Problem 9
Question
Use the intermediate value theorem to show that each function has a real zero between the two numbers given. Then, use your calculator to approximate the zero to the nearest hundredth. $$P(x)=3 x^{2}-2 x-6 ; \quad 1 \text { and } 2$$
Step-by-Step Solution
Verified Answer
There is a real zero between 1 and 2, approximately at 1.53.
1Step 1: Understand the Intermediate Value Theorem
The Intermediate Value Theorem states that if a continuous function \( f(x) \) takes values \( f(a) \) and \( f(b) \) at any two points \( a \) and \( b \), and if \( f(a) \) and \( f(b) \) have opposite signs, then there exists at least one number \( c \) between \( a \) and \( b \) such that \( f(c) = 0 \). This means we need to check the signs of \( P(1) \) and \( P(2) \).
2Step 2: Evaluate P(x) at the Given Points
Calculate \( P(1) = 3(1)^2 - 2(1) - 6 = 3 - 2 - 6 = -5 \). Next, calculate \( P(2) = 3(2)^2 - 2(2) - 6 = 12 - 4 - 6 = 2 \). Therefore, \( P(1) = -5 \) and \( P(2) = 2 \).
3Step 3: Apply the Intermediate Value Theorem
Since \( P(1) = -5 \) and \( P(2) = 2 \), and they have opposite signs, the Intermediate Value Theorem confirms that there is a real zero between \( x = 1 \) and \( x = 2 \).
4Step 4: Approximate the Zero Using a Calculator
Use a calculator to find the zero of \( P(x) = 3x^2 - 2x - 6 \) between 1 and 2. By using numerical methods, such as the bisection method or a calculator's root function, you find that the zero is approximately \( x \approx 1.53 \).
Key Concepts
Real Zeros of PolynomialsEvaluating FunctionsNumerical Approximation Methods
Real Zeros of Polynomials
Polynomials are mathematical expressions involving variables raised to whole-number exponents. The "real zeros" of a polynomial are solutions to the equation derived by setting the polynomial equal to zero. These are the points where the graph of the polynomial crosses or touches the x-axis. In simpler terms, they are the x-values for which the polynomial results in a value of zero. Finding real zeros can help us understand the behavior of polynomial functions.
The Intermediate Value Theorem helps us identify at least one real zero within a given interval by examining the signs of the function's values at the interval's endpoints.
- The polynomial in this exercise is given as: \[ P(x) = 3x^2 - 2x - 6 \].
- To find the real zeros, we want to find the values of \( x \) where \( P(x) = 0 \).
The Intermediate Value Theorem helps us identify at least one real zero within a given interval by examining the signs of the function's values at the interval's endpoints.
Evaluating Functions
Evaluating a function simply means finding the value of the function for a particular input. In this exercise, we evaluated the polynomial function \( P(x) = 3x^2 - 2x - 6 \) at different points.
- First, we calculated \( P(1) = 3(1)^2 - 2(1) - 6 = -5 \).
- Next, we figured out \( P(2) = 3(2)^2 - 2(2) - 6 = 2 \).
Numerical Approximation Methods
At times, precisely calculating the zero of a polynomial by hand is challenging or impossible. This is where numerical approximation methods are beneficial. These methods help us estimate the root of the polynomial with the help of technology, like calculators or computers.
One popular method is the bisection method, which narrows down the interval where the zero resides by repeatedly halving the interval and checking the sign changes.
One popular method is the bisection method, which narrows down the interval where the zero resides by repeatedly halving the interval and checking the sign changes.
- This process is repeated until the interval is sufficiently small to give a good approximation.
Other exercises in this chapter
Problem 9
Find a polynomial function \(P(x)\) of degree 3 with real coefficients that satisfies the given conditions. Do not use a calculator. Zeros of \(-2,1,\) and \(0
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Answer each question. Which one of the following equations is set up for direct use of the zero- product property? Solve it. A. \(3 x^{2}-17 x-6=0\) B. \((2 x+5
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Use an end behavior diagram or to describe the end behavior of the graph of each function. Do not use a calculator. $$P(x)=\sqrt{5} x^{3}+2 x^{2}-3 x+4$$
View solution Problem 9
For each quadratic function defined , (a) write the function in the form \(P(x)=a(x-h)^{2}+k,\) (b) give the vertex of the parabola, and (c) graph the function.
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