Problem 9
Question
In Exercises \(7-14,\) write out the first eight terms of each series to show how the series starts. Then find the sum of the series or show that it diverges. $$\sum_{n=1}^{\infty}\left(1-\frac{7}{4^{n}}\right)$$
Step-by-Step Solution
Verified Answer
The series diverges.
1Step 1: Understanding the Series
The series given is \( \sum_{n=1}^{\infty} \left(1 - \frac{7}{4^n}\right) \). This is an infinite series where each term is \(1 - \frac{7}{4^n}\). Our task is to write out the first eight terms and then determine if the series converges or diverges.
2Step 2: Writing the First Eight Terms
To find the first eight terms, substitute \(n = 1, 2, 3, ..., 8\) into the formula for the general term: - For \(n = 1\), the term is \(1 - \frac{7}{4} = 1 - 1.75 = -0.75\).- For \(n = 2\), the term is \(1 - \frac{7}{16} = 1 - 0.4375 = 0.5625\).- For \(n = 3\), the term is \(1 - \frac{7}{64} = 1 - 0.109375 = 0.890625\).- For \(n = 4\), the term is \(1 - \frac{7}{256} = 1 - 0.02734375 = 0.97265625\).- For \(n = 5\), the term is \(1 - \frac{7}{1024} = 1 - 0.0068359375 = 0.9931640625\).- For \(n = 6\), the term is \(1 - \frac{7}{4096} = 1 - 0.001708984375 = 0.998291015625\).- For \(n = 7\), the term is \(1 - \frac{7}{16384} = 1 - 0.00042724609375 = 0.99957275390625\).- For \(n = 8\), the term is \(1 - \frac{7}{65536} = 1 - 0.0001068115234375 = 0.9998931884765625\).
3Step 3: Observing the Pattern
From the first few terms, it is evident that each term is converging to 1 as \(n\) increases. This suggests that the series may converge towards a certain sum rather than diverge.
4Step 4: Analyzing the Series
The series can be split into two separate series: 1. \(\sum_{n=1}^{\infty} 1 = \infty\), which diverges.2. \(-\sum_{n=1}^{\infty} \frac{7}{4^n}\), which is a geometric series with first term \(-\frac{7}{4}\) and ratio \(\frac{1}{4}\).The term \(-\sum_{n=1}^{\infty} \frac{7}{4^n}\) is a convergent geometric series since \(|r| < 1\). This series sum can be calculated as the first term divided by \(1 - r\): \[-\sum_{n=1}^{\infty} \frac{7}{4^n} = \frac{-\frac{7}{4}}{1 - \frac{1}{4}} = \frac{-\frac{7}{4}}{\frac{3}{4}} = -\frac{7}{3}\].
5Step 5: Determining the Sum of the Series
Overall, the series \(\sum_{n=1}^{\infty}\left(1 - \frac{7}{4^n}\right)\) diverges because while the geometric series part \( -\frac{7}{4^n}\) converges to \(-\frac{7}{3}\), the constant term \(\sum_{n=1}^{\infty}1\) diverges to infinity. Thus, the entire series diverges.
Key Concepts
Infinite SeriesConvergence and DivergenceGeometric Series SumGeometric Series Ratio
Infinite Series
An infinite series is a sum of infinitely many terms. It is written in the form \( \sum_{n=1}^{\infty} a_n \), where each \( a_n \) is a term in the series. In simpler terms, it means adding together an infinite number of terms in a sequential manner. Infinite series are crucial in mathematics because they allow us to express complex ideas in a sum of simpler terms.
They come in many forms and can be either convergent or divergent. Understanding whether an infinite series converges or diverges plays a significant role in determining the behavior and value of the series.
They come in many forms and can be either convergent or divergent. Understanding whether an infinite series converges or diverges plays a significant role in determining the behavior and value of the series.
Convergence and Divergence
Convergence and divergence are key concepts when dealing with infinite series. A series converges if the sum of its terms approaches a specific, finite number as you continue to add more terms. Think of it as getting closer and closer to a particular value.
On the other hand, a series diverges if the sum does not approach any finite value. This could mean that the series grows without bounds or oscillates indefinitely without settling down.
On the other hand, a series diverges if the sum does not approach any finite value. This could mean that the series grows without bounds or oscillates indefinitely without settling down.
- A convergent series has a limit to which the terms of the series approach as they are added.
- A divergent series does not settle at a particular value or grows infinitely.
Geometric Series Sum
Geometric series are a specific type of series where each term is a constant multiple (called the ratio) of the previous term. A typical geometric series looks like \( a + ar + ar^2 + ar^3 + \ldots \), where \( a \) is the first term and \( r \) is the common ratio.
The sum of an infinite geometric series converges only when the absolute value of the ratio \(|r| < 1\). Otherwise, the series will diverge. The formula for the sum \( S \) of an infinite geometric series where \(|r| < 1\) is:\[S = \frac{a}{1 - r}\]If the series is convergent, this formula provides a simple way to calculate the sum of the series, making it very useful for problems involving geometric series.
The sum of an infinite geometric series converges only when the absolute value of the ratio \(|r| < 1\). Otherwise, the series will diverge. The formula for the sum \( S \) of an infinite geometric series where \(|r| < 1\) is:\[S = \frac{a}{1 - r}\]If the series is convergent, this formula provides a simple way to calculate the sum of the series, making it very useful for problems involving geometric series.
Geometric Series Ratio
In a geometric series, the ratio \( r \) is the factor by which each subsequent term is multiplied to get the next term in the series.
This ratio is critical for determining the behavior of the series. Whether a geometric series converges or diverges depends on this ratio:
This ratio is critical for determining the behavior of the series. Whether a geometric series converges or diverges depends on this ratio:
- If \(|r| < 1\), the series converges.
- If \(|r| \geq 1\), the series diverges.
Other exercises in this chapter
Problem 9
In Exercises \(1 - 14 ,\) determine if the alternating series converges or diverges. Some of the series do not satisfy the conditions of the Alternating Series
View solution Problem 9
Each of Exercises \(7-12\) gives the first term or two of a sequence along with a recursion formula for the remaining terms. Write out the first ten terms of th
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Find the Taylor polynomials of orders \(0,1,2,\) and 3 generated by \(f\) at \(a .\) \(f(x)=\sqrt{1-x}, \quad a=0\)
View solution Problem 10
Use substitution (as in Example 4) to find the Taylor series at \(x=0\) of the functions in Exercises \(1-12\) . $$\frac{1}{2-x}$$
View solution