Problem 9
Question
Fill in the blanks in the following table. (a) \(\mathrm{CoCO}_{3}\) (b) \(\mathrm{LaF}_{3}\) (c) \(\mathrm{Ba}_{3}\left(\mathrm{PO}_{4}\right)_{2}\)
Step-by-Step Solution
Verified Answer
Question: Identify the name, type, charges, and formula units for the following compounds:
(a) CoCO3
(b) LaF3
(c) Ba3(PO4)2
Answer:
(a) Cobalt(II) Carbonate, Ionic Compound, Co^2+ and CO3^2-, CoCO3
(b) Lanthanum(III) Fluoride, Ionic Compound, La^3+ and F^-, LaF3
(c) Barium Phosphate, Ionic Compound, Ba^2+ and PO4^3-, Ba3(PO4)2
1Step 1: (a) CoCO3: Name of Compound
Cobalt(II) Carbonate
2Step 2: (a) CoCO3: Type of Compound
Ionic Compound
3Step 3: (a) CoCO3: Charges
Cobalt(II) has a charge of +2 (Co^2+), while carbonate (CO3) has a charge of -2 (CO3^2-).
4Step 4: (a) CoCO3: Formula Unit
As the charges balance each other out, the formula unit is CoCO3.
5Step 5: (b) LaF3: Name of Compound
Lanthanum(III) Fluoride
6Step 6: (b) LaF3: Type of Compound
Ionic Compound
7Step 7: (b) LaF3: Charges
Lanthanum(III) has a charge of +3 (La^3+), while fluoride (F) has a charge of -1 (F^-).
8Step 8: (b) LaF3: Formula Unit
To balance the charges, we need three fluoride ions for each lanthanum ion; the formula unit is LaF3.
9Step 9: (c) Ba3(PO4)2: Name of Compound
Barium Phosphate
10Step 10: (c) Ba3(PO4)2: Type of Compound
Ionic Compound
11Step 11: (c) Ba3(PO4)2: Charges
Barium (Ba) has a charge of +2 (Ba^2+), while phosphate (PO4) has a charge of -3 (PO4^3-).
12Step 12: (c) Ba3(PO4)2: Formula Unit
To balance the charges, we need three barium ions and two phosphate ions; the formula unit is Ba3(PO4)2.
Key Concepts
Chemical NomenclatureChemical FormulaIonic Bonds
Chemical Nomenclature
Chemical nomenclature refers to the systematic naming of chemical compounds based on their molecular composition and structure. It plays a crucial role in ensuring clear communication within the scientific community and prevents misunderstandings. In the context of ionic compounds, each name consists of two parts:
- The name of the metal (cation) comes first.
- Followed by the name of the non-metal (anion) with a suffix change to "-ide" when the anion is a simple ion.
Chemical Formula
The chemical formula of a compound represents the types and numbers of atoms present. In ionic compounds, this formula also conveys information about the balance of charges. By understanding chemical formulas, we can deduce the compound's basic composition and its neutral charge state. For instance, with CoCO3:
- Co represents cobalt, and CO3 is the carbonate ion.
- Cobalt has a charge of +2, and carbonate has a charge of -2.
Ionic Bonds
Ionic bonds form through the electrostatic attraction between cations (positively charged ions) and anions (negatively charged ions). This type of chemical bond occurs when one atom transfers electrons to another, resulting in the formation of ions. For example, in lanthanum(III) fluoride (LaF3), lanthanum loses three electrons, becoming a cation (La3+), and each fluorine gains one electron, forming fluoride anions (F-). The attraction between the oppositely charged ions holds the compound together. Ionic bonds are generally strong, leading to compounds with high melting and boiling points and typically solid crystalline structures. Understanding ionic bonds is critical in predicting the properties of an ionic compound and explaining how such compounds will interact with others both chemically and physically.
Other exercises in this chapter
Problem 4
Write the equilibrium equations on which the following \(K_{s p}\) expressions are based. (a) \(\left[\mathrm{Ca}^{2+}\right]\left[\mathrm{CO}_{3}{\underline{\phantom{xx}}}^{2-}\right
View solution Problem 5
Given \(K_{s p}\) and the equilibrium concentration of one ion, calculate the equilibrium concentration of the other ion. (a) cadmium(II) hydroxide: \(K_{\text
View solution Problem 10
Fill in the blanks in the following table. (a) \(\mathrm{BaC}_{2} \mathrm{O}_{4}\) (b) \(\mathrm{Cr}(\mathrm{OH})_{3}\) (c) \(\mathrm{Pb}_{3}\left(\mathrm{PO}_{
View solution Problem 12
Cadmium(II) chloride is added to a solution of potassium hydroxide with a \(\mathrm{pH}\) of \(9.62 .\left(K_{\mathrm{sp}} \mathrm{Cd}(\mathrm{OH})_{2}=2.5 \tim
View solution