Problem 9
Question
In the following examples quantities \(x\) and \(y\) are given. Interpret the role of change dy/dx in words. $$ y \text { is the height of water in a rain collecting column, } x \text { is time. } $$
Step-by-Step Solution
Verified Answer
The change \( \frac{dy}{dx} \) describes the rate at which the water height in the column changes over time.
1Step 1: Identify Variables
In this scenario, the variable \( y \) represents the height of the water in a rain-collecting column, and \( x \) represents time. So, we are looking at how the height of the water in the column changes over time.
2Step 2: Understand dy/dx
The notation \( \frac{dy}{dx} \) represents the rate of change of \( y \) with respect to \( x \). In words, this is the rate at which the height of the water in the rain-collecting column changes over time.
3Step 3: Interpret the Rate of Change
The rate of change \( \frac{dy}{dx} \) indicates how quickly or slowly the water level is rising or falling in the column. A positive \( \frac{dy}{dx} \) would mean the water level is increasing, while a negative \( \frac{dy}{dx} \) would indicate the water level is decreasing.
Key Concepts
Rate of ChangeDerivativesInterpreting dy/dx
Rate of Change
In calculus, the concept of "rate of change" is fundamental. It helps us understand how one quantity changes as another quantity changes. This idea is often visualized with the classic example of speed, where speed is the rate of change of distance over time. Similarly, in biological and environmental sciences, the rate of change can reflect how populations evolve, how chemicals react, or even how the water level rises in a rain column.
In our example, the rate of change focuses on how the water level increases or decreases with time. If it's raining heavily, the water level might rise quickly, meaning the rate of change is large. Conversely, if the rain is light or stops, the rate of change might be smaller or even negative, indicating the water is evaporating or draining away.
In our example, the rate of change focuses on how the water level increases or decreases with time. If it's raining heavily, the water level might rise quickly, meaning the rate of change is large. Conversely, if the rain is light or stops, the rate of change might be smaller or even negative, indicating the water is evaporating or draining away.
Derivatives
Derivatives are powerful tools in calculus that help us quantify the rate of change. Essentially, a derivative gives you the slope of a function at any given point, illustrating how fast or slow a variable is changing at that point.
In our rain column scenario, the derivative \( \frac{dy}{dx} \) tells us the "steepness" of the rise in water level as time progresses.
In our rain column scenario, the derivative \( \frac{dy}{dx} \) tells us the "steepness" of the rise in water level as time progresses.
- If the derivative is positive, the water level is climbing upwards.
- If it's zero, the water is steady, neither rising nor falling.
- A negative derivative indicates the water level is going down.
Interpreting dy/dx
The notation \( \frac{dy}{dx} \) might seem complex at first glance, but it's quite intuitive once broken down. The "\( dy \)" refers to a small change in the height of the water (\( y \)), and the "\( dx \)" refers to a small change in time (\( x \)).
Thus, \( \frac{dy}{dx} \) essentially measures how the height of water changes with every tiny tick of time. This helps in interpreting how the conditions are affecting the water level at any specific moment.
For example, if we calculate \( \frac{dy}{dx} \) and find it's positive on a rainy day, we know the water is rising due to rainfall. On a sunny day, if \( \frac{dy}{dx} \) turns negative, it tells us that the water is likely evaporating or draining faster than it's being replenished.
Thus, \( \frac{dy}{dx} \) essentially measures how the height of water changes with every tiny tick of time. This helps in interpreting how the conditions are affecting the water level at any specific moment.
For example, if we calculate \( \frac{dy}{dx} \) and find it's positive on a rainy day, we know the water is rising due to rainfall. On a sunny day, if \( \frac{dy}{dx} \) turns negative, it tells us that the water is likely evaporating or draining faster than it's being replenished.
Other exercises in this chapter
Problem 9
Differentiate the functions with respect to the independent variable. \(f(x)=x e^{x}\)
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Find the first and the second derivatives of each function. $$ g(t)=t^{-5 / 2}-t^{1 / 2} $$
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In Problems 9-11, find the lines that are (a) tangential and (b) normal to each curve at the given point. $$ x^{2}+y^{2}=25,(4,-3) \text { (circle) } $$
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