Problem 9
Question
Find the slope of the tangent line to each curve when \(x\) has the given value. Do not use a calculator. $$f(x)=-\frac{2}{x} ; x=4$$
Step-by-Step Solution
Verified Answer
The slope of the tangent line at \( x = 4 \) is \( \frac{1}{8} \).
1Step 1: Understand the problem
We need to find the slope of the tangent line to the curve defined by the function \( f(x) = -\frac{2}{x} \) at the point where \( x = 4 \). The slope of the tangent line is given by the derivative of the function evaluated at this specific point.
2Step 2: Differentiate the function
Find the derivative of \( f(x) = -\frac{2}{x} \). To do this, we rewrite the function as \( f(x) = -2x^{-1} \). Use the power rule for differentiation, which is \( \frac{d}{dx} (x^n) = nx^{n-1} \). Therefore, the derivative \( f'(x) \) is calculated as follows:\[ f'(x) = -2(-1)x^{-1-1} = 2x^{-2} \].Thus, \( f'(x) = \frac{2}{x^2} \).
3Step 3: Evaluate the derivative at the given point
Now that we have \( f'(x) = \frac{2}{x^2} \), substitute \( x = 4 \) into this expression to find the slope of the tangent line at this point:\[ f'(4) = \frac{2}{(4)^2} = \frac{2}{16} = \frac{1}{8} \].
Key Concepts
DerivativeSlope of tangent linePower rule
Derivative
In calculus, the derivative is a fundamental concept that represents the rate at which a function is changing at any given point. It is like a real-world measurement of change. Imagine you are driving a car, the derivative would be analogous to the speedometer which tells you how fast you are changing your position.
When you differentiate a function, you find a new function known as the derivative. This derivative function gives you the slope of the tangent line at any point on the original function's curve. It is crucial in understanding how the function behaves.
To compute the derivative, differentiation rules such as the power rule, chain rule, and product rule are applied. In this exercise, we applied the power rule to derive the derivative of the function, making it easier to predict the slope of the curve at given points.
Slope of tangent line
The slope of a tangent line at a particular point on a curve gives information about the curve's direction and steepness at that point. It helps us understand how the function behaves in a small interval around that point.A tangent line is a straight line that touches a curve at a single point without crossing it. This line represents the instantaneous rate of change of the function at that specific point. In this exercise, you were asked to find the slope of the tangent line for the function at a specific value of \(x\). By evaluating the derivative at \(x = 4\), the slope was determined to be \(\frac{1}{8}\). This means that at the point \(x = 4\), the line that best approximates the function has a gentle upwards slope.
Power rule
The power rule is one of the most straightforward and commonly used rules in differential calculus. It deals with finding the derivative of polynomials. The rule can be stated as follows:
- If \(f(x) = x^n\), then \(f'(x) = nx^{n-1}\).
Other exercises in this chapter
Problem 8
Determine each limit. Refer to the accompanying graph of \(y=f(x)\) when it is given. Do not use a calculator. $$\lim _{x \rightarrow-4^{-}} x^{3}$$
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Let \(\lim _{x \rightarrow 4} f(x)=16\) and \(\lim _{x \rightarrow 4} g(x)=8 .\) Use the limit rules to find each limit. Do not use a calculator. $$\lim _{x \ri
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Determine each limit. Refer to the accompanying graph of \(y=f(x)\) when it is given. Do not use a calculator. $$\lim _{x \rightarrow 7^{-}} 100$$
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