Problem 9
Question
},\( of the given system. $$\begin{aligned}x_{1}+2 x_{2}-… # Determine the coefficient matrix, \)A\(, the right-hand side vector, \)\mathbf{b},\( and the augmented matrix, \)A^{\\#},$ of the given system. $$\begin{aligned}x_{1}+2 x_{2}-3 x_{3} &=1 \\\2 x_{1}+4 x_{2}-5 x_{3} &=2 \\\7 x_{1}+2 x_{2}-x_{3} &=3\end{aligned}$$
Step-by-Step Solution
Verified Answer
The coefficient matrix, \(A\), right-hand side vector, \(\mathbf{b}\), and the augmented matrix, \(A^{\#}\), for the given system are:
$$A = \begin{pmatrix}1 & 2 & -3\\2 & 4 & -5\\7 & 2 & -1\end{pmatrix}, \quad \mathbf{b} = \begin{pmatrix}1\\2\\3\end{pmatrix}, \quad A^{\#} = \left[\begin{array}{ccc|c}1 & 2 & -3 & 1\\2 & 4 & -5 & 2\\7 & 2 & -1 & 3\end{array}\right]$$
1Step 1: Identify the coefficient matrix
The coefficient matrix, \(A\), consists of the coefficients of the variables in
the system of linear equations.
In this case, the coefficients are the numbers next to \(x_1\), \(x_2,\) and \(x_3\):
$$A = \begin{pmatrix}1 & 2 & -3\\2 & 4 & -5\\7 & 2 & -1\end{pmatrix}$$
2Step 2: Identify the right-hand side vector
The right-hand side vector, \(\mathbf{b}\), consists of the constants on the
right-hand side of each equation. From the given system of equations, we
can see that the constants are:
$$\mathbf{b} = \begin{pmatrix}1\\2\\3\end{pmatrix}$$
3Step 3: Create the augmented matrix
To create the augmented matrix, \(A^{\#}\), we simply append the right-hand side
vector, \(\mathbf{b}\), to the coefficient matrix, \(A\). In this case, we join
the two matrices with a vertical line to separate them:
$$A^{\#} = \left[\begin{array}{ccc|c}1 & 2 & -3 & 1\\2 & 4 & -5 & 2\\7 & 2 & -1 & 3\end{array}\right]$$
Now, we have the coefficient matrix, \(A\), the right-hand side vector, \(\mathbf{b}\), and the augmented matrix, \(A^{\#}\), for the given system of linear equations.
Key Concepts
Coefficient MatrixRight-Hand Side VectorSystem of Linear Equations
Coefficient Matrix
When working with a system of linear equations, the coefficient matrix is a fundamental concept to grasp. It is essentially a compact way to represent the system's structure, focusing solely on the coefficients of the variables without bothering with the constants on the right-hand side of the equations.
For example, take the following system of equations:
For example, take the following system of equations:
- \(x_1 + 2x_2 - 3x_3 = 1\)
- \(2x_1 + 4x_2 - 5x_3 = 2\)
- \(7x_1 + 2x_2 - x_3 = 3\)
Right-Hand Side Vector
The right-hand side vector, denoted as \(\mathbf{b}\), complements the coefficient matrix by taking into account the constants that appear on the right-hand side of each equation in a system of linear equations. This vector embodies the targets or results that each equation wants to achieve.
In our existing example:
In our existing example:
- First equation's constant is \(1\)
- Second equation's constant is \(2\)
- Third equation's constant is \(3\)
System of Linear Equations
A system of linear equations consists of multiple linear equations that share the same set of variables. The overall goal is often to find the values of these variables that satisfy all equations simultaneously.
For example, consider this system:
To solve this, techniques such as substitution, elimination, or using matrices method - including the augmented matrix - often come in handy. The augmented matrix helps by compactly merging the coefficient matrix and the right-hand side vector into one single matrix:\[A^{\#}=\left[\begin{array}{ccc|c}1 & 2 & -3 & 1 \2 & 4 & -5 & 2 \7 & 2 & -1 & 3\end{array}\right]\]This format is particularly powerful in linear algebra as it facilitates various matrix operations like row reduction, simplifying the solution process for the system.
For example, consider this system:
- \(x_1 + 2x_2 - 3x_3 = 1\)
- \(2x_1 + 4x_2 - 5x_3 = 2\)
- \(7x_1 + 2x_2 - x_3 = 3\)
To solve this, techniques such as substitution, elimination, or using matrices method - including the augmented matrix - often come in handy. The augmented matrix helps by compactly merging the coefficient matrix and the right-hand side vector into one single matrix:\[A^{\#}=\left[\begin{array}{ccc|c}1 & 2 & -3 & 1 \2 & 4 & -5 & 2 \7 & 2 & -1 & 3\end{array}\right]\]This format is particularly powerful in linear algebra as it facilitates various matrix operations like row reduction, simplifying the solution process for the system.
Other exercises in this chapter
Problem 9
Express the matrix \(A\) as a product of elementary matrices. $$A=\left[\begin{array}{rr}3 & -4 \\\\-1 & 2\end{array}\right]$$
View solution Problem 9
use elementary row operations to reduce the given matrix to row-echelon form, and hence determine the rank of each matrix. $$\left[\begin{array}{rr} 2 & -4 \\ -
View solution Problem 9
Determine \(A^{-1},\) if possible, using the Gauss-Jordan method. If \(A^{-1}\) exists, check your answer by verifying that \(A A^{-1}=I_{n}\) $$A=\left[\begin{
View solution Problem 9
Use Gaussian elimination to determine the solution set to the given system. $$\begin{aligned} 2 x_{1}-x_{2}-4 x_{3} &=5 \\ 3 x_{1}+2 x_{2}-5 x_{3} &=8 \\ 5 x_{1
View solution