Problem 9
Question
a) Prove that if \(\sum x_{n}\) and \(\sum y_{n}\) converge absolutely, then \(\sum x_{n} y_{n}\) converges absolutely. b) Find an explicit example where the converse does not hold. c) Find an explicit example where all three series are absolutely comvergent, are not just finite sums, and \(\left(\sum x_{n}\right)\left(\sum y_{n}\right) \neq \sum x_{n} y_{n} .\) That is, show that series are not multiplied term-by- term.
Step-by-Step Solution
Verified Answer
a) Absolute convergence implies \(\sum x_n y_n\) converges. b) An example: \(x_n = (-1)^n/\sqrt{n}\), \(y_n = (-1)^n/\sqrt{n}\). c) An example: \(x_n = (-1)^n/n\), \(y_n = (-1)^n/n^2\).
1Step 1: Understanding Absolute Convergence
The series \( \sum x_n \) is said to converge absolutely if \( \sum |x_n| \) converges. Similarly, \( \sum y_n \) converges absolutely if \( \sum |y_n| \) converges.
2Step 2: Prove Absolute Convergence of \( \sum x_n y_n \)
Since \( \sum x_n \) and \( \sum y_n \) converge absolutely, by comparison, we have \( \sum |x_n| < \infty \) and \( \sum |y_n| < \infty \). Therefore, \( \sum |x_n y_n| \leq \sum |x_n| |y_n| \), which is bounded by the product \( \sum |x_n| \cdot \sup |y_n| \), ensuring the absolute convergence of \( \sum x_n y_n \) by the comparison test.
3Step 3: Example Where the Converse Does Not Hold
Consider the series \( x_n = \frac{(-1)^n}{\sqrt{n}} \) and \( y_n = \frac{(-1)^n}{\sqrt{n}} \). The series \( \sum x_n y_n = \sum \frac{1}{n} \) converges (i.e., it's a p-series with p=1), but \( \sum x_n \) and \( \sum y_n \) do not converge absolutely as \( \sum |x_n| = \sum \frac{1}{\sqrt{n}} \) diverges.
4Step 4: Example Where Combined Series Are Not Term-By-Term Multipliable
Let \( x_n = \frac{(-1)^n}{n} \) and \( y_n = \frac{(-1)^n}{n^2} \). Both \( \sum x_n \) and \( \sum y_n \) converge absolutely. Hence, \( \sum x_n y_n = \sum \frac{1}{n^3} \) also converges absolutely. However, the product of complete sums \( (\sum x_n)(\sum y_n) eq \sum x_n y_n \) as shown with the alternating series property not matching this term-by-term multiplication behavior.
Key Concepts
Convergence of SeriesComparison TestAbsolutely Convergent Series
Convergence of Series
When we talk about the convergence of a series, we are referring to whether the sum of an infinite sequence of numbers has a finite limit. In essence, it is about determining if you add up all the terms in a series, can you arrive at a specific numerical value?
- A series is considered convergent if its sequence of partial sums eventually stabilizes to a certain number.
- If the terms of \(\sum x_n\) can be rearranged without changing the sum, the original sequence is said to be absolutely convergent.
Comparison Test
The comparison test is a powerful tool for determining the convergence of infinite series. It works by comparing a series to another series whose convergence properties are already known.
- If \(\sum a_n \) is a series with positive terms and there exists another series \(\sum b_n \) where \(a_n \leq b_n\), and if \(\sum b_n\) converges, then \(\sum a_n\) converges as well.
- Conversely, if \(a_n \geq b_n\) and \(\sum b_n\) diverges, then \(\sum a_n\) diverges too.
Absolutely Convergent Series
A series is said to be absolutely convergent if the series of the absolute values of its terms converges. Absolute convergence is a stronger form of convergence because if a series converges absolutely, then it converges as well.
- For example, if \(\sum x_n\) converges absolutely, then \(\sum |x_n|\) also converges.
- Absolute convergence implies that any rearrangement of the terms of the series will still converge to the same sum.
Other exercises in this chapter
Problem 9
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