Problem 9
Question
Identify the conjugate acid-base pairs in the following equation. \(\mathrm{HNO}_{2}+\mathrm{H}_{2} \mathrm{O} \rightleftharpoons \mathrm{NO}_{2}^{-}+\mathrm{H}_{3} 0^{+}\)
Step-by-Step Solution
Verified Answer
The conjugate acid-base pairs in the given equation are:
1. HNO₂ (acid) and NO₂⁻ (conjugate base)
2. H₂O (base) and H₃O⁺ (conjugate acid)
1Step 1: Identify the Initial Acid and Base
The equation given is:
\(\mathrm{HNO}_{2}+\mathrm{H}_{2}\mathrm{O} \rightleftharpoons \mathrm{NO}_{2}^{-}+\mathrm{H}_{3}\mathrm{O}^{+}\)
Here, the HNO₂ is donating an H+ to H₂O (which accepts it). So, the initial acid is HNO₂ and the initial base is H₂O.
2Step 2: Identify the Conjugate Acid and Base
After donating a proton, HNO₂ now becomes a base (conjugate base). It forms NO₂⁻, which is without the H+ it initially had. So, the conjugate base to HNO₂ is NO₂⁻.
After accepting a proton from HNO₂, H₂O becomes an acid (conjugate acid) and is now called H₃O⁺ (the extra proton added a positive charge). So, the conjugate acid to H₂O is H₃O⁺.
3Step 3: Write Down the Conjugate Acid-Base Pairs
We have found both the conjugate acid-base pairs, and they are as follows:
1. The conjugate acid-base pair of HNO₂ (acid) is HNO₂/NO₂⁻ (conjugate base).
2. The conjugate acid-base pair of H₂O (base) is H₂O/H₃O⁺ (conjugate acid).
Key Concepts
Bronsted-Lowry TheoryAcid-Base ReactionsChemistry Education
Bronsted-Lowry Theory
The Bronsted-Lowry Theory is a fundamental part of understanding acid-base chemistry. According to this theory, an acid is a substance that donates a proton (H^+), and a base is a substance that accepts a proton. This is a broader definition compared to other theories, which offers more flexibility in classifying substances.
For example, in the reaction provided:
For example, in the reaction provided:
- \(\text{HNO}_2\) is the acid because it donates a proton to \(\text{H}_2O\).
- Water (\(\text{H}_2O\)) acts as a base because it accepts the proton from \(\text{HNO}_2\).
Acid-Base Reactions
Acid-base reactions are essential chemical reactions occurring all around us. These reactions involve the transfer of protons from acids to bases, forming conjugate acid-base pairs.
Let's break down the given equation:
Let's break down the given equation:
- The initial acid, \(\text{HNO}_2\), donates a proton, becoming \(\text{NO}_2^-\), its conjugate base.
- The initial base, \(\text{H}_2O\), accepts a proton, transforming into \(\text{H}_3O^+\), its conjugate acid.
Chemistry Education
Chemistry education focuses on making complex concepts like acid-base reactions accessible to students. By exploring real-world examples and interactive exercises, students deepen their understanding of underlying principles.
To engage with the topic better:
To engage with the topic better:
- Visual aids, like molecular diagrams, can illustrate how acids and bases interact.
- Practice problems enhance problem-solving skills by applying theoretical knowledge to practical scenarios.
- Group discussions encourage diverse perspectives and collaborative learning.
Other exercises in this chapter
Problem 7
Explain how the concentrations of hydrogen ions and hydroxide ions determine whether a solution is acidic, basic, or neutral.
View solution Problem 8
Explain why many compounds that contain one or more hydrogen atoms are not classified as Arrhenius acid.
View solution Problem 10
Write the Lewis structure for phosphorus trichoride \((\mathrm{PC} / 3) .\) Is \(\mathrm{PCl}_{3}\) a lewis acid, a Lewis base, or neither?
View solution Problem 12
Write ionization equations and acid ionization constant expressions for a. \(\mathrm{HClO}_{2} \quad\) b. HNO_ \(_{2} \quad\) c. HIOeach acid.
View solution