Problem 90
Question
Graph \(f(x)=x \cos x\) and its second derivative together for \(0 \leq x \leq 2 \pi\) . Comment on the behavior of the graph of \(f\) in relation to the signs and values of \(f^{\prime \prime} .\)
Step-by-Step Solution
Verified Answer
\(f(x)\) is concave up where \(f''(x) > 0\) and concave down where \(f''(x) < 0\), indicating regions of changing slopes affected by \(x\) and \(\cos x\).
1Step 1: Understand the function
To graph the function, first understand that \(f(x) = x \cos x\) is a product of a linear function and a trigonometric function. The linear part \(x\) will stretch the cosine function as \(x\) increases.
2Step 2: Find the first derivative
To find the behavior of the graph, we need the derivatives. The first derivative \(f'(x)\) can be found using the product rule: \(f'(x) = \cos x - x \sin x\).
3Step 3: Find the second derivative
The second derivative \(f''(x)\) gives us information about concavity. Use the product rule again to find \(f''(x)\):\[ f''(x) = -2 \sin x - x \cos x \]
4Step 4: Graph \(f(x)\) and \(f''(x)\)
Graph both \(f(x) = x \cos x\) and \(f''(x)\) on the same axes over the interval \(0 \leq x \leq 2\pi\). Notice where \(f(x)\) is concave up and down by observing the sign of \(f''(x)\).
5Step 5: Analyze the behavior
By examining the signs of \(f''(x) = -2 \sin x - x \cos x\), determine the intervals of concavity:- \(f''(x) > 0\) indicates the graph of \(f(x)\) is concave up.- \(f''(x) < 0\) indicates the graph of \(f(x)\) is concave down. Note periodicity and transition of inflection points.
Key Concepts
Second DerivativeProduct RuleConcavity Analysis
Second Derivative
The second derivative of a function provides valuable insights into the behavior of its graph. It is essentially the derivative of the function's first derivative. In this context, understanding the function \( f(x) = x \cos x \), we need to apply the product rule multiple times to work our way to the second derivative. Once we derive it, the resulting expression \( f''(x) = -2 \sin x - x \cos x \) tells us about the function's concavity and points where the graph may have inflection points.
- When \( f''(x) > 0 \), the function is concave up, forming the shape of a smile.
- When \( f''(x) < 0 \), the function is concave down, resembling a frown.
Product Rule
The product rule is a fundamental differentiation technique used when an expression includes a product of two functions. For a function \( f(x) = u(x)v(x) \), where \( u \) and \( v \) are each functions of \( x \), the product rule states: \[ f'(x) = u'(x)v(x) + u(x)v'(x)\]
This is highly relevant to our function \( f(x) = x \cos x \), where \( u(x) = x \) and \( v(x) = \cos x \). When we apply the product rule, we find:
This is highly relevant to our function \( f(x) = x \cos x \), where \( u(x) = x \) and \( v(x) = \cos x \). When we apply the product rule, we find:
- The derivative of \( x \) is 1.
- The derivative of \( \cos x \) is \( - \sin x \).
Concavity Analysis
Concavity analysis involves using the second derivative to determine where a function's graph curves upward or downward. For our function \( f(x) = x \cos x \), having the second derivative \( f''(x) = -2 \sin x - x \cos x \) is key to this analysis. This information can help understand the behavior across the interval \( 0 \leq x \leq 2\pi \):
- Identify intervals where \( f''(x) > 0 \) to establish where the function is concave up.
- Conversely, find where \( f''(x) < 0 \) to see where the function is concave down.
- At points where \( f''(x) = 0 \), combined with a change in concavity, determine the locations of inflection points.
Other exercises in this chapter
Problem 88
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