Problem 9
Question
Multiple Choice In a rectangular coordinate system, where does the point with polar coordinates \(\left(1,-\frac{\pi}{2}\right)\) lie? (a) in quadrant IV (b) on the \(y\) -axis (c) in quadrant II (d) on the \(x\) -axis
Step-by-Step Solution
Verified Answer
The point lies on the y-axis.
1Step 1: Understand polar coordinates
Polar coordinates represent a point in the plane using a distance from a reference point (the origin, usually denoted by \(r\)) and an angle \(\theta\) from a reference direction (the positive x-axis). The given polar coordinates are \(\left(1,-\frac{\pi}{2}\right)\), where \(r = 1\) and \(\theta = -\frac{\pi}{2}\).
2Step 2: Convert polar coordinates to rectangular coordinates
To find the Cartesian (rectangular) coordinates, use the formulas: \(x = r \cos(\theta)\) and \(y = r \sin(\theta)\). Substituting \(r = 1\) and \(\theta = -\frac{\pi}{2}\), we get: \(x = 1 \cos\left(-\frac{\pi}{2}\right)\) and \(y = 1 \sin\left(-\frac{\pi}{2}\right)\).
3Step 3: Evaluate the trigonometric functions
Evaluate the cosine and sine functions: \( \cos\left(-\frac{\pi}{2}\right) = 0\) and \( \sin\left(-\frac{\pi}{2}\right) = -1\). Thus, the rectangular coordinates are \( x = 1 \cdot 0 = 0 \) and \( y = 1 \cdot (-1) = -1 \).
4Step 4: Determine the location
The rectangular coordinates are \( (0, -1) \). Since \( x = 0 \), the point lies on the y-axis.
Key Concepts
rectangular coordinate systemcoordinate conversiontrigonometric functions
rectangular coordinate system
The rectangular coordinate system, also known as the Cartesian coordinate system, is a standard framework for locating points in a plane. It comprises two perpendicular axes: the x-axis (horizontal) and the y-axis (vertical).
A point in this system is denoted as \( (x, y) \) where 'x' is the horizontal distance from the origin, and 'y' is the vertical distance.
This system is divided into four quadrants:
A point in this system is denoted as \( (x, y) \) where 'x' is the horizontal distance from the origin, and 'y' is the vertical distance.
This system is divided into four quadrants:
- Quadrant I: Both x and y are positive
- Quadrant II: x is negative, y is positive
- Quadrant III: Both x and y are negative
- Quadrant IV: x is positive, y is negative
coordinate conversion
Coordinate conversion involves changing coordinates from one system to another. Here, we convert from polar to rectangular coordinates.
Polar coordinates use a radius (r) and an angle (θ). The radius represents the distance from the origin, while the angle determines the direction from the positive x-axis.
The formulas for converting polar coordinates \( (r, \theta) \) to rectangular coordinates \( (x, y) \) are:
Polar coordinates use a radius (r) and an angle (θ). The radius represents the distance from the origin, while the angle determines the direction from the positive x-axis.
The formulas for converting polar coordinates \( (r, \theta) \) to rectangular coordinates \( (x, y) \) are:
- \( x = r \cos(\theta) \)
- \( y = r \sin(\theta) \)
trigonometric functions
Trigonometric functions are essential for coordinating conversions. They link angles to the lengths of sides in right-angled triangles.
The primary trigonometric functions are sine (\text{sin}) and cosine (\text{cos}). For an angle \( \theta \):
The primary trigonometric functions are sine (\text{sin}) and cosine (\text{cos}). For an angle \( \theta \):
- \( \cos(\theta) \) gives the adjacent side's length over the hypotenuse.
- \( \sin(\theta) \) gives the opposite side's length over the hypotenuse.
Other exercises in this chapter
Problem 9
Every nonzero complex number has exactly _______ distinct complex cube roots.
View solution Problem 9
If \(\mathrm{v}\) is a vector with initial point \(\left(x_{1}, y_{1}\right)\) and terminal point \(\left(x_{2}, y_{2}\right),\) then which of the following is
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(a) find the dot product v \(\cdot \mathbf{w} ;\) (b) find the angle between \(\mathbf{v}\) and \(\mathbf{w} ;\) (c) state whether the vectors are parallel, ort
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If \(\mathbf{v}\) is a nonzero vector with direction angle \(\alpha, 0^{\circ} \leq \alpha
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