Problem 9
Question
Without doing detailed calculations, explain which of the following has the greatest number of \(\mathrm{N}\) atoms (a) \(50.0 \mathrm{g}\) \(\mathrm{N}_{2} \mathrm{O} ;\) (b) \(17.0 \mathrm{g} \mathrm{NH}_{3} ;\) (c) \(150 \mathrm{mL}\) of liquid pyridine, \(\mathrm{C}_{5} \mathrm{H}_{5} \mathrm{N}(d=0.983 \mathrm{g} / \mathrm{mL}) ;\) (d) \(1.0 \mathrm{mol} \mathrm{N}_{2}\)
Step-by-Step Solution
Verified Answer
The substance with the greatest number of Nitrogen atoms is option (d) that is \(1.0 \, \mathrm{mol}\) of \(N_{2}\), because it contains 2 moles of Nitrogen atoms.
1Step 1: Determine the Molecular Mass of each option
In this first step, the molecular masses are determined. For (a) N2O, the molecular mass is \(2(14.01) + 16.00 = 44.02 \, \mathrm{g/mol}\). For (b) NH3, the molecular mass is \(14.01 + 3(1.01) = 17.04 \, \mathrm{g/mol}\). For (c) C5H5N, the molecular mass is \(5(12.01) + 5(1.01) + 14.01 = 79.10 \, \mathrm{g/mol}\). Finally, for (d) N2, the molecular mass is \(2(14.01) = 28.02 \, \mathrm{g/mol}\).
2Step 2: Calculating the number of atoms for each option
In this step, we estimate which option gives the most number of Nitrogen atoms. For (a) \(50.0 \, \mathrm{g}\) of \(N2O\), it's approximately 1 mole of Nitrogen atoms. For (b) \(17.0 \, \mathrm{g}\) of \(NH3\), it's approximately 1 mole of Nitrogen atoms. For (c) \(150 \, \mathrm{mL}\) of pyridine \(C5H5N\), using the given density we can find its 'nitrogen mass' and using that it's again around 1 mole of Nitrogen atoms. For (d) \(1.0 \, \mathrm{mol}\) of \(N2\), we have 2 moles of Nitrogen atoms.
3Step 3: Drawing Conclusion
On comparing the moles of Nitrogen atoms from each option, it's clear that option (d) gives the highest number of Nitrogen atoms because it has 2 moles of Nitrogen atoms and all other choices have approximately 1 mole of Nitrogen atoms.
Key Concepts
Molecular MassChemical CompoundsNitrogen Atoms
Molecular Mass
Molecular mass is a crucial concept in chemistry. It helps us understand the weight of one molecule of a substance. This is calculated by adding up the atomic masses of all the atoms in the molecule. For instance, in the case of nitrogen dioxide (\(\text{N}_2\text{O}\)), you calculate its molecular mass by adding the masses of two nitrogen atoms and one oxygen atom:
- Nitrogen (N): 14.01
- Oxygen (O): 16.00
Chemical Compounds
Chemical compounds are made of atoms bonded together, and they come with varying compositions and molecular formulas. Understanding compounds like \(\text{N}_2\text{O}\), \(\text{NH}_3\), and pyridine \(\text{C}_5\text{H}_5\text{N}\) provides insight into how elements like nitrogen are grouped. Each compound has a unique molecular formula that indicates:
- The types of atoms present
- The number of each type of atom in the compound
Nitrogen Atoms
Nitrogen atoms are a fundamental part of many common compounds. They play a key role in substances like nitrogen gas (\(\text{N}_2\)), where nitrogen atoms bond together. \(\text{N}_2\) is unique because it has two nitrogen atoms per molecule, thus counting as two moles of nitrogen per mole of the compound. In other compounds such as nitrous oxide (\(\text{N}_2\text{O}\)) and ammonia (\(\text{NH}_3\)), nitrogen is present in lesser quantities.
- Understanding how nitrogen atoms are distributed allows for accurate predictions about the quantity you might find in a given sample.
- This knowledge aids in fields ranging from industrial chemistry to environmental science.
Other exercises in this chapter
Problem 7
The amino acid methionine, which is essential in human diets, has the molecular formula \(\mathrm{C}_{5} \mathrm{H}_{11} \mathrm{NO}_{2} \mathrm{S}\) Determine
View solution Problem 8
Determine the number of moles of \(\mathrm{Br}_{2}\) in a sample consisting of (a) \(8.08 \times 10^{22} \mathrm{Br}_{2}\) molecules; (b) \(2.17 \times 10^{24}\
View solution Problem 10
Without doing detailed calculations, determine which of the following has the greatest number of \(S\) atoms (a) 0.12 mol of solid sulfur, \(S_{8} ;\) (b) 0.50
View solution Problem 11
Determine the number of moles of (a) \(\mathrm{N}_{2} \mathrm{O}_{4}\) in a \(115 \mathrm{g}\) sample (b) \(\mathrm{N}\) atoms in \(43.5 \mathrm{g}\) of \(\math
View solution