Problem 9
Question
For the following exercises, find the \(x\) - or t-intercepts of the polynomial functions. $$ C(t)=2 t(t-3)(t+1)^{2} $$
Step-by-Step Solution
Verified Answer
The t-intercepts are \( t = 0 \), \( t = -1 \), and \( t = 3 \).
1Step 1: Understand the Problem
We need to find the t-intercepts of the function \( C(t) = 2t(t-3)(t+1)^2 \). The t-intercepts occur where \( C(t) = 0 \).
2Step 2: Set the Function to Zero
To find the t-intercepts, set the polynomial function equal to zero: \( 2t(t-3)(t+1)^2 = 0 \).
3Step 3: Solve for Each Factor
Since the equation is a product of factors equal to zero, we apply the zero-product property. Set each factor equal to zero: \( 2t = 0 \), \( t-3 = 0 \), and \( (t+1)^2 = 0 \).
4Step 4: Solve Each Equation
Solve each equation separately: \( 2t = 0 \) gives \( t = 0 \); \( t-3 = 0 \) gives \( t = 3 \); \( (t+1)^2 = 0 \) gives \( t = -1 \).
5Step 5: Identify the t-intercepts
The t-intercepts are the solutions to the equations. Therefore, the t-intercepts are \( t = 0 \), \( t = -1 \), and \( t = 3 \).
Key Concepts
t-interceptsZero-Product PropertySolve Polynomial Equations
t-intercepts
The concept of t-intercepts in polynomial functions relates to the points where the graph of the function crosses the t-axis. These are the values of \( t \) for which the polynomial is equal to zero. In our original exercise, the goal is to identify the t-intercepts of a polynomial function given by \( C(t) = 2t(t-3)(t+1)^2 \). To find these intercepts, you need to solve for \( t \) whenever \( C(t) = 0 \).
- t-intercepts are the solutions to the equation \( C(t) = 0 \).
- They represent the horizontal points where the graph meets the t-axis.
- For the function \( C(t) = 2t(t-3)(t+1)^2 \), setting \( C(t) = 0 \) initiates the process of finding these intercepts.
Zero-Product Property
The Zero-Product Property is a fundamental concept in algebra, which is critical for solving polynomial equations that have been factored into products of smaller expressions. It states that if a product of two or more factors is zero, then at least one of the factors must also be zero.
- This property allows us to solve equations like \( 2t(t-3)(t+1)^2 = 0 \) by splitting it into smaller equations: \( 2t = 0 \), \( t-3 = 0 \), \( (t+1)^2 = 0 \).
- By applying this property, you can solve for each factor individually to find possible solutions for \( t \).
Solve Polynomial Equations
Solving polynomial equations involves finding the values of \( t \) that satisfy the equation, typically by setting the polynomial equal to zero. In the case of our exercise, this involves using both the Zero-Product Property and factoring.
- First, represent the equation in factored form, like \( C(t) = 2t(t-3)(t+1)^2 \).
- Set \( C(t) = 0 \) and apply the Zero-Product Property to determine each factor.
- The factors are solved individually: \( 2t = 0 \) leads to \( t = 0 \), \( t-3 = 0 \) gives \( t = 3 \), and \( (t+1)^2 = 0 \) results in \( t = -1 \).
- These solutions are your t-intercepts.
Other exercises in this chapter
Problem 9
For the following exercises, use the Remainder Theorem to find the remainder. $$ \left(-3 x^{2}+6 x+24\right) \div(x-4) $$
View solution Problem 9
For the following exercises, use long division to divide. Specify the quotient and the remainder. $$ \left(2 x^{2}-3 x+2\right) \div(x+2) $$
View solution Problem 9
For the following exercises, identify the function as a power function, a polynomial function, or neither. $$ f(x)=\frac{x^{2}}{x^{2}-1} $$
View solution Problem 9
For the following exercises, rewrite the quadratic functions in standard form and give the vertex. $$ f(x)=x^{2}+5 x-2 $$
View solution