Problem 89
Question
In each of Exercises \(89-92,\) investigate the given limit numerically and graphically. \(\lim _{x \rightarrow 0}(1-\cos (x)) / \sin (x)^{2}\)
Step-by-Step Solution
Verified Answer
The limit is \( \frac{1}{2} \).
1Step 1: Understand the limit expression
We are asked to find the limit \( \lim_{x \to 0} \frac{1 - \cos(x)}{\sin^2(x)} \). The expression involves trigonometric functions \( \cos(x) \) and \( \sin(x) \), and we need to evaluate this as \( x \) approaches 0.
2Step 2: Substitute small values of x
To investigate this numerically, substitute small positive and negative values close to zero into the expression \( \frac{1 - \cos(x)}{\sin^2(x)} \), such as \( x = 0.1, 0.01, 0.001 \), etc., and observe the trend as \( x \) approaches 0.
3Step 3: Apply trigonometric limits
Use known limits: \( \lim_{x \to 0} \frac{\sin(x)}{x} = 1 \) and \( \lim_{x \to 0} \frac{1 - \cos(x)}{x^2} = \frac{1}{2} \). Rewriting the original expression, we have \( \frac{1 - \cos(x)}{\sin^2(x)} = \frac{\frac{1 - \cos(x)}{x^2}}{\left(\frac{\sin(x)}{x}\right)^2} \) and substituting these limits gives \( \frac{\frac{1}{2}}{1} = \frac{1}{2} \).
4Step 4: Graphical approach
Graph the function \( y = \frac{1 - \cos(x)}{\sin^2(x)} \) near \( x = 0 \). Observe the behavior of the graph as \( x \) approaches zero from both the left and right.
Key Concepts
Numerical InvestigationGraphical ApproachTrigonometric LimitsTrigonometric Functions
Numerical Investigation
Exploring the limit of a function numerically means substituting specific numbers close to the point of interest into the function. In this case, our focus is on \( \lim_{x \to 0} \frac{1 - \cos(x)}{\sin^2(x)} \). We take small values of \( x \), like 0.1, 0.01, and 0.001, and plug them into \( \frac{1 - \cos(x)}{\sin^2(x)} \).
By doing this, we take note of how the resulting output changes as \( x \) nears zero.
By doing this, we take note of how the resulting output changes as \( x \) nears zero.
- For \( x = 0.1 \), calculate \( \frac{1 - \cos(0.1)}{\sin^2(0.1)} \) and observe the result.
- Similarly, perform the calculation for \( x = 0.01 \) and \( x = 0.001 \).
Graphical Approach
Drawing graphs can make abstract concepts more tangible, especially when dealing with limits. For the expression \( y = \frac{1 - \cos(x)}{\sin^2(x)} \), graphing can visually show what happens as \( x \) approaches zero.
When you plot this function on a graph, focus on the interval close to zero, such as between -0.1 and 0.1.
When you plot this function on a graph, focus on the interval close to zero, such as between -0.1 and 0.1.
- Observe how the graph behaves near zero.
- Does the function seem to blow up, stabilize, or approach a horizontal line?
Trigonometric Limits
To mathematically determine the limit \( \lim_{x \to 0} \frac{1 - \cos(x)}{\sin^2(x)} \), we use known trigonometric limits.
First, remember two important limits:
First, remember two important limits:
- \( \lim_{x \to 0} \frac{\sin(x)}{x} = 1 \)
- \( \lim_{x \to 0} \frac{1 - \cos(x)}{x^2} = \frac{1}{2} \)
Trigonometric Functions
The trigonometric functions sine and cosine play a key role in understanding many mathematical concepts, including limits. Here, they are critical in determining \( \lim_{x \to 0} \frac{1 - \cos(x)}{\sin^2(x)} \).
Both \( \sin(x) \) and \( \cos(x) \) are fundamental periodic functions, featuring prominently in the principles of calculus and analytical geometry.
Both \( \sin(x) \) and \( \cos(x) \) are fundamental periodic functions, featuring prominently in the principles of calculus and analytical geometry.
- \( \sin(x) \) describes the ratio of the opposite side to the hypotenuse in a right triangle.
- \( \cos(x) \) describes the ratio of the adjacent side to the hypotenuse.
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Problem 88
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