Problem 9
Question
Write an equation for each translation. $$ x^{2}+y^{2}=9 ; \text { down } 1 $$
Step-by-Step Solution
Verified Answer
The equation of the circle after being translated one unit down is \(x^{2}+(y+1)^{2}=9\).
1Step 1: Identify the Current Position of the Circle
The equation of the circle as given is \(x^{2}+y^{2}=9\). The circle is currently at position (0,0) because the equation can be written in the form \((x-h)^{2}+(y-k)^{2}=r^{2}\), where (h,k) is the center and r is the radius of the circle. In this case, h=0, k=0, and r=3.
2Step 2: Apply the Translation
A downward translation of the circle requires subtracting the value of the translation (in this case, 1) from the y-coordinate in the equation. The new equation becomes \(x^{2}+(y+1)^{2}=9\). The center of the circle is now at (0,-1).
3Step 3: Confirm the Changes
Confirm the transformation has taken place by comparing the two equations. The initial equation was \(x^{2}+y^{2}=9\), which represents a circle centered at (0,0), and the final equation is \(x^{2}+(y+1)^{2}=9\), which represents a circle centered at (0,-1). Therefore the circle has been translated one unit down as expected.
Key Concepts
Equation of a CircleCoordinate TransformationDownward Shift
Equation of a Circle
The equation of a circle is a foundational concept in geometry and algebra. It defines the set of all points that are equidistant from a central fixed point, known as the center. This equation can be represented in the form \((x-h)^2 + (y-k)^2 = r^2\). Here, the variables \(h\) and \(k\) denote the coordinates of the circle's center, while \(r\) stands for the radius. When there is no shift along the x or y axes, the equation simplifies to \(x^2 + y^2 = r^2\), indicating a circle centered at the origin \((0,0)\).
Understanding how the equation is constructed helps in recognizing how different components affect the circle's position and size on a coordinate plane. By manipulating the equation, such as changing \(h\) or \(k\), we can shift the circle along the x and y axes, which is important for transformations.
Understanding how the equation is constructed helps in recognizing how different components affect the circle's position and size on a coordinate plane. By manipulating the equation, such as changing \(h\) or \(k\), we can shift the circle along the x and y axes, which is important for transformations.
Coordinate Transformation
Coordinate transformation involves altering the position of objects within a coordinate plane. This is done by adjusting the coordinates in the equation representing the object, affecting their place relative to other points on the plane. When discussing circles, this transformation is achieved by tweaking the terms \((x-h)\) and \((y-k)\), thereby moving the center.
To transform coordinates, we must understand the type of transformation required - whether it is a shift to the left, right, upward, or downward. Different types of translations can be applied:
To transform coordinates, we must understand the type of transformation required - whether it is a shift to the left, right, upward, or downward. Different types of translations can be applied:
- Horizontal Translations: Changes to the \(x\)-coordinate affect left-right movements.
- Vertical Translations: Adjustments to the \(y\)-coordinate result in up-down shifts.
Downward Shift
A downward shift is a type of vertical translation where an object is moved lower along the y-axis of a coordinate plane. For circles, this operation necessitates altering the \((y-k)\) term in the equation.
Consider the initial circle equation \(x^2 + y^2 = 9\). When applying a downward shift of 1 unit, the y-coordinate of the center changes, making \((y-k)\) become \((y+1)\). As a result, the circle is now centered at \((0,-1)\) rather than at the origin. This operation keeps the radius unchanged but alters the circle's position on the plane.
Understanding downward shifts is crucial because it demonstrates how changes to one part of an equation can move the entire figure, thereby influencing spatial relationships.
Consider the initial circle equation \(x^2 + y^2 = 9\). When applying a downward shift of 1 unit, the y-coordinate of the center changes, making \((y-k)\) become \((y+1)\). As a result, the circle is now centered at \((0,-1)\) rather than at the origin. This operation keeps the radius unchanged but alters the circle's position on the plane.
Understanding downward shifts is crucial because it demonstrates how changes to one part of an equation can move the entire figure, thereby influencing spatial relationships.
Other exercises in this chapter
Problem 9
Write an equation of a parabola with a vertex at the origin and the given focus. focus at \((0,7)\)
View solution Problem 9
Graph each equation. Identify the conic section and describe the graph and its lines of symmetry. Then find the domain and range. $$ 6 x^{2}+6 y^{2}=600 $$
View solution Problem 10
Find an equation of an ellipse for each given height and width. Assume that the center of the ellipse is \((0,0) .\) $$ h=32 \mathrm{ft}, w=16 \mathrm{ft} $$
View solution Problem 10
Find the equation of each hyperbola described. All points on the hyperbola are 72 units closer to one focus than the other. The foci are located at \((0,0)\) an
View solution