Problem 9
Question
Predict the sign of \(\Delta S\) for the following. (a) ice cream melting (b) boiling water (c) dissolving instant coffee in hot water (d) sugar, \(\mathrm{C}_{12} \mathrm{H}_{22} \mathrm{O}_{11}\), decomposing to carbon and steam
Step-by-Step Solution
Verified Answer
Question: Predict the sign of entropy change (\(\Delta S\)) for the following processes: (a) Ice cream melting, (b) Boiling water, (c) Dissolving instant coffee in hot water, (d) Sugar decomposing to carbon and steam.
Answer: (a) \(\Delta S > 0\), (b) \(\Delta S > 0\), (c) \(\Delta S > 0\), (d) \(\Delta S > 0\)
1Step 1: (a) Ice cream melting
When ice cream melts, it goes from a more solid state to a more liquid state. This increases the disorder of the system since the molecules in a liquid state have more freedom to move around than the molecules in a solid state. Therefore, the entropy increases and we can predict that the sign of \(\Delta S\) is positive.
2Step 2: (b) Boiling water
Boiling water involves a phase transition from liquid to gas. Gaseous molecules have more freedom of movement and are more randomly arranged as compared to liquid molecules. This means that the disorder of the system increases when water boils. Therefore, the entropy increases and we can predict that the sign of \(\Delta S\) is positive.
3Step 3: (c) Dissolving instant coffee in hot water
When instant coffee dissolves in hot water, the solid coffee particles become dispersed throughout the water. This creates a more disordered and random arrangement of particles in the system. Therefore, the entropy increases and we can predict that the sign of \(\Delta S\) is positive.
4Step 4: (d) Sugar decomposing to carbon and steam
When sugar decomposes, it breaks down into simpler components: carbon and steam. The initial state (solid sugar) is highly ordered with the molecules arranged in a crystalline lattice. The final state (carbon and steam) has significantly more disorder and randomness, as the individual atoms and molecules are separated and spread out. Therefore, the entropy increases and we can predict that the sign of \(\Delta S\) is positive.
Key Concepts
Phase TransitionsEntropy and DisorderChemical Decomposition
Phase Transitions
Understanding phase transitions is crucial as these transformations have significant impacts on the entropy of a system. Simply put, phase transitions are the changes from one state of matter to another, such as solid to liquid, liquid to gas, or the reverse. During phase transitions, the organization of particles is altered, directly influencing the system's entropy.
Consider the melting of ice cream or boiling water, as mentioned in the original exercise. These processes are classic examples of phase transitions, where solid becomes liquid, and liquid turns into gas, respectively. In each case, the change involves the absorption of energy, which disrupts the orderly arrangement of particles, allowing them more freedom of motion. This increase in particle liberty and randomness is directly associated with an increase in entropy, hence predicting a positive sign for \(\Delta S\) is correct.
Consider the melting of ice cream or boiling water, as mentioned in the original exercise. These processes are classic examples of phase transitions, where solid becomes liquid, and liquid turns into gas, respectively. In each case, the change involves the absorption of energy, which disrupts the orderly arrangement of particles, allowing them more freedom of motion. This increase in particle liberty and randomness is directly associated with an increase in entropy, hence predicting a positive sign for \(\Delta S\) is correct.
Entropy and Disorder
Entropy is fundamentally a measure of the disorder or randomness within a system. It's a concept deeply rooted in the second law of thermodynamics, which implies that in an isolated system, entropy can never decrease over time. When dealing with exercises such as dissolving coffee in water or the melting of ice cream, the commonality is the change in the system's structure towards more randomness.
For instance, as the ice cream melts, the tightly packed structure of the ice crystals becomes a more chaotic arrangement of liquid molecules. The increased number of microstates available to these molecules translates to higher disorder. A similar case occurs with the dissolution of coffee; the uniform solid coffee particles become irregularly spread in the solvent, showcasing a more disordered state. Entropy is essentially a numeric tally of this disorder, so when the randomness increases, so does the entropy.
For instance, as the ice cream melts, the tightly packed structure of the ice crystals becomes a more chaotic arrangement of liquid molecules. The increased number of microstates available to these molecules translates to higher disorder. A similar case occurs with the dissolution of coffee; the uniform solid coffee particles become irregularly spread in the solvent, showcasing a more disordered state. Entropy is essentially a numeric tally of this disorder, so when the randomness increases, so does the entropy.
Chemical Decomposition
Chemical decomposition is a process where a single compound breaks down into two or more simpler substances, which is often associated with an increase in entropy. In the sugar decomposition from the original exercise, the sugar molecule \(\mathrm{C}_{12} \mathrm{H}_{22} \mathrm{O}_{11}\) breaks down into separate carbon and steam molecules. The initial crystalline structure is highly ordered, and upon decomposition, the products are spread out and disordered.
The decomposition process is a chemical reaction that directly converts a structured substance into less ordered products. It's a prime example of how chemical changes can trigger significant changes in entropy. The predictably positive \(\Delta S\) value arises because the system moves from a state of low entropy (well-organized sugar molecules) to a state of high entropy (dispersed carbon atoms and steam), which matches with our observation that systems tend to shift towards higher levels of disorder— a principle that is at the heart of understanding entropy in chemical processes.
The decomposition process is a chemical reaction that directly converts a structured substance into less ordered products. It's a prime example of how chemical changes can trigger significant changes in entropy. The predictably positive \(\Delta S\) value arises because the system moves from a state of low entropy (well-organized sugar molecules) to a state of high entropy (dispersed carbon atoms and steam), which matches with our observation that systems tend to shift towards higher levels of disorder— a principle that is at the heart of understanding entropy in chemical processes.
Other exercises in this chapter
Problem 7
In each of the following pairs, choose the substance with a lower entropy. (a) \(\mathrm{H}_{2} \mathrm{O}(l)\) at \(10^{\circ} \mathrm{C}, \mathrm{H}_{2} \math
View solution Problem 8
In each of the following pairs, choose the substance with a lower entropy. (a) One mole of \(\mathrm{O}_{2}(g)\) with \(758 \mathrm{~mm} \mathrm{Hg}\) pressure,
View solution Problem 10
Predict the sign of \(\Delta S\) for the following. (a) a lake freezing (b) precipitating lead chloride (c) a candle burning (d) weeding a garden
View solution Problem 11
Predict the sign of \(\Delta S^{\circ}\) for each of the following reactions. (a) \(2 \mathrm{Na}(s)+\mathrm{Cl}_{2}(g) \longrightarrow 2 \mathrm{NaCl}(s)\) (b)
View solution