Problem 90
Question
Find the product for the following problems. Write the result in scientific notation. $$ \left(9.3806 \times 10^{52}\right)\left(1.009 \times 10^{-31}\right) $$
Step-by-Step Solution
Verified Answer
Question: Find the product of the following numbers in scientific notation: $(9.3806 \times 10^{52})(1.009 \times 10^{-31})$.
Answer: The product of the given numbers in scientific notation is approximately $9.4696 \times 10^{21}$.
1Step 1: Recall the rules for multiplying numbers in scientific notation
To multiply numbers in scientific notation, we have to multiply the coefficients and then add the exponents of the powers of 10. In this case, we are given the two numbers as: $$(9.3806 \times 10^{52})(1.009 \times 10^{-31})$$
2Step 2: Multiply the coefficients
Multiply the coefficients of the given numbers, which are 9.3806 and 1.009: $$9.3806 \times 1.009 \approx 9.4696$$
3Step 3: Add the exponents
Now, we add the exponents in the powers of 10: $$10^{52} \times 10^{-31} = 10^{52-31} = 10^{21}$$
4Step 4: Write the result in scientific notation
Finally, to write the product in scientific notation, we combine the coefficient (9.4696) and the power of 10 (10^21): $$\left(9.3806 \times 10^{52}\right)\left(1.009 \times 10^{-31}\right) \approx 9.4696 \times 10^{21}$$
Key Concepts
Multiplying Numbers in Scientific NotationCoefficients in Scientific NotationAdding Exponents
Multiplying Numbers in Scientific Notation
When you're dealing with numbers in scientific notation, multiplying them is a cinch once you know the simple rule. Scientific notation is a way to express very large or very small numbers succinctly. It involves two parts:
- The coefficient: a number usually between 1 and 10
- A power of ten expressed as \( 10^n \)
- First, multiply the coefficients. In our case: \( 9.3806 \, \text{and} \, 1.009 \)
- Second, add the exponents of the ten's powers. For example: \( 10^{52} \, \text{and} \, 10^{-31} \)
Coefficients in Scientific Notation
The coefficient in scientific notation is the number part that's typically between 1 and 10. It's important because it determines the significant digits of the number. When multiplying coefficients, as we did with \( 9.3806 \times 1.009 \), you simply multiply them like regular numbers.
In the exercise, we got:
In the exercise, we got:
- \( 9.3806 \times 1.009 \approx 9.4696 \)
Adding Exponents
Adding exponents is a key part when multiplying numbers in scientific notation. This step utilizes the property of exponents which states that when you multiply like bases, you add their exponents together. Here's how it works:
When you correctly add exponents, it helps to preserve the precision and scale of the number you're working with. This approach keeps the calculations neat and tidy, allowing you to express the final result accurately in scientific notation.
- Given exponents in the example: \( 10^{52} \) and \( 10^{-31} \)
- Combine them by adding: \( 52 + (-31) = 21 \)
When you correctly add exponents, it helps to preserve the precision and scale of the number you're working with. This approach keeps the calculations neat and tidy, allowing you to express the final result accurately in scientific notation.
Other exercises in this chapter
Problem 89
Find the product for the following problems. Write the result in scientific notation. $$ \left(1.06 \times 10^{-16}\right)\left(2.815 \times 10^{-12}\right) $$
View solution Problem 89
Write the following expressions using only positive exponents. Assume all variables are nonzero. $$ \frac{45 a^{4} b^{2} c^{6}}{15 a^{2} b^{7} c^{8}} $$
View solution Problem 90
Write the following expressions using only positive exponents. Assume all variables are nonzero. $$ \frac{3^{3} x^{4} y^{3} z}{3^{2} x y^{5} z^{5}} $$
View solution Problem 91
Write the following expressions using only positive exponents. Assume all variables are nonzero. $$ \frac{21 x^{2} y^{2} z^{5} w^{4}}{7 x y z^{12} w^{14}} $$
View solution