Problem 89
Question
Solve each equation in Exercises \(83-108\) by the method of your choice. $$ x^{2}-2 x=1 $$
Step-by-Step Solution
Verified Answer
The solutions to the equation are \(x = 1 - \sqrt{2}\) and \(x = 1 + \sqrt{2}\).
1Step 1: Identify coefficients
From the equation \(x^2 - 2x - 1 = 0\), we can identify the coefficients as \(a = 1\), \(b = -2\), \(c = -1\).
2Step 2: Calculate the discriminant
Before using the quadratic formula let's first compute the discriminant using the formula \(D = b^2 - 4ac\). Substituting the coefficient values, we get \(D = (-2)^2 - 4*1*(-1) = 4 + 4 = 8\).
3Step 3: Solve for x
Now we can solve for \(x\) using the quadratic formula \(x = \frac{-b \pm \sqrt{D}}{2a}\). Let's substitute the values of \(a\), \(b\) and \(D\) into the formula: \(x = \frac{2 \pm \sqrt{8}}{2} = 1 \pm \sqrt{2}\).
Key Concepts
Quadratic FormulaDiscriminant CalculationCoefficient Identification
Quadratic Formula
When solving quadratic equations, the quadratic formula is a powerful tool that provides a solution to equations of the form \( ax^2 + bx + c = 0 \). It encapsulates the process of finding the roots of the equation in a neat, single expression: \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \).
To apply this formula correctly, you first need to ensure your equation is arranged in the standard form \( ax^2 + bx + c = 0 \), where \(a\), \(b\), and \(c\) are coefficients. The formula then tells us that by substituting these coefficients into it, we can directly find the variable \(x\), which are the points where the quadratic equation intersects the \(x\)-axis, also known as the roots of the equation. This direct approach bypasses the need for factoring the quadratic, which can be particularly useful when the equation does not factor nicely.
To apply this formula correctly, you first need to ensure your equation is arranged in the standard form \( ax^2 + bx + c = 0 \), where \(a\), \(b\), and \(c\) are coefficients. The formula then tells us that by substituting these coefficients into it, we can directly find the variable \(x\), which are the points where the quadratic equation intersects the \(x\)-axis, also known as the roots of the equation. This direct approach bypasses the need for factoring the quadratic, which can be particularly useful when the equation does not factor nicely.
Discriminant Calculation
The discriminant in a quadratic equation is found within the square root of the quadratic formula and is denoted as \( D \). The formula for the discriminant is \( D = b^2 - 4ac \). It plays a crucial role in predicting the nature of the roots without actually solving the equation.
Understanding the Value of the Discriminant
- If \( D > 0 \), the quadratic equation has two distinct real roots.
- If \( D = 0 \), there is exactly one real root, also known as a repeated or double root.
- If \( D < 0 \), the roots are complex and come in conjugate pairs.
Coefficient Identification
The correct identification of coefficients in a quadratic equation is the foundational step for both the discriminant calculation and the application of the quadratic formula. Coefficients \(a\), \(b\), and \(c\) represent specific values in the standard quadratic equation, \(ax^2 + bx + c = 0\).
Identifying Coefficients:
\(a\) is the coefficient of \(x^2\), \(b\) is the coefficient of \(x\), and \(c\) is the constant term.- The coefficient \(a\) influences the parabola's opening direction and its steepness.
- The coefficient \(b\) affects the position of the parabola along the \(x\)-axis.
- The constant term \(c\) dictates where the parabola crosses the \(y\)-axis.
Other exercises in this chapter
Problem 88
Solve each absolute value inequality. $$2>|11-x|$$
View solution Problem 88
Evaluate \(x^{2}-(x y-y)\) for \(x\) satisfying \(\frac{13 x-6}{4}=5 x+2\) and \(y\) satisfying \(5-y=7(y+4)+1\).
View solution Problem 89
Will help you prepare for the material covered in the next section. Multiply and simplify: \((x-3)\left(\frac{3}{x-3}+9\right)\)
View solution Problem 89
Find all values of \(x\) satisfying the given conditions. $$ y=2 x^{3}+x^{2}-8 x+2 \text { and } y=6 $$
View solution