Problem 9
Question
The least possible value of \(k\) for which the function \(f(x)=x^{2}+k x+1\) may be increasing on \([1,2]\) is (A) 2 (B) \(-2\) (C) 0 (D) None of these
Step-by-Step Solution
Verified Answer
The least possible value of \(k\) is \(-2\). Option B.
1Step 1: Understand the conditions for an increasing function
A function is increasing on an interval if its derivative is non-negative for every point within that interval. For the function given, \( f(x) = x^2 + kx + 1 \), we need to find the derivative and check the conditions under which this derivative is non-negative on \([1, 2]\).
2Step 2: Differentiate the function
Find the derivative of \( f(x) \) with respect to \( x \). The derivative, \( f'(x) \), is given by:\[ f'(x) = 2x + k \]
3Step 3: Set up the inequality for increasing function
The function is increasing on \([1, 2]\) if \( f'(x) = 2x + k \geq 0 \) for all \( x \) in the interval \([1, 2]\). This implies two inequalities: 1. \( 2(1) + k \geq 0 \) 2. \( 2(2) + k \geq 0 \)
4Step 4: Solve the inequalities
Solve the inequalities derived in the previous step:- From \( 2(1) + k \geq 0 \), we get \( 2 + k \geq 0 \) or \( k \geq -2 \).- From \( 2(2) + k \geq 0 \), we get \( 4 + k \geq 0 \) or \( k \geq -4 \).The stronger condition is \( k \geq -2 \), as it encompasses \( k \geq -4 \).
5Step 5: Determine the least possible value of \( k \)
The least possible value of \( k \) that satisfies both conditions is \( k = -2 \). Thus, \( k = -2 \) is the smallest value for which the function is increasing on \([1, 2]\).
Key Concepts
Increasing FunctionDerivativeInequality Solving
Increasing Function
When we talk about an increasing function, it means that as you move along the graph from left to right, the values of the function never decrease.
An increasing function keeps climbing, or at least stays constant, over a specified interval.
If we consider a function \( f(x) \), it is increasing on a closed interval \([a, b]\) when for any two numbers \( x_1 \) and \( x_2 \) in that interval where \( x_1 < x_2 \), the function values satisfy:
An increasing function keeps climbing, or at least stays constant, over a specified interval.
If we consider a function \( f(x) \), it is increasing on a closed interval \([a, b]\) when for any two numbers \( x_1 \) and \( x_2 \) in that interval where \( x_1 < x_2 \), the function values satisfy:
- \( f(x_1) \leq f(x_2) \).
Derivative
The derivative of a function provides a powerful tool in calculus, representing the rate of change of the function's output for a given change in input.
The derivative essentially gives us the slope of the tangent line at any point on the function's graph.
For a function \( f(x) \), the derivative, denoted as \( f'(x) \), captures how the function’s values change as \( x \) changes.
The derivative essentially gives us the slope of the tangent line at any point on the function's graph.
For a function \( f(x) \), the derivative, denoted as \( f'(x) \), captures how the function’s values change as \( x \) changes.
- If \( f'(x) > 0 \), the function is increasing at that point.
- If \( f'(x) = 0 \), the function is constant (flat) at that point.
- If \( f'(x) < 0 \), the function is decreasing at that point.
Inequality Solving
Solving inequalities is a key part of determining where a function is increasing or decreasing.
The inequalities arise naturally from the derivative's conditions: checking whether it is non-negative or negative over certain intervals.
Consider the derivative we found: \( f'(x) = 2x + k \). To identify where the function \( f(x) = x^2 + kx + 1 \) is increasing, we set up the inequality:
Through solving such inequalities, you can identify conditions like the smallest value of \( k \) for which a function remains increasing over a given interval.
The inequalities arise naturally from the derivative's conditions: checking whether it is non-negative or negative over certain intervals.
Consider the derivative we found: \( f'(x) = 2x + k \). To identify where the function \( f(x) = x^2 + kx + 1 \) is increasing, we set up the inequality:
- \( 2x + k \geq 0 \).
- At \( x = 1 \): \( 2(1) + k \geq 0 \), resulting in \( k \geq -2 \).
- At \( x = 2 \): \( 2(2) + k \geq 0 \), giving \( k \geq -4 \).
Through solving such inequalities, you can identify conditions like the smallest value of \( k \) for which a function remains increasing over a given interval.
Other exercises in this chapter
Problem 7
The range of values of \(a\) for which the function \(f(x)=x^{3}+(a+2) x^{2}+3 a x+5\) may be monotonic in \(R\), is (A) \(a4\) (D) None of these
View solution Problem 8
The values of \(k\) for which the function \(f(x)=k x^{3}-9 x^{2}+9 x+3\) may be increasing on \(R\) are (A) \(k>3\) (B) \(k
View solution Problem 10
If \(f(x)=2 x^{3}+9 x^{2}+\lambda x+20\) is a decreasing function of \(x\) in the largest possible interval \((-2,-1)\) then \(\lambda\) is equal to (A) 12 (B)
View solution Problem 11
Let \(f^{\prime}(x)>0\) and \(g^{\prime}(x)f[g(x-1)]\) (B) \(f[g(x)]>f[g(x+1)]\) (C) \(g[f(x)]>g[f(x-1)]\) (D) \(g[f(x)]
View solution