Problem 9
Question
Prove that \(\forall x \in \mathbb{R}, x \notin \mathbb{Z} \Longrightarrow\lfloor x\rfloor+\lfloor-x\rfloor=-1\).
Step-by-Step Solution
Verified Answer
For \(x \otin \mathbb{Z} \), \(\floor{x} + \floor{-x} = -1\).
1Step 1: Understand the Floor Function
The floor function \(\floor{x}\) of a real number \(x\) is the greatest integer less than or equal to \(x\). For example, \(\floor{2.3} = 2\) and \(\floor{-1.7} = -2\).
2Step 2: Analyze \(x\) and \(-x\) for Non-Integer x
Given \(x otin \mathbb{Z}\), \(x\) is not an integer. This means \(x\) can be written as \(n + f\) where \(n\) is an integer and \(0 < f < 1\). Similarly, \(-x = -n - f\).
3Step 3: Apply the Floor Function
Apply the floor function to \(x\) and \(-x\). We get \(\floor{x} = \floor{n + f} = n\) because \(n\) is the largest integer ≤ \(n + f\). For \(-x\), we have \(\floor{-x} = \floor{-n - f} = -n - 1\) because \(-n - 1\) is the largest integer ≤ \(-n - f\).
4Step 4: Sum the Values
Sum the values obtained in the previous step: \(\floor{x} + \floor{-x} = n + (-n - 1) = -1\).
5Step 5: Conclusion
We've shown that \(\floor{x} + \floor{-x} = -1\) for any \(x otin \mathbb{Z}\). This means \(\forall x \in \mathbb{R}, x \otin \mathbb{Z}, \floor{x} + \floor{-x} = -1\).
Key Concepts
Understanding Real NumbersNon-Integer ValuesMathematical Proofs
Understanding Real Numbers
Real numbers, denoted as \(\backslash mathbb{R}\), include all the numbers that can be found on the number line. This category encompasses:
- Integers like \(-2, 0, 5\)
- Rational numbers such as \(\frac{1}{2}, -7.3, 8\frac{1}{4}\)
- Irrational numbers like \(\backslash sqrt{2}, π\)
Non-Integer Values
Non-integer values are real numbers that are not whole numbers. These include:
- Fractions and decimals (e.g., \(\frac{3}{4}\) and 0.65)
- Irrational numbers (e.g., \(\backslash sqrt{3}\) and π)
Mathematical Proofs
Mathematical proofs are logical arguments demonstrating that a statement is true. They involve a sequence of steps based on axioms, definitions, and previously established results. Proofs can be:
- Direct: Where the truth is established through straightforward reasoning.
- Indirect: By showing the negation of the statement leads to a contradiction.
Other exercises in this chapter
Problem 9
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Suppose that \(a, b\) and \(c\) are integers such that \(a \mid b\) and \(b \mid c .\) Prove that \(a \mid c\)
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