Problem 9
Question
Hydrochloric acid is sold as a concentrated aqueous solution. If the molarity of commercial HCl is 12.0 and its density is \(1.18 \mathrm{g} / \mathrm{cm}^{3},\) calculate the following: (a) the molality of the solution (b) the weight percent of HCl in the solution
Step-by-Step Solution
Verified Answer
(a) Molality is 16.16 m; (b) Weight percent is 37.08%.
1Step 1: Understand the Given Information
We are given the molarity of the HCl solution as 12.0 M and the density of the solution as 1.18 g/cm³. We need to calculate the molality and the weight percent of HCl in the solution.
2Step 2: Calculate the Total Mass of the Solution
First, we need to find the mass of 1 liter (1000 mL) of the solution, using the density. \[ \text{Mass of solution} = \text{Volume} \times \text{Density} = 1000 \text{ mL} \times 1.18 \text{ g/mL} = 1180 \text{ g} \].
3Step 3: Calculate the Moles of HCl
Using the molarity and volume, find the number of moles of HCl in 1 liter of solution. \[ \text{Moles of HCl} = 12.0 \text{ mol/L} \times 1 \text{ L} = 12.0 \text{ moles} \].
4Step 4: Calculate the Mass of HCl
Use the molar mass of HCl (approximately 36.46 g/mol) to find the mass of HCl. \[ \text{Mass of HCl} = 12.0 \text{ moles} \times 36.46 \text{ g/mol} = 437.52 \text{ g} \].
5Step 5: Calculate the Mass of Water in the Solution
Subtract the mass of HCl from the total mass of the solution to find the mass of water. \[ \text{Mass of water} = 1180 \text{ g} - 437.52 \text{ g} = 742.48 \text{ g} \].
6Step 6: Calculate the Molality of the Solution
Molality is defined as moles of solute per kilogram of solvent. Convert the mass of water to kilograms, then calculate molality. \[ \text{Molality} (m) = \frac{12.0 \text{ moles}}{0.74248 \text{ kg}} = 16.16 \text{ m} \].
7Step 7: Calculate the Weight Percent of HCl
Weight percent is the mass of the solute divided by the total mass of the solution, multiplied by 100. \[ \text{Weight percent} = \left(\frac{437.52 \text{ g}}{1180 \text{ g}}\right) \times 100 = 37.08\% \].
Key Concepts
MolarityMolalityWeight PercentDensityHCl Solutions
Molarity
Molarity is an important concept in chemistry that refers to the concentration of a solute in a solution. It's defined as the number of moles of solute per liter of solution. The formula is:
- Molarity (M) = moles of solute / liters of solution
Molality
Molality, unlike molarity, is a measure of the concentration based not on the volume of the solution but on the mass of the solvent. It is expressed in moles of solute per kilogram of solvent. The formula is:
- Molality (m) = moles of solute / kilograms of solvent
Weight Percent
Weight percent, often expressed as percentage by mass, refers to the ratio of the mass of a component to the total mass of the mixture, multiplied by 100. It's a unit commonly used in chemistry to express concentration and purity. The formula is:
- Weight percent = (mass of solute / mass of solution) × 100
Density
Density is a measure of how much mass is contained in a given volume and is expressed as grams per cubic centimeter (g/cm³) or grams per milliliter (g/mL) in the context of solutions. The formula to calculate density is:
- Density = mass / volume
HCl Solutions
Hydrochloric acid (HCl) is a common aqueous solution in labs, known for its strong acidic properties. Solutions of HCl vary in concentration, where commercial solutions are typically highly concentrated. These concentrations can be described in terms of molarity or weight percent, offering flexibility to chemists depending on the usage scenario.
Commercial HCl solutions, like the one in our example with 12.0 M molarity, are used for industrial cleaning, pH control, and manufacturing of organic compounds. Safety is a big concern when handling HCl due to its corrosive nature; proper precautions and equipment are necessary. Understanding the concentration terms like molarity, molality, and weight percent aids in handling, storage, and application of HCl solutions safely and effectively.
Other exercises in this chapter
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