Problem 9
Question
In each of Problems 1-20, a parametric representation of a curve is given. (a) Graph the curve. (b) Is the curve closed? Is it simple? (c) Obtain the Cartesian equation of the curve by eliminating the parameter (see Examples 1-4). $$ x=t^{3}-4 t, y=t^{2}-4 ;-3 \leq t \leq 3 $$
Step-by-Step Solution
Verified Answer
The curve is not closed and not simple. The Cartesian equation is \( x = (y+4)^{3/2} - 4(y+4)^{1/2} \) and \( x = -(y+4)^{3/2} + 4(y+4)^{1/2} \).
1Step 1: Understand the Parametric Equations
The given parametric equations are \( x = t^3 - 4t \) and \( y = t^2 - 4 \). The parameter \( t \) is ranging from \(-3\) to \(3\).
2Step 2: Determine the Range of Values
Calculate the values of \(x\) and \(y\) at the endpoints and determine how the curve behaves within the given range of \(t\). By substituting the values of \(t\) from \(-3\) to \(3\), generate several points to understand the path of the curve.
3Step 3: Graph the Curve
Using the points obtained by substituting the values of \(t\) into the parametric equations, plot these points on the Cartesian plane. Analyze the changes in the direction of the curve as \(t\) varies to sketch the path accurately.
4Step 4: Check for Closure and Simplicity
Determine whether the curve comes back to its starting point (closure) and whether it crosses itself (simplicity) by analyzing the graph. A curve is closed if it starts and ends at the same point, and it is simple if it doesn't intersect itself.
5Step 5: Eliminate the Parameter to Find the Cartesian Equation
To eliminate the parameter \(t\), express \(t\) in terms of \(y\) from the equation \( y = t^2 - 4 \), giving \( t = \pm \sqrt{y+4} \). Substitute this expression for \(t\) into the equation for \(x\): \[ x = (\pm \sqrt{y+4})^3 - 4(\pm \sqrt{y+4}). \]
6Step 6: Simplify the Cartesian Equation
From \( t = \pm \sqrt{y+4} \), the expression becomes:\( x = (y+4)^{3/2} - 4(y+4)^{1/2} \) and \( x = -(y+4)^{3/2} + 4(y+4)^{1/2} \). This gives the Cartesian equation of the curve in the implicit form.
Key Concepts
Curve SketchingCartesian EquationCurve ClosureCurve Simplicity
Curve Sketching
Curve sketching is a fundamental technique in mathematics to visualize the behavior of a given parametric equation. When dealing with parametric equations like \( x = t^3 - 4t \) and \( y = t^2 - 4 \), it's important to assess how the curve progresses as the parameter \( t \) changes.
To sketch the curve:
To sketch the curve:
- Start by substituting various values of \( t \) into both equations to generate points that lie on the curve.
- Use these points to plot the curve on a Cartesian plane.
- Observe how the curve moves as \( t \) transitions from \(-3\) to \(3\) to understand its full shape.
Cartesian Equation
A Cartesian equation represents a relationship between x and y in a standard form, free from any parameters. To transform parametric equations into Cartesian form, the process of eliminating the parameter \( t \) is used.
To eliminate the parameter:
To eliminate the parameter:
- Find \( t \) in terms of a single variable, typically using one of the parametric equations.
- For our example, starting with \( y = t^2 - 4 \), you solve for \( t \): \( t = \pm \sqrt{y + 4} \).
- Substitute this expression for \( t \) back into the equation for \( x \), forming \( x = (\pm \sqrt{y+4})^3 - 4(\pm \sqrt{y+4}) \).
Curve Closure
The concept of curve closure revolves around whether or not a curve will return to its starting point as it is traversed once. To verify closure in parametric equations:
- Check if the starting and ending values of the parameter result in identical points on the curve.
- For instance, when \( t = -3 \), calculate \( x \) and \( y \); then do the same for \( t = 3 \).
- Compare the points: if they are the same, the curve is closed; if not, the curve remains open.
Curve Simplicity
Curve simplicity examines if a curve intersects itself at any point. A simple curve differs from others by not intersecting itself. When evaluating simplicity:
- Observe the plotted curve for any crossings or overlaps.
- Simple curves will not revisit a point already plotted, except at their endpoints.
- For the parametric equations in question, visualize the curve using plotted points to identify any self-intersections.
Other exercises in this chapter
Problem 9
Sketch the graph of the given equation, indicating vertices, foci, and asymptotes. \(\frac{x^{2}}{16}+\frac{y^{2}}{4}=1\)
View solution Problem 9
Name the conic or limiting form represented by the given equation. Usually you will need to use the process of completing the square. $$ 3 x^{2}+3 y^{2}-6 x+12
View solution Problem 9
Find the standard equation of each parabola from the given information. Assume that the vertex is at the origin. Focus is at \((2,0)\)
View solution Problem 10
Find polar coordinates of the points whose Cartesian coordinates are given. (a) \((-3 / \sqrt{3}, 1 / \sqrt{3})\) (b) \((-\sqrt{3} / 2, \sqrt{3} / 2)\) (c) \((0
View solution