Problem 9
Question
Assume that the coordinates of the points \(P\) \(Q, R, S,\) and \(O\) are as follows: \(P(-1,3) \quad Q(4,6) \quad R(4,3) \quad S(5,9) \quad O(0,0)\) Draw the indicated vector (using graph paper) and compute its magnitude. Compute the sums using the definition. Use the parallelogram law to compute the sums. $$\overrightarrow{O P}+\overrightarrow{P Q}$$
Step-by-Step Solution
Verified Answer
The resultant vector is \( (4, 6) \) with magnitude \( 2\sqrt{13} \).
1Step 1: Define the Vectors
The vector \(\overrightarrow{OP}\) is the vector from point \(O\) to point \(P\), so its coordinates are \((-1, 3)\). The vector \(\overrightarrow{PQ}\) is the vector from point \(P\) to point \(Q\), so to find it, we subtract the coordinates of \(P\) from \(Q\): \(\overrightarrow{PQ} = (4-(-1), 6-3) = (5, 3)\).
2Step 2: Calculate Vector Sum
Using the vectors from Step 1, we add \(\overrightarrow{OP}\) and \(\overrightarrow{PQ}\) by adding their respective components: \((x_1 + x_2, y_1 + y_2) = (-1 + 5, 3 + 3) = (4, 6)\). Thus, \(\overrightarrow{OP} + \overrightarrow{PQ} = (4, 6)\).
3Step 3: Compute Magnitude of the Resultant Vector
The magnitude of the vector \((4, 6)\) is calculated using the formula \(\|\mathbf{v}\| = \sqrt{x^2 + y^2}\): \[ \|\mathbf{v}\| = \sqrt{4^2 + 6^2} = \sqrt{16 + 36} = \sqrt{52} = 2\sqrt{13} \].
4Step 4: Confirm using the Parallelogram Law
The parallelogram law of vector addition involves constructing a parallelogram with \(\overrightarrow{OP}\) and \(\overrightarrow{PQ}\) as adjacent sides. The resultant vector, \(\overrightarrow{OA}\), from \(O\) to the opposite corner of the parallelogram, confirms the addition: \(\overrightarrow{OA} = \overrightarrow{OP} + \overrightarrow{PQ} = (4, 6)\), confirming the previous result.
Key Concepts
Coordinate GeometryMagnitude of a VectorParallelogram LawVector Components
Coordinate Geometry
Coordinate geometry is a branch of mathematics that helps us deal with geometry using a coordinate system. A coordinate system uses numbers as coordinates to describe the position of points on a plane.
In our exercise, we work in a two-dimensional plane with pairs of numbers, \(x, y\), representing each point like \((x, y)\). For example, point \(P(-1, 3)\) tells us that \(-1\) is how far 'left or right' it is from the origin (0,0), and \(3\) is how far 'up or down'.
In our exercise, we work in a two-dimensional plane with pairs of numbers, \(x, y\), representing each point like \((x, y)\). For example, point \(P(-1, 3)\) tells us that \(-1\) is how far 'left or right' it is from the origin (0,0), and \(3\) is how far 'up or down'.
- The negative sign with \(-1\) means it is to the left of the origin.
- The positive \(3\) means it is above the origin.
Magnitude of a Vector
The magnitude of a vector tells us about its length. It's a bit like figuring out how long a stick would measure if it was positioned between two points. In math, we find the magnitude by using the Pythagorean theorem.
For a vector with components \(x\) and \(y\), its magnitude is represented by \(\|\mathbf{v}\|\) and calculated as: \[\|\mathbf{v}\| = \sqrt{x^2 + y^2}\].
In our problem, the resultant vector \(\overrightarrow{OP} + \overrightarrow{PQ}\) has the coordinates \(4,6\). To find its magnitude, we plug \(4\) and \(6\) into our formula:
\[\|\mathbf{v}\| = \sqrt{4^2 + 6^2} = \sqrt{16 + 36} = \sqrt{52} = 2\sqrt{13} .\]
This magnitude tells us the straight-line distance from point \(O\) to the resultant point in the plane. It's an important property in physics and engineering where vectors represent quantities like velocity or force.
For a vector with components \(x\) and \(y\), its magnitude is represented by \(\|\mathbf{v}\|\) and calculated as: \[\|\mathbf{v}\| = \sqrt{x^2 + y^2}\].
In our problem, the resultant vector \(\overrightarrow{OP} + \overrightarrow{PQ}\) has the coordinates \(4,6\). To find its magnitude, we plug \(4\) and \(6\) into our formula:
\[\|\mathbf{v}\| = \sqrt{4^2 + 6^2} = \sqrt{16 + 36} = \sqrt{52} = 2\sqrt{13} .\]
This magnitude tells us the straight-line distance from point \(O\) to the resultant point in the plane. It's an important property in physics and engineering where vectors represent quantities like velocity or force.
Parallelogram Law
The parallelogram law is a visual way to understand vector addition. Imagine drawing a parallelogram where two vectors serve as adjacent sides. The diagonal of this parallelogram represents the sum of the two vectors.
In our specific case, \(\overrightarrow{OP}\) and \(\overrightarrow{PQ}\) create adjacent sides. The diagonal from \(O\) represents \(\overrightarrow{OP} + \overrightarrow{PQ}\). This diagonal or resultant vector should match our earlier calculated sum.
In our specific case, \(\overrightarrow{OP}\) and \(\overrightarrow{PQ}\) create adjacent sides. The diagonal from \(O\) represents \(\overrightarrow{OP} + \overrightarrow{PQ}\). This diagonal or resultant vector should match our earlier calculated sum.
- Start at \(O\), draw \(\overrightarrow{OP}\).
- Then from \(P\), draw \(\overrightarrow{PQ}\).
- Complete the parallelogram from these points.
- The vector from \(O\) to the opposite corner of the parallelogram is \(\overrightarrow{OA}\).
Vector Components
Vector components break a vector down into parts based on the coordinate directions. Think of a vector as having two fingers pointing: one horizontally along the x-axis, and the other vertically along the y-axis.
For example, the sum vector \(\overrightarrow{OP} + \overrightarrow{PQ} = (4, 6)\) was calculated by adding the x-components together and the y-components together: \((-1 + 5, 3 + 3) = (4, 6)\). This method makes the math straightforward and logical while following the rules of coordinate geometry thoroughly.
- The x-component tells how far along the x-direction the vector is.
- The y-component shows how far along the y-direction.
For example, the sum vector \(\overrightarrow{OP} + \overrightarrow{PQ} = (4, 6)\) was calculated by adding the x-components together and the y-components together: \((-1 + 5, 3 + 3) = (4, 6)\). This method makes the math straightforward and logical while following the rules of coordinate geometry thoroughly.
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