Problem 9
Question
Make a scatterplot of the data. Then find an exponential, logarithmic, or logistic function \(f\) that best models the data. $$\begin{array}{ccccccc} x & 0 & 1 & 2 & 3 & 4 & 5 \\ \hline y & 0.3 & 1.3 & 4.0 & 7.5 & 9.3 & 9.8\end{array}$$
Step-by-Step Solution
Verified Answer
Use a logistic function like \(f(x) = \frac{10}{1 + e^{-1.5(x-3)}}\) to model the data.
1Step 1: Plot the Data on a Scatterplot
First, we'll create a scatterplot using the given data points. The data points are: (0, 0.3), (1, 1.3), (2, 4.0), (3, 7.5), (4, 9.3), and (5, 9.8). Plot each \((x, y)\) pair on a graph with \(x\) values on the horizontal axis and \(y\) values on the vertical axis.
2Step 2: Determine the Type of Function
Examine the scatterplot to identify the type of function that might fit the data best. The \(y\) values start very small, increase rapidly, and then start to level off as \(x\) increases. This pattern suggests that we should try a logistic function to model the data.
3Step 3: Find a Logistic Function Model
A logistic function can be written in the form: \[ f(x) = \frac{L}{1 + e^{-k(x-x_0)}} \]where \(L\) is the maximum value the function approaches, \(k\) is the steepness, and \(x_0\) is the \(x\)-value of the midpoint. Use a software tool or a graphing calculator to fit a logistic function to the data. Based on the data behavior, start with initial guesses such as \(L \approx 10\), modify \(k\), and \(x_0\) until the function matches the data closely.
4Step 4: Refine the Model and Verify
Adjust the parameters \(L\), \(k\), and \(x_0\) iteratively until the logistic function accurately models the data points. After fitting, ensure the function shape closely matches the overall trend of the scatterplot. The final logistic function could look like:\[ f(x) = \frac{10}{1 + e^{-1.5(x-3)}} \]Check this against the plotted data to confirm accuracy.
Key Concepts
Logistic FunctionData ModelingGraph Interpretation
Logistic Function
A logistic function is particularly useful for modeling data that shows a rapid increase followed by leveling off. This type of function is characterized by an 'S' shaped curve, known as a sigmoid, which starts at a low value, rises sharply, and then tapers towards an upper limit or ceiling.
In our context, the logistic function is formulated as:
In our context, the logistic function is formulated as:
- \[f(x) = \frac{L}{1 + e^{-k(x-x_0)}}\]
- \( L \) is the asymptotic maximum value the curve approaches. It represents the ceiling or the saturation point of the data.
- \( k \) dictates the steepness of the curve and how quickly it grows or rises from the lower bound to the upper bound.
- \( x_0 \) is the x-value of the midpoint, marking where the curve transitions most dramatically.
Data Modeling
Modeling data involves creating a mathematical representation that approximates real-world data points. This process allows us to understand and predict behaviors within a dataset.
In the case of our exercise, the task is to select and apply a function type that closely represents the observed data. We have three options: exponential, logarithmic, or logistic functions. As identified, the logistic function suits our data best because:
In the case of our exercise, the task is to select and apply a function type that closely represents the observed data. We have three options: exponential, logarithmic, or logistic functions. As identified, the logistic function suits our data best because:
- The data displays an early rapid increase in value.
- This is followed by a tapering off which is characteristic of logistic behavior.
Graph Interpretation
Interpreting a graph involves analyzing the plotted data to discern patterns and trends. Graph interpretation helps us choose an appropriate function type to model the data, providing insights into the nature of the relationship between variables.
For instance, examining the scatterplot generated in the original exercise reveals a pattern typical of logistic growth:
For instance, examining the scatterplot generated in the original exercise reveals a pattern typical of logistic growth:
- The y-values start low and increase rapidly.
- As the x-values increase, the increment of y-values becomes smaller, indicating a leveling off.
Other exercises in this chapter
Problem 8
Simplify the expression without a calculator $$ \frac{95 \sqrt{6}}{9^{1 / 3}} $$
View solution Problem 8
Exercises \(7-10:\) Use \(f(x)\) and \(g(x)\) to evaluate each expression symbolically. \(f(x)=4 x-x^{3}, g(x)=x+3\) (a) \((g+g)(-2)\) (b) \((f-g)(0)\) (c) \((g
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Determine mentally an integer \(n\) so that the logarithm is between \(n\) and \(n+1 .\) Check your result with a calculator. (a) \(\log 79\) (b) \(\log 500\) (
View solution Problem 9
Simplify the expression without a calculator $$ e^{x} e^{x} $$
View solution