Problem 89
Question
Let \(z_{1}\) and \(z_{2}\) be two complex numbers such that \(\frac{z_{1}}{z_{2}}+\frac{z_{2}}{z_{1}}=1\), then (A) \(z_{1}, z_{2}\) are collinear (B) \(z_{1}, z_{2}\) and the origin from a right angled triangle (C) \(z_{1}, z_{2}\) and the origin form an equilateral triangle (D) None of these
Step-by-Step Solution
Verified Answer
(C) \(z_{1}, z_{2}\), and the origin form an equilateral triangle.
1Step 1: Understand the Problem
We need to determine the geometric relationship between the complex numbers \(z_1\), \(z_2\), and the origin given the equation \(\frac{z_1}{z_2}+\frac{z_2}{z_1}=1\).
2Step 2: Simplify the Equation
Start by multiplying both sides by \(z_1 z_2\) to eliminate the fractions:\[\frac{z_1}{z_2} + \frac{z_2}{z_1} = 1 \Rightarrow z_1^2 + z_2^2 = z_1 z_2.\]
3Step 3: Analyze the Equation
Reorganize the simplified equation: \[z_1^2 - z_1 z_2 + z_2^2 = 0.\] This resembles the form of the cosine rule for a triangle.
4Step 4: Identify Geometric Implications
The equation \(z_1^2 - z_1 z_2 + z_2^2 = 0\) can be interpreted as a condition for roots of unity or an equilateral triangle. This implies that \(z_1\), \(z_2\), and the origin form an equilateral triangle.
5Step 5: Conclusion
With the derived equation resembling that of the roots of unity, \(z_1\) and \(z_2\), and the origin form an equilateral triangle. So the correct choice is (C).
Key Concepts
Geometric InterpretationEquilateral TriangleRoots of Unity
Geometric Interpretation
To understand the nature of complex numbers, it is often helpful to visualize them as points on a plane. This is the crux of their geometric interpretation. Each complex number, such as \( z = a + bi \), corresponds to a point \((a, b)\) in the complex plane:
When complex numbers are part of an equation, such as \( \frac{z_1}{z_2} + \frac{z_2}{z_1} = 1 \), their positions relative to each other and the origin often have direct implications for their geometric arrangement. By solving the equation, we gain insights into this arrangement, which in our example, suggests a symmetrical shape like an equilateral triangle.
- The real part \(a\) corresponds to the horizontal axis.
- The imaginary part \(b\) corresponds to the vertical axis.
When complex numbers are part of an equation, such as \( \frac{z_1}{z_2} + \frac{z_2}{z_1} = 1 \), their positions relative to each other and the origin often have direct implications for their geometric arrangement. By solving the equation, we gain insights into this arrangement, which in our example, suggests a symmetrical shape like an equilateral triangle.
Equilateral Triangle
The solution of the equation \( z_1^2 - z_1 z_2 + z_2^2 = 0 \) points to the formation of an equilateral triangle between the complex numbers and the origin. An equilateral triangle in the complex plane is characterized by all sides being equal in length and all angles measuring \(60^\circ\).
To visualize it easily:
To visualize it easily:
- Consider \( z_1 \), \( z_2 \), and the origin as vertices of the triangle.
- The equal magnitude of the segments formed by \( z_1 - z_2 \), \( z_1 - 0 \), and \( z_2 - 0 \) confirms the equal sides property.
- For these vectors forming such an angle, the scalar product will align with cosine rule derivations found in equal energetic setups.
Roots of Unity
Roots of unity are a fundamental concept when it comes to complex numbers and their symmetric arrangements. Simply put, the \( n \)-th roots of unity are complex numbers which satisfy the equation \( z^n = 1 \).
They are evenly distributed on the unit circle, which is a circle with radius 1 centered at the origin of the complex plane. For case \( n=3 \) (like forming an equilateral triangle with origin):
They are evenly distributed on the unit circle, which is a circle with radius 1 centered at the origin of the complex plane. For case \( n=3 \) (like forming an equilateral triangle with origin):
- The 3rd roots of unity are \( 1, \omega, \omega^2 \) where \( \omega = e^{i \frac{2\pi}{3}} \).
- These points form vertices of an equilateral triangle on the plane.
- The symmetry and equal spacing attribute to equilateral triangle formation when seen from the origin.
Other exercises in this chapter
Problem 87
If for the complex numbers \(z_{1}\) and \(z_{2},\left|z_{1}+z_{2}\right|=\left|z_{1}-z_{2}\right|\), then \(\operatorname{amp} z_{1} \sim \operatorname{amp} z_
View solution Problem 88
The locus of the complex number \(z\) in an argand plane satisfying the inequality \(\log _{1 / 2}\left(\frac{|z-1|+4}{3|z-1|-2}\right)>1\left(\right.\) where \
View solution Problem 91
If \(a, b, c, p, q, r\) are three non-zero complex numbers such that \(\frac{p}{a}+\frac{q}{b}+\frac{r}{c}=1+i\) and \(\frac{a}{p}+\frac{b}{q}+\frac{c}{r}=0\),
View solution Problem 92
If \(z_{1}, z_{2}\) are two complex numbers such that \(\left|\frac{z_{1}-z_{2}}{z_{1}+z_{2}}\right|=1\) and \(t z_{1}=k z_{2}\) where \(k \in R\), then the ang
View solution