Problem 9
Question
Calculate Samples \(\mathrm{A}, \mathrm{B}\) , and \(C\) have masses of \(80 \mathrm{g}, 12 \mathrm{g},\) and \(33 \mathrm{g},\) and volumes of \(20 \mathrm{mL}, 4 \mathrm{cm}^{3},\) and 11 \(\mathrm{mL}\) , respectively. Which of the samples have the same density?
Step-by-Step Solution
Verified Answer
Samples B and C have the same density (3 g/mL).
1Step 1: Understand the formula for density
Density is calculated using the formula: \( \text{Density} = \frac{\text{Mass}}{\text{Volume}} \). This formula will help us determine the density of each sample.
2Step 2: Calculate the density of Sample A
Sample A has a mass of 80 g and a volume of 20 mL. Using the density formula: \( \text{Density of A} = \frac{80\, \text{g}}{20\, \text{mL}} = 4\, \text{g/mL} \).
3Step 3: Calculate the density of Sample B
Sample B has a mass of 12 g and a volume of 4 cm\(^3\). Since 1 mL = 1 cm\(^3\), the volume can be considered without conversion. Thus, \( \text{Density of B} = \frac{12\, \text{g}}{4\, \text{cm}^3} = 3\, \text{g/cm}^3 \).
4Step 4: Calculate the density of Sample C
Sample C has a mass of 33 g and a volume of 11 mL. Thus, \( \text{Density of C} = \frac{33\, \text{g}}{11\, \text{mL}} = 3\, \text{g/mL} \).
5Step 5: Compare the densities of the samples
The densities calculated are: Sample A = 4 g/mL, Sample B = 3 g/cm\(^3\), and Sample C = 3 g/mL. Since the densities of samples B and C are equal, these two have the same density.
Key Concepts
Mass and VolumeUnit ConversionDensity FormulaDensity Comparison
Mass and Volume
When we talk about density, we start with mass and volume. Mass refers to the amount of matter an object contains, while volume is the amount of space that object occupies. In our exercise, Sample A has a mass of 80 grams and a volume of 20 mL, Sample B has a mass of 12 grams and a volume of 4 cm³, and Sample C has a mass of 33 grams and a volume of 11 mL. Understanding mass and volume is crucial because these values are used to calculate density. Remember that mass is typically measured in grams (g) and volume in milliliters (mL) or cubic centimeters (cm³). For liquids, 1 mL is equivalent to 1 cm³.
Unit Conversion
Unit conversion is a fundamental step to ensure consistency in our calculations. It helps in easily comparing different sets of data. In our example, Sample B's volume is given in cm³, but because 1 cm³ equals 1 mL, we don’t need to convert it to find density.
- Always check for different units and make sure they are comparable.
- Use conversion factors, like 1 mL = 1 cm³, when needed to align your units.
Density Formula
The density formula is a simple yet powerful tool: \[ \text{Density} = \frac{\text{Mass}}{\text{Volume}} \] This formula tells us how much mass is contained in a given volume.
- For Sample A, density is \( \frac{80 \, \text{g}}{20 \, \text{mL}} = 4 \, \text{g/mL} \).
- For Sample B: \( \frac{12 \, \text{g}}{4 \, \text{cm}^3} = 3 \, \text{g/cm}^3 \).
- For Sample C: \( \frac{33 \, \text{g}}{11 \, \text{mL}} = 3 \, \text{g/mL} \).
Density Comparison
Density comparison allows us to determine which materials are relatively heavier or lighter for their size. In the exercise, we found:
- Sample A with a density of 4 g/mL.
- Sample B with 3 g/cm³.
- Sample C also at 3 g/mL.
Other exercises in this chapter
Problem 7
Define the relationships among the mass, volume, and density of a material.
View solution Problem 8
Apply Why does oil float on water?
View solution Problem 10
Design a concept map that shows the relationships among the following terms: volume, derived unit, mass, base unit, time, and length.
View solution Problem 11
Express each number in scientific notation. a. 700\(\quad\) c. 4,500,000 \(\quad\) e. 0.0054\(\quad\) g. 0.000000076 b. 38,000\(\quad\) d. 685,000,000,000 \(\qu
View solution