Problem 9
Question
Find each of the following dot products $(3,4) \cdot\langle 5,5\rangle
Step-by-Step Solution
Verified Answer
The dot product is 35.
1Step 1: Understand Dot Product Formula
The dot product of two vectors \((a, b)\) and \((c, d)\) is found using the formula: \[ a imes c + b imes d \] Here, vector \((3,4)\) corresponds to \((a, b)\) and vector \(\langle 5, 5 \rangle\) corresponds to \((c, d)\).
2Step 2: Multiply Corresponding Components
Using the formula, multiply the corresponding components of both vectors: - First components: \(3 \times 5\) - Second components: \(4 \times 5\)
3Step 3: Calculate Individual Products
Calculate the results of the products you set in Step 2:- Calculate \(3 \times 5 = 15\)- Calculate \(4 \times 5 = 20\)
4Step 4: Add Products Together
Add the results from Step 3 together to find the dot product:- Add \(15 + 20 = 35\)
Key Concepts
Vector MultiplicationTrigonometryVector Components
Vector Multiplication
Vector multiplication is a fundamental operation in vector algebra. When we talk about multiplying vectors, we often refer to the dot product. The dot product results in a scalar, which is essentially a single number. To calculate the dot product of two vectors
- Label the components of the first vector as \(a, b\) and of the second vector as \(c, d\).
- Apply the formula for the dot product: \( a \times c + b \times d \).
Trigonometry
Trigonometry often finds its way into vector operations, especially with dot products. A remarkable aspect of the dot product is its connection to the angle between two vectors. Using trigonometry, we can express the dot product as:
- \( \text{Dot Product} = |\vec{A}| \cdot |\vec{B}| \cdot \cos(\theta) \), where \(\theta\) is the angle between the vectors.
Vector Components
Vectors are often broken down into components for easier manipulation. Each vector in a plane can be described by its horizontal and vertical components:
- These components are usually expressed as \(x\) and \(y\), forming an ordered pair \( (x, y) \).
- The concept here is that a vector can be thought of as a combination of its directional parts along these axes.
Other exercises in this chapter
Problem 8
Find the semi perimeter of triangle \(A B C\). \(a=153 \mathrm{~cm}, b=174 \mathrm{~cm}, c=232 \mathrm{~cm}\)
View solution Problem 8
For each of the following triangles, solve for \(B\) and use the results to explain why the triangle has the given number of solutions. \(A=30^{\circ}, b=10 \ma
View solution Problem 9
Find the semi perimeter of triangle \(A B C\). \(a=2.1 \mathrm{~m}, b=2.3 \mathrm{~m}, c=3.9 \mathrm{~m}\)
View solution Problem 9
For each of the following triangles, solve for \(B\) and use the results to explain why the triangle has the given number of solutions. \(A=60^{\circ}, b=18 \ma
View solution