Problem 9
Question
For the following exercises, determine which conic section is represented based on the given equation. \(4 x^{2}-y^{2}+8 x-1=0\)
Step-by-Step Solution
Verified Answer
The equation represents a hyperbola.
1Step 1: Rearrange the Equation
Given the equation is \(4x^{2} - y^{2} + 8x - 1 = 0\). We will rearrange it to group the \(x\) terms together and move the constant to the other side: \(4x^{2} + 8x - y^{2} = 1\).
2Step 2: Identify the Standard Form
The equation resembles the general form of a conic section, which is either an ellipse, hyperbola, or parabola. When rearranging, we need to figure out whether the coefficients of \(x^2\) and \(y^2\) have opposite signs, which indicates it's a hyperbola.
3Step 3: Recognize Coefficients and Signs
In the rearranged equation \(4x^{2} + 8x - y^{2} = 1\): The coefficient of \(x^2\) is \(4\) and \(y^2\) is \(-1\). Since one is positive and the other is negative, this indicates a hyperbola.
Key Concepts
HyperbolaEquations of Conic SectionsStandard Form of Conics
Hyperbola
A hyperbola is one of the four types of conic sections, and it has unique features that differentiate it from other conics like circles, ellipses, and parabolas. The defining property of a hyperbola is that the differences in distances from any point on the curve to two fixed points (the foci) are constant.
Its shape resembles two open curves, or branches, facing away from each other, and it can have either horizontal or vertical orientations.
Here's what's interesting about hyperbolas:
- There are always two branches in a hyperbola.
- Hyperbolas have two axes of symmetry, which are two lines that divide the figure into mirror-image halves.
- The vertices of a hyperbola are the points where the branches come closest to each other.
Equations of Conic Sections
Conic sections can be described using different types of equations, highlighting their geometric properties. The main types of conic sections are the circle, ellipse, parabola, and hyperbola. Each has equations that define its specific form and characteristics.Key features of conic section equations include:
- Circles: The equation has the general form \((x-h)^2 + (y-k)^2 = r^2\), where \( (h, k) \) is the center and \( r \) is the radius.
- Ellipses: Similar to circles but with different radii, expressed with \(\frac{(x-h)^2}{a^2} + \frac{(y-k)^2}{b^2} = 1 \).
- Hyperbolas: Have the form \(\frac{(x-h)^2}{a^2} - \frac{(y-k)^2}{b^2} = 1 \) or \(\frac{(y-k)^2}{b^2} - \frac{(x-h)^2}{a^2} = 1 \), characterized by having opposite signs compared to ellipses.
- Parabolas: Generally represented by \((y-k) = a(x-h)^2\) or \((x-h) = a(y-k)^2\), indicating a single curved path.
Standard Form of Conics
The standard form of conic sections provides a simplified and structured way of expressing conic equations, which helps in identifying and graphing the type of conic section. These forms are derived from the general quadratic equation in two variables:\[ Ax^2 + Bxy + Cy^2 + Dx + Ey + F = 0 \]In the case of a hyperbola, breaking down the general quadratic equation into a standard form makes it easy to comprehend its geometry:
- The standard form for a
- horizontal hyperbola: \(\frac{(x-h)^2}{a^2} - \frac{(y-k)^2}{b^2} = 1\)
- vertical hyperbola: \(\frac{(y-k)^2}{b^2} - \frac{(x-h)^2}{a^2} = 1\)
- For hyperbolas, distinguish between horizontal and vertical based on the placement and sign of terms.
- Completing the square is often used to rearrange conic equations into a more recognizable standard form.
Other exercises in this chapter
Problem 8
For the following exercises, determine whether the given equation is a parabola. If so, rewrite the equation in standard form. \(3 x^{2}-6 y^{2}=12\)
View solution Problem 9
For the following exercises, identify the conic with a focus at the origin, and then give the directrix and eccentricity. \(r=\frac{5}{1+2 \sin \theta}\)
View solution Problem 9
For the following exercises, determine whether the given equation is a parabola. If so, rewrite the equation in standard form. \((y-3)^{2}=8(x-2)\)
View solution Problem 10
For the following exercises, identify the conic with a focus at the origin, and then give the directrix and eccentricity. \(r=\frac{16}{4+3 \quad \cos \theta}\)
View solution