Problem 9
Question
Find the distance between each pair of points. If necessary, round answers to two decimals places. $$(0,-3)\( and \)(4,1)$$
Step-by-Step Solution
Verified Answer
The distance between the points (0, -3) and (4, 1) is approximately 5.66 units.
1Step 1: Identify the Coordinates
Identify and label the coordinates of the two points. Here, (x1, y1) = (0, -3) and (x2, y2) = (4, 1).
2Step 2: Apply Distance Formula
Apply the distance formula \(d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}\) by replacing x1, y1, x2, and y2 with the coordinates identified in step 1. The result is \(d = \sqrt{(4 - 0)^2 + (1 - (-3))^2}\).
3Step 3: Simplify The Equation
Simplify the equation from step 2. \(d = \sqrt{(4)^2 + (4)^2} = \sqrt{16 + 16}\).
4Step 4: Final Calculation
Finish the calculation to receive \(d = \sqrt{32} = 5.66\) after rounding up to two decimals.
Key Concepts
Coordinate GeometryPythagorean TheoremEquation Simplification
Coordinate Geometry
Coordinate geometry, also known as analytic geometry, is the study of geometric figures through a coordinate system. By using coordinates, such as (x, y), we can precisely locate a point on a plane. This system allows us to represent geometric figures, find distances, and much more.
In our given exercise, we have two points:
This visualization aids us in applying mathematical formulas to solve problems, such as calculating the distance between two points.
In our given exercise, we have two points:
- (0, -3)
- (4, 1)
This visualization aids us in applying mathematical formulas to solve problems, such as calculating the distance between two points.
Pythagorean Theorem
The Pythagorean theorem is a fundamental principle in mathematics used to determine the length of the sides in a right-angled triangle. It states that in such a triangle, the square of the hypotenuse, or the longest side, is equal to the sum of the squares of the other two sides. This theorem is often expressed in the equation: \[ a^2 + b^2 = c^2 \]where \(c\) represents the hypotenuse.
In the context of coordinate geometry, this principle is used to derive the distance formula. When you want to find the distance between two points on a plane, you can imagine drawing a right triangle with these points.
The horizontal leg represents the difference in x-coordinates, \((x_2 - x_1)\), and the vertical leg is the difference in y-coordinates, \((y_2 - y_1)\). By applying the Pythagorean theorem, the distance between the two points is represented by the hypotenuse: \[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \] Thus, this formula is simply an application of the Pythagorean theorem to the coordinate plane.
In the context of coordinate geometry, this principle is used to derive the distance formula. When you want to find the distance between two points on a plane, you can imagine drawing a right triangle with these points.
The horizontal leg represents the difference in x-coordinates, \((x_2 - x_1)\), and the vertical leg is the difference in y-coordinates, \((y_2 - y_1)\). By applying the Pythagorean theorem, the distance between the two points is represented by the hypotenuse: \[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \] Thus, this formula is simply an application of the Pythagorean theorem to the coordinate plane.
Equation Simplification
Equation simplification is the process of making an equation easier to solve or understand. In mathematical problems, particularly those involving calculations, simplifying equations is crucial. It involves reducing expressions and combining terms. Simplification ensures calculations are straightforward and helps in getting to the solution without unnecessary complexity.
In our solution, after applying the distance formula, the equation included expressions such as:
In our solution, after applying the distance formula, the equation included expressions such as:
- \((x_2 - x_1)^2\)
- \((y_2 - y_1)^2\)
- For the x-coordinates: \((4 - 0)^2 = 16\)
- For the y-coordinates: \((1 - (-3))^2 = 16\)
Other exercises in this chapter
Problem 8
determine whether each relation is a function. Give the domain and range for each relation. $$ |(-7,-7),(-5,-5),(-3,-3),(0,0)\\} $$
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Find \(f(g(x))\) and \(g(f(x))\) and determine whether each pair of functions \(f\) and \(g\) are inverses of each other. $$ f(x)=-x \text { and } g(x)=-x $$
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Use the given conditions to write an equation for each line in point-slope form and general form. Passing through \((-2,2)\) and parallel to the line whose equa
View solution Problem 9
Find the domain of each function. $$ f(x)-\frac{1}{x+7}+\frac{3}{x-9} $$
View solution