Problem 9
Question
Find the conjunctive normal form of \(\left(x_{1}+x_{2}+x_{3}\right)\left(x_{1} x_{2}+x_{1}^{\prime} x_{3}\right)^{\prime} .\)
Step-by-Step Solution
Verified Answer
The conjunctive normal form of \((x_1 + x_2 + x_3)(x_1 x_2 + x'_1x_3)'\) is \(x'_1x'_2 + x'_2x'_3 + x'_3\).
1Step 1: Expand the brackets
Expand the brackets by multiplying each term inside the first brackets with the whole second brackets using distributive property. The new expression becomes:\[ (x_1 + x_2 + x_3)(x_1x_2)'(x’_1x_3)'.\]
2Step 2: Apply De Morgan’s laws
De Morgan's laws state that the negation of a disjunction is the conjunction of the negations, and the negation of a conjunction is the disjunction of the negations. We can apply these properties to the expression as follows:\[ x'_1x_2'x'_1 x'_3 + x'_2x'_1 x'_3 + x'_3x'_1 x'_3.\]
3Step 3: Simplify the Boolean expression
Here we can see the term \(x'_1x'_1\) and \(x'_3x'_3\) are repeating, according to the idempotent law in Boolean algebra, \(x.x = x\) and \(x+x=x\), we can simplify the expressions to:\[ x'_1x'_2 + x'_2x'_3 + x'_3.\]
4Step 4: Conjunctive Normal Form
Finally, we've arrived at the CNF of the given Boolean expression. The CNF is a conjunction of disjunctions. Each conjunct is a disjunction of literals (in this case \(x'_1, x'_2\) and \(x'_3\)).
Key Concepts
De Morgan’s LawsBoolean AlgebraDistributive Property
De Morgan’s Laws
De Morgan's Laws are fundamental principles in Boolean Algebra that relate to complementing expressions.
They state that the complement of a conjunction (AND operation) is equivalent to the disjunction (OR operation) of the complements, and vice versa. This means:
They state that the complement of a conjunction (AND operation) is equivalent to the disjunction (OR operation) of the complements, and vice versa. This means:
- The negation of a conjunction: \((A \cdot B)' = A' + B'\)
- The negation of a disjunction: \((A + B)' = A' \cdot B'\)
Boolean Algebra
Boolean Algebra is the mathematical framework used to manipulate logical expressions.
It's built on binary variables that can take values of 0 (false) or 1 (true), allowing us to model and simplify logical statements effectively.
Here are some key properties of Boolean Algebra:
It's built on binary variables that can take values of 0 (false) or 1 (true), allowing us to model and simplify logical statements effectively.
Here are some key properties of Boolean Algebra:
- Idempotent Law: \(x \cdot x = x\) and \(x + x = x\). A variable ANDed or ORed with itself is the variable.
- Complement Law: \(x + x' = 1\) and \(x \cdot x' = 0\). A variable ORed with its complement equals 1; ANDed equals 0.
- Identity Law: \(x + 0 = x\) and \(x \cdot 1 = x\). Zero is the identity for OR; one is the identity for AND.
- Distributive Law: Explored in detail later.
Distributive Property
The Distributive Property is a key tool in Boolean Algebra and arithmetic.
It allows you to redistribute terms in an equation to simplify or rearrange them into a more usable form.
In Boolean Algebra, the Distributive Property works similarly to arithmetic but has unique characteristics:
It allows you to redistribute terms in an equation to simplify or rearrange them into a more usable form.
In Boolean Algebra, the Distributive Property works similarly to arithmetic but has unique characteristics:
- \(A \cdot (B + C) = (A \cdot B) + (A \cdot C)\): Multiplication over addition.
- \(A + (B \cdot C) = (A + B) \cdot (A + C)\): Addition over multiplication.
Other exercises in this chapter
Problem 9
An isomorphism of posets is a bijective order-homomorphism, whose inverse is also an order-homomorphism. Prove: If \(f\) is an isomorphism of a poset \(L\) onto
View solution Problem 9
Let \(B=\\{X \subseteq \mathbb{N} \mid X\) is finite or its complement in \(\mathbb{N}\) is finite\\}. Show that \(B\) is a Boolean subalgebra of \(P(\mathbb{N}
View solution Problem 9
Show that the equation \(a+x=1\) in a Boolean algebra \(B\) has the general solution \(x=a^{\prime}+u\), where \(u\) is an arbitrary element in \(B\).
View solution Problem 10
Let ( \(C[a, b]\), max, min) be the lattice of continuous real-valued functions on a closed interval \([a, b]\) and let \(D[a, b]\) be the set of all differenti
View solution