Problem 9
Question
The orbital angular momentum of an electron has a magnitude of \(4.716 \times 10^{-34} \mathrm{kg} \cdot \mathrm{m}^{2} / \mathrm{s}\) . What is the angular- momentum quantum number \(/\) for this electron?
Step-by-Step Solution
Verified Answer
The angular-momentum quantum number \( l \) is 4.
1Step 1: Understand the formula
The formula to calculate the magnitude of the angular momentum \(L\) in quantum mechanics is given by \(L = \sqrt{l(l+1)} \, \hbar\), where \(\hbar\) is the reduced Planck's constant \( (\hbar = 1.0545718 \times 10^{-34} \mathrm{J} \cdot \mathrm{s}) \) and \( l \) is the angular-momentum quantum number.
2Step 2: Calculate \(\hbar\) term
Since \(L = 4.716 \times 10^{-34} \mathrm{kg} \cdot \mathrm{m}^2 / \mathrm{s} \), we can write \( \sqrt{l(l+1)} \hbar = 4.716 \times 10^{-34} \). Divide both sides by \(\hbar\): \[ \sqrt{l(l+1)} = \frac{4.716 \times 10^{-34}}{1.0545718 \times 10^{-34}} \approx 4.473. \]
3Step 3: Solve for \(l\)
We have \( \sqrt{l(l+1)} = 4.473 \). Square both sides to remove the square root: \[ l(l+1) = (4.473)^2 \approx 20.007. \] Solve the quadratic equation \( l^2 + l - 20.007 = 0 \) using the quadratic formula \( l = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \), where \(a = 1\), \(b = 1\), and \(c = -20.007\).
4Step 4: Apply the quadratic formula
Using the quadratic formula, \( l = \frac{-1 \pm \sqrt{1 + 4 \times 20.007}}{2} = \frac{-1 \pm \sqrt{81.028}}{2} \approx \frac{-1 \pm 9.005}{2} \). The valid physical solution would be \( l = \frac{-1 + 9.005}{2} \approx 4.0025 \). Since \( l \) must be an integer, we round it to the nearest whole number, which is \( l = 4 \).
Key Concepts
Orbital Angular MomentumQuantum MechanicsReduced Planck's ConstantQuadratic Formula
Orbital Angular Momentum
Orbital angular momentum is a fundamental concept in quantum mechanics that describes the rotational motion of electrons around the nucleus in atoms. Unlike classical mechanics, where angular momentum can take any value, in quantum mechanics it is quantized. This means that only certain discrete values, determined by quantum numbers, are allowed. Orbital angular momentum is associated with the angular-momentum quantum number, often denoted as "l". This quantum number determines the shape of the electron cloud around the nucleus and can have integer values starting from zero. The magnitude of the orbital angular momentum is given by the expression \( L = \sqrt{l(l+1)} \hbar \), where \( \hbar \) is the reduced Planck's constant.
Understanding the quantized nature of orbital angular momentum helps explain various atomic structures and spectral lines. It is key to interpreting how electrons occupy different energy levels in an atom, providing insight into the periodic table and chemical reactivity.
Understanding the quantized nature of orbital angular momentum helps explain various atomic structures and spectral lines. It is key to interpreting how electrons occupy different energy levels in an atom, providing insight into the periodic table and chemical reactivity.
Quantum Mechanics
Quantum mechanics is the branch of physics that deals with the behavior of very small particles, such as electrons and photons, which follow different rules than macro-scale objects. One of its core principles is the quantization of certain physical properties. This includes energies, angular momentum, and even the orbitals of electrons within atoms.
Key elements of quantum mechanics include:
Key elements of quantum mechanics include:
- Wave-particle duality: Particles like electrons exhibit both wave-like and particle-like properties.
- Quantum superposition: Particles can exist in multiple states simultaneously until measured.
- Heisenberg's uncertainty principle: It is impossible to know both the position and momentum of a particle precisely at the same time.
Reduced Planck's Constant
The reduced Planck's constant, often represented as \( \hbar \), is a fundamental constant in quantum mechanics. It relates to the quantization of angular momentum and energy levels. Numerically, \( \hbar = 1.0545718 \times 10^{-34} \mathrm{J} \cdot \mathrm{s} \).
The formula for orbital angular momentum \( L = \sqrt{l(l+1)} \hbar \) includes \( \hbar \) as a scaling factor, showing how fundamental it is in translating the quantum mechanical equations into measurable quantities. In many equations throughout quantum mechanics, the presence of \( \hbar \) shows up, for instance, in energy calculations and uncertainty relations.
Understanding \( \hbar \) helps in bridging the conceptual gap between observable physical quantities and their quantized descriptions in quantum theory. It acts as a conversion factor between the abstract mathematics of quantum mechanics and the physically observable phenomena.
The formula for orbital angular momentum \( L = \sqrt{l(l+1)} \hbar \) includes \( \hbar \) as a scaling factor, showing how fundamental it is in translating the quantum mechanical equations into measurable quantities. In many equations throughout quantum mechanics, the presence of \( \hbar \) shows up, for instance, in energy calculations and uncertainty relations.
Understanding \( \hbar \) helps in bridging the conceptual gap between observable physical quantities and their quantized descriptions in quantum theory. It acts as a conversion factor between the abstract mathematics of quantum mechanics and the physically observable phenomena.
Quadratic Formula
The quadratic formula is a mathematical tool used to find solutions to quadratic equations, which are polynomials of the form \( ax^2 + bx + c = 0 \). The formula is given by:\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]In the context of quantum mechanics, the quadratic formula is essential for solving equations that describe electron behavior, like calculating the angular-momentum quantum number from given angular momentum. In this problem, by expressing the equation \( l(l+1) = (4.473)^2 \) in the form \( l^2 + l - 20.007 = 0 \), the quadratic formula provides the solutions for "l".
The formula is straightforward but powerful, often unveiling two potential solutions due to the \( \pm \) symbol. In physical applications, typically only one solution is meaningful based on the context, as in the case with the angular-momentum quantum number, which must be an integer.
The formula is straightforward but powerful, often unveiling two potential solutions due to the \( \pm \) symbol. In physical applications, typically only one solution is meaningful based on the context, as in the case with the angular-momentum quantum number, which must be an integer.
Other exercises in this chapter
Problem 7
Consider an electron in the \(N\) shell. (a) What is the smallest orbital angular momentum it could have? (b) What is the largest orbital angular momentum it co
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An electron is in the hydrogen atom with \(n=5 .\) (a) Find the possible values of \(L\) and \(L_{z}\) for this electron, in units of \(\hbar .\) (b) For each v
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Consider states with angular-momentum quantum number \(l=2 .\) (a) In units of \(\hbar,\) what is the largest possible value of \(L_{z} ?\) (b) In units of \(\h
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Calculate, in units of \(\hbar,\) the magnitude of the maximum orbital angular momentum for an electron in a hydrogen atom for states with a principal quantum n
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