Problem 9
Question
Find the middle term in the binomial expansion of each. $$\left(x+\frac{1}{x}\right)^{4}$$
Step-by-Step Solution
Verified Answer
The middle term of the binomial expansion of \(\left(x+\frac{1}{x}\right)^{4}\) is 6.
1Step 1: Identify a, b, and n.
In this problem, \(a = x\), \(b = \frac{1}{x}\), and \(n = 4\).
2Step 2: Find the middle term using the binomial theorem.
Since we have four terms in our expansion, the middle term is the third term. Therefore, we need to find the \(r = 3\) term. According to the binomial theorem, this term is:
\(\binom{n}{r-1}a^{n-r+1}b^{r-1} = \binom{4}{3-1}x^{4-3+1}\left(\frac{1}{x}\right)^{3-1}\)
3Step 3: Compute the binomial coefficient.
Using the formula for the binomial coefficient, we can compute \(\binom{4}{2}\) as follows:
\(\binom{4}{2} = \frac{4!}{2!(4-2)!} = \frac{4!}{2!2!} = \frac{4 \times 3 \times 2 \times 1}{(2\times 1)(2 \times 1)} = \frac{24}{4} = 6\)
4Step 4: Substitute the binomial coefficient and simplify the term.
Now that we have found the binomial coefficient, we can substitute it into our expression and simplify the term:
\(6x^{2}\left(\frac{1}{x}\right)^2 = 6x^{2}\frac{1}{x^2} = 6\frac{x^2}{x^2} = 6\)
5Step 5: Write the final answer.
The middle term of the binomial expansion of \(\left(x+\frac{1}{x}\right)^{4}\) is 6.
Key Concepts
Binomial CoefficientBinomial TheoremMiddle Term in Expansion
Binomial Coefficient
The binomial coefficient is an essential part of the binomial theorem and is represented as \( \binom{n}{r} \), which is read as "\( n \) choose \( r \)." This number determines how many ways you can combine \( n \) items taken \( r \) at a time, regardless of order. It is given by the formula:
\[\binom{n}{r} = \frac{n!}{r!(n-r)!}\]
where \( n! \) ("\( n \) factorial") is the product of all positive integers up to \( n \), and \( r! \) is the product of all positive integers up to \( r \).
Quick Points about Binomial Coefficients:
\[\binom{n}{r} = \frac{n!}{r!(n-r)!}\]
where \( n! \) ("\( n \) factorial") is the product of all positive integers up to \( n \), and \( r! \) is the product of all positive integers up to \( r \).
Quick Points about Binomial Coefficients:
- The coefficient is always a whole number.
- It can be visualized using Pascal's Triangle, where each number is the sum of the two numbers directly above it.
- When \( r = 0 \) or \( r = n \), \( \binom{n}{r} = 1 \).
Binomial Theorem
The Binomial Theorem provides a powerful way to expand expressions of the form \( (a + b)^n \). According to the theorem, the expansion is expressed as a sum of terms of the form:\[\binom{n}{r} a^{n-r} b^r\]This concise expression tells us to combine the coefficients (binomial coefficients), the powers of \( a \), and the powers of \( b \), creating every possible product. Each term in the expansion will have a unique power of \( a \) and \( b \) that adds up to \( n \).
Important Features of the Binomial Theorem:
Important Features of the Binomial Theorem:
- There are \( n + 1 \) terms in the expansion of \( (a + b)^n \).
- The powers of \( a \) decrease from \( n \) to 0, while the powers of \( b \) increase from 0 to \( n \).
- The coefficients for the terms can be found using binomial coefficients.
Middle Term in Expansion
Finding the middle term in a binomial expansion can be straightforward when \( n \), the exponent in \( (a + b)^n \), is even. The middle term(s) is generally found by looking at term \( T \), where \( T_{r+1} \) corresponds to the number of terms divided by 2 plus one for expansions with an odd number of terms or just \( n/2 \) for even \( n \).
For example:
For example:
- When \( n = 4 \) (as in our exercise), the total number of terms is 5, so the middle term is the third one, \( T_3 \).
- This term can be calculated using the formula from the binomial theorem discussed earlier: \( \binom{4}{2} x^{2} \left(\frac{1}{x}\right)^2 \).
Other exercises in this chapter
Problem 8
Two dice are rolled. Find the probability of obtaining: A sum less than five.
View solution Problem 9
Using the alternate inclusion-exclusion formula, find the number of primes not exceeding: 125
View solution Problem 9
Find the number of ternary words over the alphabet \\{0,1,2\\} that are of length four and: Contain exactly three 0 's.
View solution Problem 9
Solve the recurrence relation \(d_{n}=-d_{n-1}, n \geq 2,\) where \(d_{1}=-1\).
View solution