Problem 9
Question
Use the properties of limits to calculate the following limits: \(\lim _{(x, y) \rightarrow(2.1)} \frac{x^{2}+y^{2}}{x^{2}-y^{2}}\)
Step-by-Step Solution
Verified Answer
The limit is \(\frac{5}{3}\).
1Step 1: Identify the Type of Limit
We have a multivariable limit \[ \lim_{(x, y) \rightarrow (2,1)} \frac{x^2 + y^2}{x^2 - y^2} \]We need to evaluate this limit as \((x, y)\) approaches \((2, 1)\).
2Step 2: Simplifying the Function
First, plug in the values \(x = 2\) and \(y = 1\) into the expression \(\frac{x^2 + y^2}{x^2 - y^2}\) to see if it's defined:\[\frac{2^2 + 1^2}{2^2 - 1^2} = \frac{4 + 1}{4 - 1} = \frac{5}{3}\] As the expression does not result in an indeterminate form like \(\frac{0}{0}\), the limit can be directly evaluated.
3Step 3: Evaluate the Limit
Since substituting \((x, y) = (2, 1)\) into the function \(\frac{x^2 + y^2}{x^2 - y^2}\) yields a defined value without indeterminacy, the limit is the value of the function at that point:\[\lim _{(x, y) \rightarrow(2, 1)} \frac{x^{2}+y^{2}}{x^{2}-y^{2}} = \frac{5}{3}\]
Key Concepts
CalculusProperties of LimitsIndeterminate Forms
Calculus
Calculus is a branch of mathematics that enables us to understand the change and motion through the use of derivatives and integrals. One important aspect of calculus is the concept of limits. Limits help us to understand the behavior of a function as it approaches a certain point. This is crucial in determining continuity, finding tangents, and evaluating multivariable functions, like in our exercise where we approach \\((x, y) \rightarrow (2,1)\).
- Limits are fundamental in calculus for analyzing functions.
- They allow us to see what happens as inputs approach a certain point.
- Understanding limits is essential for mastering calculus and for tackling multivariable problems.
Properties of Limits
Understanding the properties of limits is key to evaluating the limits of complex functions, especially when dealing with multivariable calculus. These properties provide rules that help us break down and simplify problems to find limit values more easily.Some basic properties that are often used include:
- Sum Rule: The limit of a sum is the sum of the limits.
- Difference Rule: The limit of a difference is the difference of the limits.
- Product Rule: The limit of a product is the product of the limits.
- Quotient Rule: The limit of a quotient is the quotient of the limits, provided the limit of the denominator is not zero.
Indeterminate Forms
Indeterminate forms occur when the limits of functions result in undefined expressions such as \( \frac{0}{0} \) or \( \frac{\infty}{\infty} \). These forms require special techniques to evaluate, often involving algebraic manipulation or L'Hopital's Rule if applicable.In the exercise, when substituting \( x = 2 \) and \( y = 1 \), the expression \( \frac{x^{2} + y^{2}}{x^{2} - y^{2}} \) did not result in an indeterminate form. This means it evaluated smoothly to \( \frac{5}{3} \). When faced with an indeterminate form, you might consider:
- Simplification: Algebraically simplify the function, if possible.
- L'Hopital's Rule: Apply this rule if both numerator and denominator tend to zero or infinity.
- Rewriting expressions: Use trigonometric identities, factoring, or common factors to simplify.
Other exercises in this chapter
Problem 8
8\. Write down an expression for \(\frac{d w}{d t}\) where \(w=e^{f(x, y)}\) with \(x=u(t)\) and \(y=v(t)\)
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Find \(\partial f / \partial x\) and \(\partial f / \partial y\) for the given functions. \(f(x, y)=e^{\sqrt{x+y}}\)
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Evaluate each function at the given point. \(f(x, y)=x^{2}+y\) at \((2,3)\)
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The functions are defined for all \((x, y) \in R^{2} .\) Find all candidates for local extrema, and use the Hessian matrix to determine the type (maximum, minim
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