Problem 89
Question
Solve. $$ 0.035 x+5.112=0.010 x+5.107 $$
Step-by-Step Solution
Verified Answer
The solution is \( x = -0.2 \).
1Step 1: Isolate the Variable Terms
To isolate the variable terms, we need to move the term with the variable on the right side of the equation to the left. Subtract \(0.010x\) from both sides of the equation:\[ 0.035x + 5.112 - 0.010x = 5.107 \]This simplifies to:\[ 0.025x + 5.112 = 5.107 \]
2Step 2: Isolate the Constant Terms
Next, we need to move all constant terms to the right side of the equation. Subtract \(5.112\) from both sides:\[ 0.025x + 5.112 - 5.112 = 5.107 - 5.112 \]This simplifies to:\[ 0.025x = -0.005 \]
3Step 3: Solve for the Variable
To solve for \(x\), divide both sides of the equation by \(0.025\):\[ x = \frac{-0.005}{0.025} \]Simplify the fraction:\[ x = -0.2 \]
4Step 4: Solution Verification
Substitute \(x = -0.2\) back into the original equation to verify:Original equation:\[ 0.035(-0.2) + 5.112 = 0.010(-0.2) + 5.107 \]Calculate each side:- Left: \(0.035(-0.2) = -0.007 \), so \(-0.007 + 5.112 = 5.105 \)- Right: \(0.010(-0.2) = -0.002 \), so \(-0.002 + 5.107 = 5.105 \)Both sides are equal. Thus, the solution is verified.
Key Concepts
Linear EquationsSolving EquationsVariable IsolationEquation Verification
Linear Equations
Linear equations are mathematical expressions that create a straight line when graphed. They are usually written in the form \(ax + b = c\), where \(a\), \(b\), and \(c\) are constants and \(x\) is the variable. These equations are fundamental in algebra as they help in determining the value of the unknown variable that makes the equation true. They play a vital role in various fields such as physics, engineering, and economics for modeling relationships and predicting outcomes. Understanding linear equations provides a strong foundation for solving more complex mathematical problems. When dealing with linear equations, it's important to remember that the solutions are valid only if the mathematical operations are applied consistently to both sides of the equation. This ensures the balance of equality.
Solving Equations
Solving equations involves finding the value of the variable that satisfies the equation. In algebra, solving linear equations typically follows a structured approach:
- Identify the equation and simplify both sides if necessary.
- Apply mathematical operations to isolate the variable term on one side.
- Perform the reverse of the operations used, maintaining equation balance.
- Check the solution by substituting the variable back into the original equation.
Variable Isolation
Variable isolation is a method used to rearrange the equation so that the unknown variable stands alone on one side of the equation. This process often requires:
- Subtracting or adding terms to both sides to move the variable.
- Dividing or multiplying values to further simplify the expression.
Equation Verification
Equation verification is the final step in the problem-solving process where you confirm that the obtained solution is indeed correct. This involves substituting the solution back into the original equation.For example, in the exercise solution, after determining that \(x = -0.2\), you plug this value into the original equation to check balance on both sides. Calculate each side separately and compare results:
- Left Side: Calculate with the solution substituted into the left-hand expression.
- Right Side: Calculate with the solution substituted into the right-hand expression.
Other exercises in this chapter
Problem 88
Simplify each expression. See Section \(1.8 .\) \(8(z-6)+7 z-1\)
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Substitute the given values into each given formula and solve for the unknown variable. If necessary, round to one decimal place. $$ I=P R T ; \quad I=3750, P=2
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Fill in the blank with a number of your choice so that each equation has the given solution. 6 x= ____ ; solution: -8
View solution Problem 89
Substitute the given values into each given formula and solve for the unknown variable. If necessary, round to one decimal place. $$ V=\frac{4}{3} \pi r^{3} ; \
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