Problem 9
Question
Find the \(x\) -intercept and the \(y\) -intercept of the graph of the equation. Graph the equation. $$ y=x+2 $$
Step-by-Step Solution
Verified Answer
The \(x\)-intercept is -2 and the \(y\)-intercept is 2.
1Step 1: Finding the \(x\)-intercept
To find the \(x\)-intercept, set \(y=0\) in the equation and solve for \(x\). Plugging \(y=0\) into the equation \(y=x+2\), we get \(0=x+2\). Solving for \(x\) gives \(x=-2\). So the \(x\)-intercept is -2.
2Step 2: Finding the \(y\)-intercept
To find the \(y\)-intercept, set \(x=0\) in the equation and solve for \(y\). Plugging \(x=0\) into the equation \(y=x+2\), we get \(y=0+2\). Simplifying this gives \(y=2\). So the \(y\)-intercept is 2.
3Step 3: Graphing the equation
To graph the equation \(y=x+2\), we can use the intercepts found in previous steps. We plot the \(x\)-intercept at (-2, 0) and the \(y\)-intercept at (0, 2), then draw a straight line through these two points. These two points are enough to define the line since it is a linear equation.
Other exercises in this chapter
Problem 9
Graph the equation. \(y=x\)
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Plot the points and draw the line that passes through them. Without finding the slope, determine whether the slope is positive, negative, zero, or undefined. $$
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Rewrite the equation in function form. $$ 4 x+2+2 y=10 $$
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Complete the statement with always, sometimes, or never. A point plotted on the \(x\) -axis ? has \(y\) -coordinate \(0 .\)
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