Problem 89
Question
Predict which of these clements would have the greatest difference betwcen the first and sccond ionization cncrgics: Si, \(\mathrm{Na}, \mathrm{P}, \mathrm{Mg} .\) Bricfly explain your answer.
Step-by-Step Solution
Verified Answer
Sodium (
\(\text{Na}\)) has the greatest difference in ionization energies.
1Step 1: Understanding Ionization Energies
Ionization energy is the energy required to remove an electron from an atom or ion in its gaseous state. The first ionization energy refers to removing the first electron, while the second ionization energy refers to removing the second electron.
2Step 2: Evaluating Ionization Energy Trends
In general, the second ionization energy is significantly higher than the first ionization energy for elements whose removal of a second electron requires disrupting a stable electronic configuration. This is because it would involve breaking into a filled or half-filled shell.
3Step 3: Examining the Electronic Configurations
Let's consider the electronic configurations of the elements: - Sodium (\( ext{Na}\)): 1s² 2s² 2p⁶ 3s¹ - Silicon (\( ext{Si}\)): 1s² 2s² 2p⁶ 3s² 3p² - Phosphorus (\( ext{P}\)): 1s² 2s² 2p⁶ 3s² 3p³ - Magnesium (\( ext{Mg}\)): 1s² 2s² 2p⁶ 3s². The key is to determine which element will have a stable configuration after the removal of the first electron and thus a greater increase in ionization energy for the second electron.
4Step 4: Identifying the Greatest Energy Difference
Sodium (\( ext{Na}\)) has a configuration of 1s² 2s² 2p⁶ 3s¹. Removing the first electron leaves it with a stable, filled, 2s² 2p⁶ configuration. However, removing the second electron would mean breaking into this stable configuration, resulting in a large increase in ionization energy between the first and second ionization.
5Step 5: Conclusion
Based on electronic configuration analysis, sodium (\( ext{Na}\)) is expected to have the greatest difference between the first and second ionization energies among the given elements as it reaches a noble gas configuration with the removal of the first electron.
Key Concepts
First Ionization EnergySecond Ionization EnergyElectronic ConfigurationStable Configuration
First Ionization Energy
The first ionization energy is the energy needed to remove the first electron from an atom. Imagine trying to pull a basketball out from a tight rack. The first ball might come out easily if the grip isn't too strong.
In the case of atoms, this energy depends on the attraction between the electrons and the nucleus. The stronger the attraction, the more energy is required.
In the case of atoms, this energy depends on the attraction between the electrons and the nucleus. The stronger the attraction, the more energy is required.
- This process turns a neutral atom into a positively charged ion.
- For sodium ( Na ), the first ionization energy involves removing the 3s¹ electron, leaving behind a stable, noble gas configuration, 1s² 2s² 2p⁶.
Second Ionization Energy
The second ionization energy is the energy required to remove another electron from an already positively charged ion. Continuing with our basketball analogy, the second ball is often wedged tighter, making it harder to remove.
- Typically, the second ionization energy is higher than the first because you're removing an electron from an already positive ion, which means it feels an even greater pull toward the nucleus.
- For sodium, after the 3s¹ electron is removed, what remains is a stable, complete 2s² 2p⁶ shell. Breaking into this shell requires much more energy, hence a much higher second ionization energy.
Electronic Configuration
Electronic configuration refers to the arrangement of electrons in an atom's orbitals. Think of it as the blueprint outlining where each electron lives within the atom's house.
- It's written in a notation combining energy levels, sublevels, and the number of electrons, like 1s² 2s² 2p⁶ for sodium's ion.
- Understanding electronic configuration helps predict chemical behavior, including ionization energies.
- A stable configuration, like sodium's 1s² 2s² 2p⁶ after first ionization, is why its second ionization energy jumps significantly.
Stable Configuration
A stable configuration occurs when electrons fill an energy level, making the atom energetically favored. Consider a perfectly balanced tower of blocks; moving just one might destabilize the entire structure.
- In atomic terms, a filled or half-filled shell represents stability.
- This stability explains why atoms like sodium show a massive increase in ionization energy upon removing a second electron because you're disturbing a completed 2p level.
Other exercises in this chapter
Problem 87
Which of these groups of elements is arranged correctly in order of increasing ionization energy? (a) \(\mathrm{C}\). \(\mathrm{Si}, \mathrm{Li}, \mathrm{Ne}\)
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Rank these ionization energies (IE) from the smallest to the largest value. Briefly explain your answer. (a) First \(I E\) of \(B e\) (b) First IE of \(\mathrm{
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Compare the clemcnts \(\mathrm{B}, \mathrm{Al}, \mathrm{C}, \mathrm{Si}\). (a) Which has the most metallic character? (b) Which has the largest atomic radius? (
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Compare the elements \(\mathrm{I} \mathrm{i}, \mathrm{K}, \mathrm{C}, \mathrm{N}\). (a) Which has the largest atomic radius? (b) Arrange the elements in order o
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