Problem 9
Question
Yes or No? If No, give a reason. If the graph of an equation is symmetric with respect to both the \(x\) - and \(y\) -axes, is it necessarily symmetric with respect to the origin?
Step-by-Step Solution
Verified Answer
No, symmetry with respect to both axes doesn't guarantee origin symmetry.
1Step 1: Understand Symmetry
To determine symmetry, we need to understand what it means for a graph to be symmetric with respect to each axis and the origin. A graph is symmetric with respect to the x-axis if replacing \( y \) with \( -y \) yields an equivalent equation, symmetric with respect to the y-axis if replacing \( x \) with \( -x \) yields an equivalent equation, and symmetric with respect to the origin if replacing both \( x \) with \( -x \) and \( y \) with \( -y \) yields an equivalent equation.
2Step 2: Analyze Given Symmetries
Given that the graph is symmetric with respect to the x-axis, replacing \( y \) with \( -y \) yields the same graph. Similarly, symmetry with respect to the y-axis means replacing \( x \) with \( -x \) also yields an equivalent graph. We need to explore how these two symmetries together might relate to origin symmetry.
3Step 3: Explore Origin Symmetry
Origin symmetry occurs when both \( x \) and \( y \) are replaced by their negatives and the equation remains equivalent. We theorize that if the graph is symmetric with respect to both axes, the transformations involved could inherently satisfy the conditions for origin symmetry, since \((x,y)\) would map to \((-x,-y)\) through these successive transformations.
4Step 4: Counterexample Test
Consider specific equations to test: \( y^2 = x^2 + 1 \) is symmetric with respect to both the x- and y-axes, yet not symmetric with respect to the origin because substituting \( (-x,-y) \) yields \( y^2 = x^2 + 1 \), which is not satisfied for negative substitutions.
5Step 5: Conclusion
From the counterexample, we see that although the graph is symmetric with respect to both axes, this does not guarantee origin symmetry. Therefore, it is not necessarily true that symmetry about the x- and y-axes implies origin symmetry.
Key Concepts
x-axis symmetryy-axis symmetryorigin symmetry
x-axis symmetry
When a graph is symmetric with respect to the x-axis, it means that for every point \( (x, y) \) on the graph, the point \( (x, -y) \) will also be on the graph. In practical terms, this means you can "fold" the graph along the x-axis, and both halves will match perfectly.
To test for x-axis symmetry, simply replace \( y \) with \( -y \) in the equation of the graph. If the equation remains unchanged, then the graph is symmetric about the x-axis. For example:
To test for x-axis symmetry, simply replace \( y \) with \( -y \) in the equation of the graph. If the equation remains unchanged, then the graph is symmetric about the x-axis. For example:
- Consider the equation \( y^2 = x+1 \). If we replace \( y \) with \( -y \), the equation remains the same \( (-y)^2 = x+1 \), proving x-axis symmetry.
y-axis symmetry
A graph is symmetric with respect to the y-axis if, for every point \( (x, y) \) on the graph, the point \( (-x, y) \) is also on the graph. Visually, it's like "folding" the graph along the y-axis, ensuring that both sides align perfectly.
Testing for y-axis symmetry involves substituting \( x \) with \( -x \) in the equation of a graph. If the equation appears unaltered after the substitution, the graph is symmetric about the y-axis.
Testing for y-axis symmetry involves substituting \( x \) with \( -x \) in the equation of a graph. If the equation appears unaltered after the substitution, the graph is symmetric about the y-axis.
- Take the equation \( y = x^2 \). If we replace \( x \) with \( -x \), we still have \( y = (-x)^2 \), which is equivalent to the original equation, confirming y-axis symmetry.
origin symmetry
Origin symmetry in a graph signifies that if a point \( (x, y) \) is part of the graph, then the point \( (-x, -y) \) will also be. It's akin to rotating the graph 180 degrees around the origin and still having the same graph.
To check for origin symmetry, substitute both \( x \) and \( y \) with their negatives in the equation. If the equation is unchanged, the graph is symmetric about the origin.
To check for origin symmetry, substitute both \( x \) and \( y \) with their negatives in the equation. If the equation is unchanged, the graph is symmetric about the origin.
- For instance, consider the equation \( y = x^3 \). Replacing \( x \) and \( y \) with \( -x \) and \( -y \) gives us \( -y = (-x)^3 \), simplifying to \( y = x^3 \). This shows the graph is origin symmetric.
Other exercises in this chapter
Problem 9
Write an equation that expresses the statement. \(v\) is inversely proportional to \(z\)
View solution Problem 9
Write each radical expression using exponents, and each exponential expression using radicals. Radical expression = \(\frac{1}{\sqrt{3}}\) Exponential expressio
View solution Problem 9
Let \(S=\left\\{-5,-1,0, \frac{2}{3}, \frac{5}{6}, 1, \sqrt{5}, 3,5\right\\}\) Determine which elements of \(S\) satisfy the inequality. $$1
View solution Problem 9
Find the slope of the line through \(P\) and \(Q .\) \(P(-1,2), Q(0,0)\)
View solution