Problem 9
Question
Evaluate each of the iterated integrals. $$ \int_{0}^{\pi / 2} \int_{0}^{1} x \sin x y d y d x $$
Step-by-Step Solution
Verified Answer
The solution setup involves complex integration, often resolved using numerical methods or special functions.
1Step 1: Integrate with respect to y
To evaluate the iterated integral \( \int_{0}^{\pi / 2} \int_{0}^{1} x \sin(xy) \, dy \, dx \), we first hold \( x \) constant and integrate with respect to \( y \). The integral becomes \( \int_{0}^{1} x \sin(xy) \, dy \). To solve this, use the substitution \( u = xy \), which gives \( du = x \, dy \) or \( dy = \frac{du}{x} \). The limits of \( y \) from 0 to 1 transform \( u \) from 0 to \( x \). The integral becomes \( \int_{0}^{x} \sin(u) \frac{1}{x} \, du \). This simplifies to \( \frac{1}{x} \left[ -\cos(u) \right]_{0}^{x} \). Substitute back to get \( \frac{1}{x}(-\cos(x) + 1) = \frac{1 - \cos(x)}{x} \).
2Step 2: Integrate with respect to x
Now integrate with respect to \( x \) over the interval from 0 to \( \pi/2 \): \( \int_{0}^{\pi/2} \frac{1 - \cos(x)}{x} \, dx \). This is a challenging integral to evaluate analytically without special functions, so we must focus on determining it as a conceptual step in the setup of iterated integrals. However, we note that integration by parts or numerical techniques could give an approximate value. The precise integration of this form would ideally use advanced mathematical techniques or numerical methods for a solution.
Key Concepts
Integration TechniquesSubstitution MethodIntegration by PartsNumerical Integration
Integration Techniques
In calculus, integration techniques are methods used to find the integral of functions. These techniques are crucial because they allow us to compute areas under curves, volumes, and solve various problems in physics and engineering.
There are several common integration techniques:
In the given exercise, we applied substitution and recognized that future techniques could assist in completing the problem.
There are several common integration techniques:
- Basic Integration: Involves straightforward integration of functions that have simple antiderivatives.
- Substitution: Used when a direct integration is not possible and involves substituting parts of the integral with a new variable.
- Integration by Parts: Useful for integrating products of functions.
- Partial Fractions: Used for integrating rational functions by breaking them into simpler fractions.
In the given exercise, we applied substitution and recognized that future techniques could assist in completing the problem.
Substitution Method
The substitution method is a powerful technique to simplify an integral. It works by transforming the variable of integration into a new variable, making the integral easier to compute.
In the exercise, we used substitution by setting up a new variable, \( u = xy \), which leads to derivative transformation \( du = x \, dy \). By rewriting \( dy \) as \( \frac{du}{x} \), the integral simplifies, enabling easier integration over the limits.
This method is particularly helpful when an integral contains products or compositions of functions, such as trigonometric or exponential functions. It simplifies the function inside the integral and often resolves complex integrals into standard form.
In the exercise, we used substitution by setting up a new variable, \( u = xy \), which leads to derivative transformation \( du = x \, dy \). By rewriting \( dy \) as \( \frac{du}{x} \), the integral simplifies, enabling easier integration over the limits.
This method is particularly helpful when an integral contains products or compositions of functions, such as trigonometric or exponential functions. It simplifies the function inside the integral and often resolves complex integrals into standard form.
Integration by Parts
Integration by parts is a technique derived from the product rule of differentiation and is particularly useful for integrating products of functions.
It is expressed as \( \int u \, dv = uv - \int v \, du \). Here, \( u \) and \( dv \) are parts carefully chosen from the integral. This transformation sometimes simplifies the integration process significantly.
In our example, integration by parts may help in solving \( \int_{0}^{\pi/2} \frac{1 - \cos(x)}{x} \, dx \) effectively. While straightforward calculations are complex, this method leverages the derivative and integral connections, facilitating simplification by recursive application. Often, identifying the right functions for \( u \) and \( dv \) is key to reducing the integral into simpler components.
It is expressed as \( \int u \, dv = uv - \int v \, du \). Here, \( u \) and \( dv \) are parts carefully chosen from the integral. This transformation sometimes simplifies the integration process significantly.
In our example, integration by parts may help in solving \( \int_{0}^{\pi/2} \frac{1 - \cos(x)}{x} \, dx \) effectively. While straightforward calculations are complex, this method leverages the derivative and integral connections, facilitating simplification by recursive application. Often, identifying the right functions for \( u \) and \( dv \) is key to reducing the integral into simpler components.
Numerical Integration
Sometimes, an integral cannot be solved analytically, and numerical integration methods become necessary. These techniques approximate the value of an integral using discrete data points.
Common numerical methods include:
Common numerical methods include:
- Trapezoidal Rule: Approximates the region under the curve as a series of trapezoids.
- Simpson's Rule: Uses parabolic segments instead of linear ones for approximation.
- Monte Carlo Integration: Useful for multidimensional integrals and is based on randomness.
Other exercises in this chapter
Problem 9
Evaluate the iterated integrals. \(\int_{-2}^{4} \int_{x-1}^{x+1} \int_{0}^{\sqrt{2 y / x}} 3 x y z d z d y d x\)
View solution Problem 9
Evaluate the iterated integrals. $$ \int_{0}^{\pi / 9} \int_{\pi / 4}^{3 r} \sec ^{2} \theta d \theta d r $$
View solution Problem 10
Use cylindrical coordinates to find the indicated quantity. Volume of the solid bounded above by the plane \(z=y+4\), below by the \(x y\) -plane, and laterally
View solution Problem 10
Find the image of the rectangle with the given corners and find the Jacobian of the transformation. $$ x=u, y=u^{2}-v^{2} ;(0,0),(3,0),(3,1),(0,1) $$
View solution