Problem 9
Question
Solve each of the equations. $$x=3.36-0.12 x$$
Step-by-Step Solution
Verified Answer
\( x = 3 \)
1Step 1: Move all terms involving x to one side
Our goal is to isolate the variable \( x \) on one side of the equation. Start by adding \( 0.12x \) to both sides of the equation, resulting in: \[ x + 0.12x = 3.36 \] Thus, the equation becomes: \[ 1.12x = 3.36 \].
2Step 2: Solve for x
To find \( x \), we need to divide both sides of the equation by 1.12. This will isolate \( x \): \[ x = \frac{3.36}{1.12} \] Calculate the division to get the value of \( x \): \[ x = 3 \].
Key Concepts
Solving EquationsVariable IsolationBasic Algebra
Solving Equations
Solving equations is a fundamental part of algebra that requires you to find the value of a variable that makes an equation true. In this exercise, the goal is to solve an equation where the variable, represented by \( x \), appears on both sides. The first step is to simplify and rearrange the terms so that all the terms involving \( x \) are on one side of the equation. This process often involves:
- Adding or subtracting terms to both sides
- Combining like terms to simplify the equation
Variable Isolation
Variable isolation is a key technique in solving equations, especially linear equations like the one in this exercise. The importance of isolating the variable lies in its ability to lead us to the solution directly. Here's how it works:Once you have gathered all the terms with \( x \) on one side, you need to ensure that \( x \) stands alone. In our worked-out problem, we reached the equation \( 1.12x = 3.36 \). To isolate \( x \):
- Divide both sides of the equation by the coefficient of \( x \), which in this case is 1.12.
Basic Algebra
Awareness and understanding of basic algebra principles are crucial when dealing with equations. Concepts like collecting like terms, balancing equations, and performing arithmetic operations accurately, form the backbone of solving problems. These fundamentals mean acting upon the properties of equality consistently, which keeps the equation balanced.In our equation \( x = 3.36 - 0.12x \):
- Recognize \( 0.12x \) as a term involving the variable, needing a move to the other side
- Combine like terms to reduce complexity
- Use division to finalize the isolation
Other exercises in this chapter
Problem 9
For Problems \(1-12\), solve each of the equations. These equations are the types you will be using in Problems 13-40. $$ \frac{5}{2} r+\frac{5}{2}(r+6)=135 $$
View solution Problem 9
For Problems \(1-10\), solve for the specified variable using the given facts. (Objective 1) Solve \(A=P+P r t\) for \(t\) if \(A=652, P=400\), and \(r=0.07\).
View solution Problem 9
Solve each of the equations. $$\frac{x+1}{6}=\frac{x+2}{4}$$
View solution Problem 10
For Problems 1-12, solve each equation. You will be using these types of equations in Problems \(13-41\). $$ 30 x+14\left(3 \frac{1}{2}-x\right)=97 $$
View solution