Problem 89
Question
Symmetry What symmetry will you find in a surface that has an equation of the form \(r=f(z)\) in cylindrical coordinates? Give reasons for your answer.
Step-by-Step Solution
Verified Answer
The surface has rotational symmetry around the \( z \)-axis.
1Step 1: Understanding the Equation
The equation provided is in the form of cylindrical coordinates, where \( r = f(z) \). Here, \( r \) is a function of \( z \), indicating how the radius varies with the height \( z \). This suggests that the radial distance depends solely on the vertical coordinate \( z \).
2Step 2: Analyzing Symmetrical Features
In cylindrical coordinates, if \( r \) depends only on \( z \), it implies that the surface is symmetrical around the \( z \)-axis. This is because, for any fixed \( z \), \( r \) will be the same for all values of the angular coordinate \( \theta \). Thus, the surface will look the same when rotated around the \( z \)-axis.
3Step 3: Conclusion on Type of Symmetry
Based on the analysis, the surface described by the equation \( r = f(z) \) possesses rotational symmetry about the \( z \)-axis. This means that for every height \( z \), the cross-section is a circle centered on the \( z \)-axis.
Key Concepts
Cylindrical CoordinatesRotational SymmetryGeometric Transformations
Cylindrical Coordinates
Cylindrical coordinates are an extension of polar coordinates into three dimensions. They are particularly useful when dealing with problems that have symmetry around an axis, making them ideal for surfaces that revolve around a central line, like a cylinder or a cone. This coordinate system uses three variables: \( r \), \( \theta \), and \( z \).
- \( r \) represents the radial distance from the central axis. It's analogous to the radius in polar coordinates and determines the distance of a point from the \( z \)-axis.
- \( \theta \) is the angular coordinate and is measured in the plane perpendicular to the \( z \)-axis. It shows the rotation angle around the axis and varies between \( 0 \) and \( 2\pi \).
- \( z \) denotes the height or the vertical distance from a reference plane, much like the \( z \)-coordinate in Cartesian coordinates.
Rotational Symmetry
Rotational symmetry occurs when a shape or object retains its overall appearance even after being rotated about an axis. This is a common feature in many natural and man-made structures, and it is a significant simplification in geometric problem-solving.In the case of the equation \( r = f(z) \) in cylindrical coordinates, the dependency of \( r \) only on \( z \) means for every specific height \( z \), \( r \) remains constant, making the distance from the \( z \)-axis uniform around a circle.
- This creates a rotationally symmetric surface around the \( z \)-axis.
- No matter how much the surface is rotated around this axis, it will look the same.
Geometric Transformations
Geometric transformations involve changing the position, size, or orientation of an object while retaining its shape and proportions. These transformations are fundamental in understanding different perspectives in geometry and algebra.In cylindrical coordinate systems, such transformations often include rotations and translations, which help in visualizing symmetry and simplifying equations.
- Rotations: Since the object in question has rotational symmetry, any rotation around the \( z \)-axis does not change the shape of the object, thereby preserving its geometry.
- Translations: Moving the entire surface up and down along the \( z \)-axis will not affect its symmetry or shape, as it only involves changing the \( z \) coordinate.
- Scaling: Uniformly increasing or decreasing \( r \) values leads to a proportional change in the object's size without altering its symmetry.
Other exercises in this chapter
Problem 86
Vertical circular cylinders in spherical coordinates Find an equation of the form \(\rho=f(\phi)\) for the cylinder \(x^{2}+y^{2}=a^{2}\)
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Symmetry What symmetry will you find in a surface that has an equation of the form \(\rho=f(\phi)\) in spherical coordinates? Give reasons for your answer.
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Density of center of a planet \(A\) planet is in the shape of a sphere of radius \(R\) and total mass \(M\) with spherically symmetric density distribution that
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