Problem 9
Question
Find the domain and range of the given functions. $$f(s)=\frac{2}{s^{2}}$$
Step-by-Step Solution
Verified Answer
Domain: \((-1e, 0) \cup (0, 1e)\), Range: \((0, 1e)\).
1Step 1: Identify Values That Make the Denominator Zero
The function is undefined where the denominator is zero, as division by zero is not possible. The denominator here is \(s^2\). Set it to zero and solve for \(s\): \(s^2 = 0\). This gives \(s = 0\).
2Step 2: Establish the Domain of the Function
The domain of \(f(s) = \frac{2}{s^2}\) includes all real numbers except where the function is undefined. From Step 1, \(s = 0\) causes the denominator to be zero. Therefore, the domain is all real numbers except zero, or \((-1e, 0) \cup (0, 1e)\).
3Step 3: Identify the Range of the Function
The range of \(f(s)\) is determined by the possible output values \(f(s)\) can produce. Since \(f(s) = \frac{2}{s^2}\), as \(s^2\) becomes very large or very small, \(f(s)\) approaches zero. However, \(f(s)\) is never zero because \(2/s^2\) is always positive, making the range \((0, 1e)\).
Key Concepts
Denominator ZeroReal NumbersUndefined Function
Denominator Zero
When a denominator in a function equals zero, it causes the function to become undefined at that particular point. This is because division by zero is mathematically impossible and leads to an operation that doesn’t yield a real number result. To resolve functions like these, it is essential to identify values that make the denominator zero and exclude them from the domain.
In the function given, \(f(s) = \frac{2}{s^2}\), the denominator is \(s^2\). Setting \(s^2 = 0\) and solving for \(s\) gives \(s = 0\).
In the function given, \(f(s) = \frac{2}{s^2}\), the denominator is \(s^2\). Setting \(s^2 = 0\) and solving for \(s\) gives \(s = 0\).
- This means that when \(s\) is zero, the denominator is zero and the function is undefined.
- Thus, the value \(s = 0\) must be excluded from the domain of the function.
Real Numbers
Real numbers include all possible numbers along the continuous number line, without any gaps. They incorporate both rational numbers (like integers and fractions) and irrational numbers (like the square root of non-square-perfects).
In the context of function domains, a real number set refers to all numbers excluding the ones that cause issues such as making a denominator zero. For the function \(f(s) = \frac{2}{s^2}\), since \(s = 0\) is not allowed, the domain is all real numbers except zero.
In the context of function domains, a real number set refers to all numbers excluding the ones that cause issues such as making a denominator zero. For the function \(f(s) = \frac{2}{s^2}\), since \(s = 0\) is not allowed, the domain is all real numbers except zero.
- This is expressed as: \((- \infty, 0) \cup (0, \infty)\).
- It means the domain doesn't include zero but includes every other real number.
Undefined Function
A function becomes undefined in situations where typical mathematical operations cannot be performed. One common cause of an undefined function is when attempting to divide by zero.
For \(f(s) = \frac{2}{s^2}\), the denominator \(s^2\) becomes zero when \(s = 0\), hence making the function undefined at this point. The solution involves removing such points where the function is undefined from its domain.
For \(f(s) = \frac{2}{s^2}\), the denominator \(s^2\) becomes zero when \(s = 0\), hence making the function undefined at this point. The solution involves removing such points where the function is undefined from its domain.
- However, excluding these points ensures that the function remains valid wherever it is defined.
- Even though the function is undefined at certain points, the range of the function might still span a continuous set depending on how the function behaves elsewhere.
- For example, \(f(s)\) produces values that are always positive when \(s eq 0\), making the range \((0, \infty)\).
Other exercises in this chapter
Problem 9
Plot the given points and then join these points, in the order given, by straight-line segments. Name the geometric figure formed. $$A(-2,-1), B(3,-1), C(3,5),
View solution Problem 9
In Exercises \(5-36,\) graph the given functions. $$s=7-2 t$$
View solution Problem 9
Find the domain and range of the given functions. In Exercises 11 and \(12,\) explain your answers. $$f(s)=\frac{2}{s^{2}}$$
View solution Problem 10
Graph the given functions. $$y=-3$$
View solution