Problem 9
Question
Let \(X\) be a set and \(d, d^{\prime}\) be two metrics on \(X .\) Suppose there exists an \(\alpha>0\) and \(\beta>0\) such that \(\alpha d(x, y) \leq d^{\prime}(x, y) \leq \beta d(x, y)\) for all \(x, y \in X .\) Show that \(U\) is open in \((X, d)\) if and only if \(U\) is open in \(\left(X, d^{\prime}\right) .\) That is, the topologies of \((X, d)\) and \(\left(X, d^{\prime}\right)\) are the same.
Step-by-Step Solution
Verified Answer
The topologies of \((X, d)\) and \((X, d')\) are equivalent.
1Step 1: Understand the Definition of Open Set in Metric Space
A set \( U \) in a metric space \( (X, d) \) is open if for every \( x \in U \), there exists \( \epsilon > 0 \) such that the \( \epsilon \)-neighborhood \( B_d(x, \epsilon) = \{ y \in X : d(x, y) < \epsilon \} \) is contained in \( U \).
2Step 2: Show Direct Implication (Open in \((X, d)\) implies open in \((X, d')\))
Assume \( U \) is open in \((X, d)\). For each point \( x \in U \), there exists \( \epsilon > 0 \) such that \( B_d(x, \epsilon) \subseteq U \). Given the condition \( d'(x,y) \leq \beta \, d(x,y) \), we have \( B_d(x, \epsilon) \subseteq B_{d'} \left(x, \frac{\epsilon}{\beta} \right) \). Hence \( x \in B_{d'} \left(x, \frac{\epsilon}{\beta} \right) \subseteq U \), showing \( U \) is open in \((X, d')\).
3Step 3: Show Reverse Implication (Open in \((X, d')\) implies open in \((X, d)\))
Assume \( U \) is open in \((X, d')\). For each \( x \in U \), there exists \( \delta > 0 \) such that \( B_{d'}(x, \delta) \subseteq U \). The inequality \( d'(x,y) \geq \alpha \, d(x,y) \) gives \( B_{d'}(x, \delta) \subseteq B_d \left(x, \frac{\delta}{\alpha} \right) \). Thus \( x \in B_d \left(x, \frac{\delta}{\alpha} \right) \subseteq U \), showing \( U \) is open in \((X, d)\).
4Step 4: Conclude Equivalence of Topologies
Both implications show that if a set is open in one metric space, it is open in the other, so the open sets in \((X, d)\) are identical to the open sets in \((X, d')\). Hence, the topologies generated by the metrics \( d \) and \( d' \) are the same.
Key Concepts
TopologyOpen SetEquivalent MetricsReal Analysis
Topology
Topology is a concept in mathematics that helps describe how sets, shapes, and spaces are structured and how they relate to each other. In simpler terms, it deals with the 'shape' and 'size' of objects without regard to their exact structure. In a metric space, topology helps define what we refer to as 'open sets'.
For instance, in the real number line, open sets can be simple intervals like \( 1, 2 \) where the endpoints are not included. Topology is important because it describes the 'neighborhoods' around every point in a space, how these neighborhoods overlap, and the ways in which they interact.
For instance, in the real number line, open sets can be simple intervals like \( 1, 2 \) where the endpoints are not included. Topology is important because it describes the 'neighborhoods' around every point in a space, how these neighborhoods overlap, and the ways in which they interact.
- Topological properties include concepts like continuity, compactness, and connectedness.
- A topology determined by a metric is known as a metric topology.
Open Set
An open set is a core concept in topology, particularly when dealing with metric spaces. Simply put, an open set is a collection of points where, around every point, you can find a little 'buffer zone' that is entirely within the set.
This buffer zone is known as an \( \varepsilon\) neighborhood in metric spaces. Here is how it works:
This buffer zone is known as an \( \varepsilon\) neighborhood in metric spaces. Here is how it works:
- Pick any point \( x \) from the open set \( U \).
- There exists some distance \( \varepsilon > 0 \) such that all points within this distance from \( x \) are also inside \( U \).
Equivalent Metrics
Equivalent metrics arise when two different metrics on the same space define the exact same topology. In other words, the open sets under one metric are the same as the open sets under the other metric. This happens often when comparing different ways to measure distances in the same space.
To determine equivalent metrics, one check involves showing that each metric can 'sandwich' the distance measured by the other metric as expressed in inequalities:
To determine equivalent metrics, one check involves showing that each metric can 'sandwich' the distance measured by the other metric as expressed in inequalities:
- There exists an \( \alpha > 0 \) and \( \beta > 0 \) such that \( \alpha d(x, y) \leq d^{\prime}(x, y) \leq \beta d(x, y) \) for all points \( x, y \).
Real Analysis
Real analysis is a fundamental area of mathematics focusing primarily on the properties and behaviors of real numbers, sequences, and functions. It utilizes the precise definitions and logical proofs to investigate properties like limits, continuity, differentiability, and integrability.
Central to real analysis is the concept of limits and convergence, both of which rely heavily on understanding metric spaces and topology.
Central to real analysis is the concept of limits and convergence, both of which rely heavily on understanding metric spaces and topology.
- Utilizes concepts like open sets to define continuity and limits.
- Investigates how functions behave, ensuring they can reach desired levels of precision.
Other exercises in this chapter
Problem 8
Let \(\left(X, d_{X}\right)\) and \(\left(Y, d_{Y}\right)\) be metric space and \(f: X \rightarrow Y\) be a one-to-one and onto continuous function. Suppose \(X
View solution Problem 8
Let \((X, d)\) be a metric space. For nonempty bounded subsets \(A\) and \(B\) let $$ d(x, B):=\inf \\{d(x, b): b \in B\\} \quad \text { and } \quad d(A, B):=\s
View solution Problem 9
Let \(f(x):=x-\frac{x^{2}-2}{2 x}\) (you may recognize Newton's method for \(\sqrt{2}\) ). a) Prove \(f([1, \infty)) \subset[1, \infty) .\) b) Prove that \(f:[1
View solution Problem 9
Show that there exists a metric on \(\mathbb{R}\) that makes \(\mathbb{R}\) into a compact set.
View solution