Problem 9
Question
Find an equation of an ellipse for each given height and width. Assume that the center of the ellipse is \((0,0) .\) $$ h=1 \mathrm{m}, w=3 \mathrm{m} $$
Step-by-Step Solution
Verified Answer
The equation of the ellipse is \(0.44x^2 + 4y^2 = 1\).
1Step 1: Identify the Given Values
From the problem, we know that the height (h) is 1m and the width (w) is 3m. The semi-major axis 'a' is half the width and the semi-minor axis 'b' is half the height in our case.
2Step 2: Plug in the Values
As the center of the ellipse is at the origin (0,0), the equation becomes \((\frac{x^2}{(\frac{3}{2})^2}) + (\frac{y^2}{(\frac{1}{2})^2}) = 1\).
3Step 3: Simplify
Simplify the equation to \((\frac{x^2}{2.25}) + (\frac{y^2}{0.25}) = 1\). Further simplification yields \(0.44x^2 + 4y^2 = 1\). This is the equation of the ellipse.
Key Concepts
Semi-Major AxisSemi-Minor AxisGeometric ShapesQuadratic Equations
Semi-Major Axis
The semi-major axis of an ellipse is an essential component in understanding its structure. It is the longest radius of the ellipse that extends from the center to the furthest edge. In simpler terms, it represents half of the longest diameter of the ellipse. For our exercise, the semi-major axis is one-half of the width given, meaning it is calculated as \( \frac{w}{2} \).
In our example, the width is 3 meters. Therefore, the semi-major axis, represented by \( a \), is calculated as:
In our example, the width is 3 meters. Therefore, the semi-major axis, represented by \( a \), is calculated as:
- \( a = \frac{3}{2} = 1.5 \, \text{meters} \)
Semi-Minor Axis
The semi-minor axis is another pivotal part of the ellipse's structure. It is the shortest radius extending from the center to the closest edge of the ellipse, effectively representing half the shortest diameter. For our specific case, the semi-minor axis is one-half of the height, which is given in the problem.
This height is 1 meter. So, the semi-minor axis \( b \) is calculated as:
This height is 1 meter. So, the semi-minor axis \( b \) is calculated as:
- \( b = \frac{1}{2} = 0.5 \, \text{meters} \)
Geometric Shapes
Ellipses are fascinating geometric shapes that belong to the family of conic sections. Unlike a perfect circle, which has equal radii, an ellipse has two distinct axes: the aforementioned semi-major and semi-minor axes.
This variation in axis length gives the ellipse its characteristic oval shape, making it a central figure in many mathematical applications such as physics and engineering. Geometric shapes like ellipses are defined by their symmetry and distinct mathematical properties. In the coordinate plane, an ellipse centered at the origin is often described by the formula \( \frac{x^2}{a^2} + \frac{y^2}{b^2} = 1 \). Understanding these properties enhances learning about different geometric forms.
This variation in axis length gives the ellipse its characteristic oval shape, making it a central figure in many mathematical applications such as physics and engineering. Geometric shapes like ellipses are defined by their symmetry and distinct mathematical properties. In the coordinate plane, an ellipse centered at the origin is often described by the formula \( \frac{x^2}{a^2} + \frac{y^2}{b^2} = 1 \). Understanding these properties enhances learning about different geometric forms.
Quadratic Equations
Ellipses are described by a specific type of quadratic equation, which is a polynomial equation of degree two. Generally, a quadratic equation in its standard form is represented as \( ax^2 + bxy + cy^2 + dx + ey + f = 0 \). However, for ellipses situated at the origin, without rotation, the equation simplifies to:
\( \frac{x^2}{a^2} + \frac{y^2}{b^2} = 1 \)
This form clearly showcases how the variables \( x \) and \( y \) relate to the semi-major (\( a \)) and semi-minor (\( b \)) axes. In our problem, after inserting the values for semi-major and semi-minor axes, we have:
\( \frac{x^2}{a^2} + \frac{y^2}{b^2} = 1 \)
This form clearly showcases how the variables \( x \) and \( y \) relate to the semi-major (\( a \)) and semi-minor (\( b \)) axes. In our problem, after inserting the values for semi-major and semi-minor axes, we have:
- \( \frac{x^2}{1.5^2} + \frac{y^2}{0.5^2} = 1 \)
Other exercises in this chapter
Problem 8
Graph each equation. Identify the conic section and describe the graph and its lines of symmetry. Then find the domain and range. $$ x^{2}-2 y^{2}=4 $$
View solution Problem 8
Write an equation of a circle with the given center and radius. Check your answers. $$ (-1.5,-3), 2 $$
View solution Problem 9
Write an equation of a hyperbola with the given characteristics. vertices \((0,-2)\) and \((0,4),\) foci \((0,6)\) and \((0,-4)\)
View solution Problem 9
Graph each equation. $$ 81 y^{2}-9 x^{2}=729 $$
View solution