Problem 9
Question
In Exercises \(1-20\), plot the graph of the polar equation by hand. Carefully label your graphs.In Exercises \(1-20\), plot the graph of the polar equation by hand. Carefully label your graphs. Cardioid: \(r=3-3 \cos (\theta)\)
Step-by-Step Solution
Verified Answer
Plot the graph as a cardioid that starts and ends at the origin, reaching its maximum distance at \(r=6\) for \(\theta = \pi\).
1Step 1: Understanding the Polar Equation
The given polar equation is \(r = 3 - 3 \cos(\theta)\). This is the equation of a cardioid, which is a type of limaçon. In this form, the parameter '3' outside the cosine function affects the distance, and '3' inside the cosine affects the shape and orientation of the cardioid.
2Step 2: Calculate Key Points
We begin by calculating values of \(r\) for key angles \(\theta\): 0, \(\frac{\pi}{2}\), \(\pi\), \(\frac{3\pi}{2}\), and 2\(\pi\). For \(\theta = 0\), \(r = 3 - 3\cos(0) = 0\). For \(\theta = \frac{\pi}{2}\), \(r = 3 - 3\cos\left(\frac{\pi}{2}\right) = 3\). For \(\theta = \pi\), \(r = 3 - 3\cos(\pi) = 6\). For \(\theta = \frac{3\pi}{2}\), \(r = 3 - 3\cos\left(\frac{3\pi}{2}\right) = 3\). For \(\theta = 2\pi\), \(r = 3 - 3\cos(2\pi) = 0\).
3Step 3: Plot the Calculated Points
On the polar grid, plot the points calculated: For \(\theta = 0\), place a point at the origin with \(r = 0\). For \(\theta = \frac{\pi}{2}\) and \(\theta = \frac{3\pi}{2}\), mark points at radius 3. For \(\theta = \pi\), place a point at \(r = 6\), on the opposite side of the pole from \(\theta = 0\).
4Step 4: Connect the Points with a Smooth Curve
Starting from the origin at \(\theta = 0\), draw a smooth curve through each of the calculated points. The curve should extend outwards to the maximum radius of \(6\) at \(\theta = \pi\) then loop back to meet the origin again at \(\theta = 2\pi\), forming a heart-shaped cardioid.
5Step 5: Label the Graph
Label your graph, indicating each key point you calculated as well as the axis (0, \(\frac{\pi}{2}\), \(\pi\), \(\frac{3\pi}{2}\), 2\(\pi\)). Ensure that your labels clearly show the orientation and key features of the cardioid.
Key Concepts
Understanding Cardioid in Polar CoordinatesExploring the Polar GridLimaçon Shapes and their Diversity
Understanding Cardioid in Polar Coordinates
A cardioid in polar coordinates is a fascinating shape resembling a heart or an apple. Its equation typically takes the form \( r = a + a \cos(\theta) \) or \( r = a + a \sin(\theta) \). In your exercise, the equation is \( r = 3 - 3 \cos(\theta) \), which is a specific type of cardioid derived from the general shape of a limaçon.
The characteristics of this cardioid include:
The characteristics of this cardioid include:
- The '3' outside the cosine term in the equation impacts the size of the cardioid. It defines the maximum extent of the curve.
- The negative sign before the cosine function results in symmetry about the x-axis, often creating a distinct loop or indentation in the shape.
- Cardioids can exhibit different shapes depending on whether cosine or sine functions are used, altering their orientation.
Exploring the Polar Grid
The polar grid is an essential tool when plotting polar equations like the cardioid. Unlike the Cartesian coordinate system, where points are determined by \(x\) and \(y\) values, the polar grid uses radius \(r\) and angle \(\theta\) to determine a point's position.
Here are some key points about the polar grid:
Here are some key points about the polar grid:
- The origin in polar coordinates, also called the pole, is where \(r = 0\).
- Angles are measured in radians from the polar axis, akin to the positive x-axis in Cartesian coordinates.
- The radius \(r\) indicates how far the point is from the pole.
- Points for different values of \(\theta\) reveal the path traced by a polar equation, aiding in visualizing complex curves like the cardioid.
Limaçon Shapes and their Diversity
Limaçons are part of a broader family of curves in polar coordinates, closely related to the cardioid. The general form of a limaçon is \( r = a + b \cos(\theta) \) or \( r = a + b \sin(\theta) \), where the cardioid is a special case when \( a = b \).
Here's what makes limaçons intriguing:
Here's what makes limaçons intriguing:
- Depending on the ratio between \( a \) and \( b \), limaçons can vary in shape considerably. They can have inner loops, look like circles, or even appear as distorted circles.
- If \( a = b \), the result is a cardioid, demonstrating the transitional phase between a standard limaçon and this distinct curve.
- When \( a < b \), limaçons develop inner loops, making their visual interpretation even more complex and fascinating.
Other exercises in this chapter
Problem 9
In Exercises \(1-20\), plot the set of parametric equations by hand. Be sure to indicate the orientation imparted on the curve by the parametrization. $$ \left\
View solution Problem 9
Use the given pair of vectors \(\vec{v}\) and \(\vec{w}\) to find the following quantities. State whether the result is a vector or a scalar. $$ \begin{array}{l
View solution Problem 9
Find a polar representation for the complex number \(z\) and then identify \(\operatorname{Re}(z)\), \(\operatorname{Im}(z),|z|, \arg (z)\) and \(\operatorname{
View solution Problem 9
Graph the following equations. $$ r=\frac{2}{1-\cos (\theta)} $$
View solution