Problem 89
Question
Perform the indicated operations, and simplify. \((2 x+y-3)(2 x+y+3)\)
Step-by-Step Solution
Verified Answer
The simplified form is \( 4x^2 + 4xy + y^2 - 9 \).
1Step 1: Apply the Difference of Squares Formula
Recognize the expression \( (2x + y - 3)(2x + y + 3) \) as a difference of squares, which takes the form \( (a - b)(a + b) = a^2 - b^2 \). In this case, let:- \( a = 2x + y \) - \( b = 3 \). So, the operation becomes:\( ((2x + y)^2 - 3^2) \).
2Step 2: Square the Binomial
Square the binomial \( (2x + y) \), which involves expanding \( (2x + y)^2 \).Use the formula \( (a + b)^2 = a^2 + 2ab + b^2 \):\[ (2x + y)^2 = (2x)^2 + 2(2x)(y) + y^2 = 4x^2 + 4xy + y^2 \].
3Step 3: Square the Constant
Calculate the square of the constant:\\[ 3^2 = 9 \].
4Step 4: Combine the Results
Substitute the squared terms back into the difference of squares equation:\[ (2x + y)^2 - 3^2 = 4x^2 + 4xy + y^2 - 9 \].
5Step 5: Simplify the Result
Check the expression \( 4x^2 + 4xy + y^2 - 9 \) for any like terms, which there aren't any.The simplified form of the expression is:\( 4x^2 + 4xy + y^2 - 9 \).
Key Concepts
Binomial ExpansionAlgebraic SimplificationPolynomial Expressions
Binomial Expansion
The process of expanding a binomial is commonly used in algebra to break down expressions of the form \((a + b)^2\). The goal is to rewrite it as a sum of terms. In our original exercise, we had to expand \((2x + y)^2\). Expanding this correctly requires remembering the formula:
- \((a + b)^2 = a^2 + 2ab + b^2\)
- \((2x + y)^2 = (2x)^2 + 2(2x)(y) + y^2\)
- \((2x)^2 = 4x^2\)
- \(2(2x)(y) = 4xy\)
- \(y^2 = y^2\)
Algebraic Simplification
Simplifying algebraic expressions is about reducing them to their simplest form while maintaining their original value. In the original exercise, we used one type of simplification called the difference of squares, followed by combining like terms. First, we acknowledge the presence of a difference of squares:
- This was seen in \((2x + y - 3)(2x + y + 3)\) in the form \((a-b)(a+b) = a^2 - b^2\).
- \((2x + y)^2 - 3^2\)
- \((2x+y)^2 = 4x^2 + 4xy + y^2\)
- \(3^2 = 9\)
- The operation became \(4x^2 + 4xy + y^2 - 9\).
Polynomial Expressions
Polynomial expressions consist of variables, coefficients, and exponents all combined by addition or subtraction. Consider our example expression of the form \(4x^2 + 4xy + y^2 - 9\), which is a polynomial:
They can represent real-world phenomena or theoretical constructs, making their simplification and manipulation essential skills. Identifying terms as mentioned above helps decipher and manage these expressions effectively in operations such as addition, subtraction, multiplication, and division.
- Each term involves powers of variables. \(4x^2\) and \(y^2\) are quadratic terms.
- \(4xy\) represents a mixed or cross term involving both \(x\) and \(y\).
- The \(-9\) is a constant term, simply a number without any variable attached.
They can represent real-world phenomena or theoretical constructs, making their simplification and manipulation essential skills. Identifying terms as mentioned above helps decipher and manage these expressions effectively in operations such as addition, subtraction, multiplication, and division.
Other exercises in this chapter
Problem 89
Rationalize the denominator. $$ \frac{1}{2-\sqrt{3}} $$
View solution Problem 89
Factor the expression completely. Begin by factoring out the lowest power of each common factor. $$ 2 x^{1 / 3}(x-2)^{2 / 3}-5 x^{4 / 3}(x-2)^{-1 / 3} $$
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Rationalize the denominator. $$ \frac{2}{3-\sqrt{5}} $$
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Factor the expression completely. Begin by factoring out the lowest power of each common factor. $$ 3 x^{-1 / 2}\left(x^{2}+1\right)^{5 / 4}-x^{3 / 2}\left(x^{2
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