify such equations makes them indispensable in mathematics.
- They help in linearizing exponential relationships.
- They are used extensively in calculus for integration and differentiation.
Isolating Variables
Isolating variables is a fundamental technique in solving equations. It involves manipulating the equation to get the variable of interest on one side by itself. This is a crucial step because it allows you to clearly understand the relationship and find the value of the variable you're looking to solve.
When dealing with exponential equations, isolating the variable often requires:
This methodical approach can apply not only to exponential equations but to any mathematical problem, serving as a universal problem-solving strategy.
When dealing with exponential equations, isolating the variable often requires:
- Subtracting constants from both sides.
- Dividing all terms by the coefficient of the variable or any multiplicative value attached to it.
This methodical approach can apply not only to exponential equations but to any mathematical problem, serving as a universal problem-solving strategy.
Growth Models
Growth models are mathematical representations used to describe how a quantity increases over time. They are often expressed through exponential functions due to their natural fit to growth phenomena, such as population growth and interest accumulation.
In the context of this exercise, an exponential growth model helps predict the behavior of the variable \( P \). Growth models typically depend on parameters like:
By learning how to solve equations related to growth models, you can gain insights into diverse fields such as finance, biology, and environmental science.
In the context of this exercise, an exponential growth model helps predict the behavior of the variable \( P \). Growth models typically depend on parameters like:
- Initial Condition (e.g., \( P_0 \) in the formula).
- Growth Rate (e.g., \( r \) in the formula).
- Time (e.g., \( t \) in the formula).
By learning how to solve equations related to growth models, you can gain insights into diverse fields such as finance, biology, and environmental science.
Other exercises in this chapter
Problem 89
Use \(f(x)\) to complete the table. $$ f(x)=4 x $$ TABLE CANNOT COPY.
View solution Problem 90
Solve each equation. Approximate answers to four decimal places when appropriate. $$\ln 5 x=8$$
View solution Problem 90
Exercises \(81-94:\) (Refer to Example \(11 .\) ) Find functions \(f\) and \(g\) so that \(h(x)=(g \circ f)(x) .\) Answers may vary. $$ h(x)=5 \sqrt{x-1} $$
View solution Problem 91
Solve each equation. Approximate answers to four decimal places when appropriate. $$5 \ln x-1=6$$
View solution